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Cprogramming~5 mins

For loop in C

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Introduction

A for loop helps you repeat a set of actions many times without writing the same code again and again.

When you want to count from 1 to 10 and do something each time.
When you need to process each item in a list one by one.
When you want to repeat a task a fixed number of times, like printing a message 5 times.
When you want to run a block of code while increasing or decreasing a number step by step.
Syntax
C
for (initialization; condition; update) {
    // code to repeat
}

initialization sets a starting point, like int i = 0;

condition is checked before each loop; if false, the loop stops.

Examples
This prints numbers 0 to 4, increasing i by 1 each time.
C
for (int i = 0; i < 5; i++) {
    printf("%d\n", i);
}
This counts down from 10 to 1, decreasing i by 1 each time.
C
for (int i = 10; i > 0; i--) {
    printf("%d\n", i);
}
This prints even numbers from 0 to 8 by adding 2 each time.
C
for (int i = 0; i < 10; i += 2) {
    printf("%d\n", i);
}
Sample Program

This program prints "Hello" followed by numbers 1 to 5, each on a new line.

C
#include <stdio.h>

int main() {
    for (int i = 1; i <= 5; i++) {
        printf("Hello %d\n", i);
    }
    return 0;
}
OutputSuccess
Important Notes

Remember the semicolons inside the for loop parentheses separate the parts.

If you forget to update the variable, the loop might run forever.

You can use any variable name, not just i.

Summary

A for loop repeats code a set number of times.

It has three parts: start, condition, and update.

Use it to count, repeat tasks, or process items step by step.

Practice

(1/5)
1. What does a for loop in C primarily do?
easy
A. Repeats a block of code a fixed number of times
B. Defines a new variable
C. Stops the program execution
D. Declares a function

Solution

  1. Step 1: Understand the purpose of a for loop

    A for loop is designed to repeat a block of code multiple times based on a condition.
  2. Step 2: Identify the correct description

    Among the options, only repeating code a fixed number of times matches the for loop's purpose.
  3. Final Answer:

    Repeats a block of code a fixed number of times -> Option A
  4. Quick Check:

    For loop = repeat code [OK]
Hint: For loops repeat code a set number of times [OK]
Common Mistakes:
  • Confusing for loop with variable declaration
  • Thinking for loop stops program
  • Mixing for loop with function declaration
2. Which of the following is the correct syntax for a for loop in C?
easy
A. for i = 0 to 5 { }
B. for (int i = 0; i++ < 5;) { }
C. for (i < 5; i = 0; i++) { }
D. for (int i = 0; i < 5; i++) { }

Solution

  1. Step 1: Review standard for loop syntax in C

    The correct syntax is: for (initialization; condition; update) { body }
  2. Step 2: Check each option

    for (int i = 0; i < 5; i++) { } matches the correct syntax with initialization, condition, and update in proper order.
  3. Final Answer:

    for (int i = 0; i < 5; i++) { } -> Option D
  4. Quick Check:

    Syntax = for(init; cond; update) [OK]
Hint: For loop syntax: for(init; condition; update) [OK]
Common Mistakes:
  • Using 'for i = 0 to 5' which is not C syntax
  • Swapping condition and initialization
  • Missing semicolons inside for parentheses
3. What is the output of this code?
for(int i = 1; i <= 3; i++) {
    printf("%d ", i);
}
medium
A. 3 2 1
B. 0 1 2 3
C. 1 2 3
D. 1 2 3 4

Solution

  1. Step 1: Analyze the loop range

    The loop starts at i=1 and runs while i is less than or equal to 3, incrementing i by 1 each time.
  2. Step 2: Determine printed values

    It prints i each time: 1, then 2, then 3, then stops.
  3. Final Answer:

    1 2 3 -> Option C
  4. Quick Check:

    Loop prints 1 to 3 [OK]
Hint: Check loop start, end, and increments carefully [OK]
Common Mistakes:
  • Starting loop at 0 instead of 1
  • Including an extra number beyond 3
  • Printing in reverse order
4. Identify the error in this for loop:
for(int i = 0; i < 5; i)
    printf("%d ", i);
medium
A. Missing semicolon after printf statement
B. Missing increment operator in for loop update
C. Incorrect loop condition syntax
D. Variable i not declared

Solution

  1. Step 1: Examine the for loop update part

    The update section is 'i' without increment operator, so i never changes.
  2. Step 2: Understand the effect of missing increment

    Without 'i++' or similar, the loop runs infinitely or behaves incorrectly.
  3. Final Answer:

    Missing increment operator in for loop update -> Option B
  4. Quick Check:

    Update must change loop variable [OK]
Hint: For loop update must change variable (e.g., i++) [OK]
Common Mistakes:
  • Forgetting to increment loop variable
  • Confusing semicolon placement
  • Assuming variable auto-increments
5. How can you use a for loop to print only even numbers from 2 to 10 inclusive in C?
hard
A. for(int i = 2; i <= 10; i += 2) { printf("%d ", i); }
B. for(int i = 0; i <= 10; i++) { if(i % 2 == 0) printf("%d ", i); }
C. for(int i = 2; i < 10; i++) { if(i % 2 == 0) printf("%d ", i); }
D. for(int i = 0; i <= 10; i += 3) { printf("%d ", i); }

Solution

  1. Step 1: Understand the goal

    We want to print even numbers from 2 to 10 inclusive.
  2. Step 2: Check each option

    for(int i = 2; i <= 10; i += 2) { printf("%d ", i); } starts at 2 and increments by 2, printing 2,4,6,8,10 exactly.
  3. Final Answer:

    for(int i = 2; i <= 10; i += 2) { printf("%d ", i); } -> Option A
  4. Quick Check:

    Increment by 2 prints evens directly [OK]
Hint: Increment by 2 to print evens directly [OK]
Common Mistakes:
  • Using wrong increment step
  • Off-by-one errors in loop condition
  • Printing odd numbers by mistake
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