For loop in C - Mini Project: Build & Apply

Counting Even Numbers with a For Loop in C

📖 Scenario: You have a list of numbers representing daily sales counts in a small shop. You want to find out how many days had an even number of sales.

🎯 Goal: Build a C program that counts how many numbers in a given list are even using a for loop.

📋 What You'll Learn

Create an integer array called sales with the exact values: 12, 7, 9, 20, 15

Create an integer variable called count_even and set it to 0

Use a for loop with an integer variable i to iterate over the sales array

Inside the loop, use an if statement to check if the current number is even

Increase count_even by 1 for each even number found

Print the final value of count_even using printf

💡 Why This Matters

🌍 Real World

Counting specific types of data in a list is common in many real-world tasks, like analyzing sales, temperatures, or survey results.

💼 Career

Understanding loops and conditions is essential for programming jobs, as they help automate repetitive tasks and data analysis.

1

Create the sales data array

Create an integer array called sales with these exact values: 12, 7, 9, 20, 15.

C

// Your code here

Need a hint?

Use curly braces {} to list the numbers inside the array.

2

Create a counter variable

Create an integer variable called count_even and set it to 0.

C

int sales[] = {12, 7, 9, 20, 15};
// Your code here

Need a hint?

This variable will keep track of how many even numbers you find.

3

Use a for loop to count even numbers

Use a for loop with an integer variable i to iterate over the sales array. Inside the loop, use an if statement to check if sales[i] is even (divisible by 2). If it is even, increase count_even by 1.

C

int sales[] = {12, 7, 9, 20, 15};
int count_even = 0;
// Your code here

Need a hint?

Remember, use i < 5 because the array has 5 elements indexed 0 to 4.

4

Print the count of even numbers

Write a printf statement to print the value of count_even with the exact text: "Number of even sales days: %d\n".

C

int sales[] = {12, 7, 9, 20, 15};
int count_even = 0;
for (int i = 0; i < 5; i++) {
    if (sales[i] % 2 == 0) {
        count_even++;
    }
}
// Your code here

Need a hint?

Use printf with %d to show the number stored in count_even.