delete operator in C++

Introduction

The delete operator frees memory that was previously allocated with new. It helps keep your program from using too much memory.

When you create an object using <code>new</code> and want to remove it after use.

When you want to avoid memory leaks by cleaning up unused memory.

When you allocate an array with <code>new[]</code> and want to free it.

When managing resources manually in simple programs without smart pointers.

Syntax

C++

delete pointer;
delete[] pointer_to_array;

Use delete for single objects allocated with new.

Use delete[] for arrays allocated with new[].

Examples

Deletes a single integer allocated on the heap.

C++

int* p = new int;
// use p
delete p;

Deletes an array of 5 integers allocated on the heap.

C++

int* arr = new int[5];
// use arr
delete[] arr;

Sample Program

This program creates a single integer and an array on the heap, prints their values, and then frees the memory using delete and delete[].

C++

#include <iostream>

int main() {
    int* number = new int(42);
    std::cout << "Number: " << *number << std::endl;
    delete number;  // free memory

    int* array = new int[3]{1, 2, 3};
    std::cout << "Array elements: ";
    for (int i = 0; i < 3; ++i) {
        std::cout << array[i] << " ";
    }
    std::cout << std::endl;
    delete[] array;  // free array memory

    return 0;
}

Important Notes

Always match new with delete and new[] with delete[] to avoid undefined behavior.

After deleting, set pointers to nullptr to avoid dangling pointers.

Using delete on memory not allocated with new causes errors.

Summary

The delete operator frees memory allocated with new.

Use delete for single objects and delete[] for arrays.

Proper use prevents memory leaks and keeps programs efficient.

Practice

1. What is the main purpose of the delete operator in C++?

easy

A. To allocate new memory

B. To free memory allocated with new

C. To copy objects

D. To declare variables

Solution

1. Step 1: Understand memory allocation

   The new operator allocates memory dynamically on the heap.

2. Step 2: Role of delete

   The delete operator frees that allocated memory to avoid leaks.

3. Final Answer:

   To free memory allocated with new -> Option B

4. Quick Check:

   delete frees memory [OK]

Hint: Remember: new allocates, delete frees memory [OK]

Common Mistakes:

• Confusing delete with new
• Using delete to copy objects
• Thinking delete declares variables

2. Which of the following is the correct syntax to delete a dynamically allocated array arr?

easy

A. delete arr;

B. delete array arr;

C. delete arr[];

D. delete[] arr;

Solution

1. Step 1: Identify array deletion syntax

   For arrays allocated with new[], use delete[] to free all elements properly.

2. Step 2: Match correct syntax

   delete[] arr; correctly deletes the entire array.

3. Final Answer:

   delete[] arr; -> Option D

4. Quick Check:

   Use delete[] for arrays [OK]

Hint: Use delete[] for arrays, delete for single objects [OK]

Common Mistakes:

• Using delete instead of delete[] for arrays
• Placing brackets after variable name incorrectly
• Writing delete array arr (invalid syntax)

3. What will be the output of the following code?

int* p = new int(10);
std::cout << *p << std::endl;
delete p;
// std::cout << *p << std::endl; // Uncommenting this line causes what?

medium

A. 10 and then 10 again

B. Compilation error at delete

C. 10 and then undefined behavior

D. Runtime error at new

Solution

1. Step 1: Analyze output before delete

   The pointer p points to an int with value 10, so *p prints 10.

2. Step 2: Effect of delete and accessing pointer

   After delete p;, the memory is freed. Accessing *p after delete causes undefined behavior (may crash or print garbage).

3. Final Answer:

   10 and then undefined behavior -> Option C

4. Quick Check:

   Access after delete = undefined behavior [OK]

Hint: Don't use pointer after delete; it's unsafe [OK]

Common Mistakes:

• Assuming deleted pointer still holds valid data
• Expecting compilation error on delete
• Ignoring undefined behavior risks

4. Identify the error in this code snippet:

int* arr = new int[5];
delete arr;

medium

A. Should use delete[] instead of delete

B. Should use delete without brackets

C. No error, code is correct

D. Should not delete dynamically allocated arrays

Solution

1. Step 1: Check allocation type

   arr is allocated with new int[5], which creates an array.

2. Step 2: Correct deletion method

   Arrays must be deleted with delete[] arr; to properly free all elements.

3. Final Answer:

   Should use delete[] instead of delete -> Option A

4. Quick Check:

   Array delete needs delete[] [OK]

Hint: Match new[] with delete[] always [OK]

Common Mistakes:

• Using delete for arrays causes undefined behavior
• Thinking delete works for both single and arrays
• Ignoring memory leaks from wrong delete

5. Consider this code:

int** matrix = new int*[3];
for (int i = 0; i < 3; ++i) {
    matrix[i] = new int[4];
}
// Code to delete matrix properly?

Which is the correct way to delete all allocated memory?

hard

A. for (int i = 0; i < 3; ++i) delete[] matrix[i]; delete[] matrix;

B. for (int i = 0; i < 3; ++i) delete matrix[i]; delete[] matrix;

C. delete[] matrix; delete[] matrix[0];

D. delete matrix; delete matrix[0];

Solution

1. Step 1: Understand allocation

   Each matrix[i] is an array allocated with new int[4], so must be deleted with delete[].

2. Step 2: Delete outer array

   The matrix pointer itself is an array of pointers allocated with new int*[3], so delete with delete[] matrix;.

3. Final Answer:

   for (int i = 0; i < 3; ++i) delete[] matrix[i]; delete[] matrix; -> Option A

4. Quick Check:

   Match new[] with delete[] at all levels [OK]

Hint: Delete inner arrays with delete[], then outer with delete[] [OK]

Common Mistakes:

• Using delete instead of delete[] for inner arrays
• Deleting outer array with delete instead of delete[]
• Forgetting to delete inner arrays causing leaks