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Cprogramming~10 mins

For loop in C - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to print numbers from 0 to 4.

C
for (int i = 0; i [1] 5; i++) {
    printf("%d\n", i);
}
Drag options to blanks, or click blank then click option'
A<=
B>=
C>
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using >= or > will cause the loop to not run as expected.
Using <= will print an extra number.
2fill in blank
medium

Complete the code to sum numbers from 1 to 5 using a for loop.

C
int sum = 0;
for (int i = 1; i [1] 6; i++) {
    sum += i;
}
printf("%d\n", sum);
Drag options to blanks, or click blank then click option'
A>=
B<=
C<
D>
Attempts:
3 left
💡 Hint
Common Mistakes
Using <= 5 instead of < 6 is correct but not in the options.
Using > or >= will cause the loop to not run.
3fill in blank
hard

Fix the error in the for loop condition to print even numbers from 2 to 10.

C
for (int i = 2; i [1] 10; i += 2) {
    printf("%d\n", i);
}
Drag options to blanks, or click blank then click option'
A<=
B>=
C<
D>
Attempts:
3 left
💡 Hint
Common Mistakes
Using < 10 will exclude 10 from the output.
Using > or >= will cause the loop to not run.
4fill in blank
hard

Fill both blanks to create a for loop that prints numbers from 10 down to 1.

C
for (int i = [1]; i [2] 1; i--) {
    printf("%d\n", i);
}
Drag options to blanks, or click blank then click option'
A10
B>
C>=
D1
Attempts:
3 left
💡 Hint
Common Mistakes
Starting at 1 will not print numbers down from 10.
Using > excludes 1 from the output.
5fill in blank
hard

Fill all three blanks to create a for loop that prints squares of numbers from 1 to 5.

C
for (int [1] = 1; [2] [3] 5; [1]++) {
    printf("%d\n", [1] * [1]);
}
Drag options to blanks, or click blank then click option'
Ai
C<=
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using different variable names in the loop causes errors.
Using < instead of <= excludes 5.

Practice

(1/5)
1. What does a for loop in C primarily do?
easy
A. Repeats a block of code a fixed number of times
B. Defines a new variable
C. Stops the program execution
D. Declares a function

Solution

  1. Step 1: Understand the purpose of a for loop

    A for loop is designed to repeat a block of code multiple times based on a condition.
  2. Step 2: Identify the correct description

    Among the options, only repeating code a fixed number of times matches the for loop's purpose.
  3. Final Answer:

    Repeats a block of code a fixed number of times -> Option A
  4. Quick Check:

    For loop = repeat code [OK]
Hint: For loops repeat code a set number of times [OK]
Common Mistakes:
  • Confusing for loop with variable declaration
  • Thinking for loop stops program
  • Mixing for loop with function declaration
2. Which of the following is the correct syntax for a for loop in C?
easy
A. for i = 0 to 5 { }
B. for (int i = 0; i++ < 5;) { }
C. for (i < 5; i = 0; i++) { }
D. for (int i = 0; i < 5; i++) { }

Solution

  1. Step 1: Review standard for loop syntax in C

    The correct syntax is: for (initialization; condition; update) { body }
  2. Step 2: Check each option

    for (int i = 0; i < 5; i++) { } matches the correct syntax with initialization, condition, and update in proper order.
  3. Final Answer:

    for (int i = 0; i < 5; i++) { } -> Option D
  4. Quick Check:

    Syntax = for(init; cond; update) [OK]
Hint: For loop syntax: for(init; condition; update) [OK]
Common Mistakes:
  • Using 'for i = 0 to 5' which is not C syntax
  • Swapping condition and initialization
  • Missing semicolons inside for parentheses
3. What is the output of this code?
for(int i = 1; i <= 3; i++) {
    printf("%d ", i);
}
medium
A. 3 2 1
B. 0 1 2 3
C. 1 2 3
D. 1 2 3 4

Solution

  1. Step 1: Analyze the loop range

    The loop starts at i=1 and runs while i is less than or equal to 3, incrementing i by 1 each time.
  2. Step 2: Determine printed values

    It prints i each time: 1, then 2, then 3, then stops.
  3. Final Answer:

    1 2 3 -> Option C
  4. Quick Check:

    Loop prints 1 to 3 [OK]
Hint: Check loop start, end, and increments carefully [OK]
Common Mistakes:
  • Starting loop at 0 instead of 1
  • Including an extra number beyond 3
  • Printing in reverse order
4. Identify the error in this for loop:
for(int i = 0; i < 5; i)
    printf("%d ", i);
medium
A. Missing semicolon after printf statement
B. Missing increment operator in for loop update
C. Incorrect loop condition syntax
D. Variable i not declared

Solution

  1. Step 1: Examine the for loop update part

    The update section is 'i' without increment operator, so i never changes.
  2. Step 2: Understand the effect of missing increment

    Without 'i++' or similar, the loop runs infinitely or behaves incorrectly.
  3. Final Answer:

    Missing increment operator in for loop update -> Option B
  4. Quick Check:

    Update must change loop variable [OK]
Hint: For loop update must change variable (e.g., i++) [OK]
Common Mistakes:
  • Forgetting to increment loop variable
  • Confusing semicolon placement
  • Assuming variable auto-increments
5. How can you use a for loop to print only even numbers from 2 to 10 inclusive in C?
hard
A. for(int i = 2; i <= 10; i += 2) { printf("%d ", i); }
B. for(int i = 0; i <= 10; i++) { if(i % 2 == 0) printf("%d ", i); }
C. for(int i = 2; i < 10; i++) { if(i % 2 == 0) printf("%d ", i); }
D. for(int i = 0; i <= 10; i += 3) { printf("%d ", i); }

Solution

  1. Step 1: Understand the goal

    We want to print even numbers from 2 to 10 inclusive.
  2. Step 2: Check each option

    for(int i = 2; i <= 10; i += 2) { printf("%d ", i); } starts at 2 and increments by 2, printing 2,4,6,8,10 exactly.
  3. Final Answer:

    for(int i = 2; i <= 10; i += 2) { printf("%d ", i); } -> Option A
  4. Quick Check:

    Increment by 2 prints evens directly [OK]
Hint: Increment by 2 to print evens directly [OK]
Common Mistakes:
  • Using wrong increment step
  • Off-by-one errors in loop condition
  • Printing odd numbers by mistake
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