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Cprogramming~5 mins

Writing first C program

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Introduction

We write a first C program to learn how to tell the computer what to do using simple instructions. It helps us understand the basics of programming.

When you want to print a message on the screen.
When you want to learn how to start programming in C.
When you want to check if your computer can run C programs.
When you want to understand how a simple program is structured.
Syntax
C
#include <stdio.h>

int main() {
    printf("Hello, world!\n");
    return 0;
}

#include <stdio.h> tells the program to use input/output functions like printf.

int main() is the starting point of the program.

Examples
This program prints a different greeting message.
C
#include <stdio.h>

int main() {
    printf("Hello, C learner!\n");
    return 0;
}
This program shows a welcome message to new programmers.
C
#include <stdio.h>

int main() {
    printf("Welcome to C programming!\n");
    return 0;
}
Sample Program

This program prints the message "Hello, world!" on the screen. It shows how to write a simple C program that runs and displays text.

C
#include <stdio.h>

int main() {
    printf("Hello, world!\n");
    return 0;
}
OutputSuccess
Important Notes

Always end your printf strings with \n to move to the next line.

The return 0; means the program finished successfully.

Use a semicolon ; at the end of each instruction.

Summary

A C program starts with int main() function.

Use printf to show messages on the screen.

End each statement with a semicolon ;.

Practice

(1/5)
1. What is the purpose of the int main() function in a C program?
easy
A. It prints messages to the screen.
B. It is the starting point where the program begins execution.
C. It declares variables for the program.
D. It ends the program immediately.

Solution

  1. Step 1: Understand the role of main()

    The main() function is where the program starts running in C.
  2. Step 2: Identify the correct purpose

    It is not for declaring variables or printing messages but for starting the program.
  3. Final Answer:

    It is the starting point where the program begins execution. -> Option B
  4. Quick Check:

    Program starts at main() [OK]
Hint: Remember: C programs always start at main() [OK]
Common Mistakes:
  • Thinking main() prints output
  • Confusing main() with variable declaration
  • Believing main() ends the program immediately
2. Which of the following is the correct syntax to print "Hello, World!" in C?
easy
A. printf("Hello, World!");
B. printf("Hello, World!")
C. print("Hello, World!");
D. echo("Hello, World!");

Solution

  1. Step 1: Identify the correct function for output

    In C, printf is used to print text to the screen.
  2. Step 2: Check syntax details

    Each statement must end with a semicolon ;. So printf("Hello, World!"); is correct.
  3. Final Answer:

    printf("Hello, World!"); -> Option A
  4. Quick Check:

    Use printf with semicolon [OK]
Hint: Always end printf with a semicolon [OK]
Common Mistakes:
  • Missing semicolon at the end
  • Using print instead of printf
  • Using echo which is not C syntax
3. What will be the output of the following C program?
#include 
int main() {
    printf("Welcome to C programming!\n");
    return 0;
}
medium
A. No output
B. Welcome to C programming!\n
C. Syntax Error
D. Welcome to C programming!

Solution

  1. Step 1: Understand the printf statement

    The string inside printf includes \n which means new line after printing.
  2. Step 2: Predict the output

    The program prints "Welcome to C programming!" followed by a new line.
  3. Final Answer:

    Welcome to C programming! -> Option D
  4. Quick Check:

    \n creates new line, output is plain text [OK]
Hint: \n means new line, not literal text [OK]
Common Mistakes:
  • Thinking \n prints as text
  • Expecting syntax error due to \n
  • Ignoring the return statement effect
4. Identify the error in the following C program:
#include 
int main() {
    printf("Hello World")
    return 0;
}
medium
A. Incorrect header file included
B. Missing return type for main
C. Missing semicolon after printf statement
D. Missing main function

Solution

  1. Step 1: Check each statement for syntax

    The printf statement is missing a semicolon at the end.
  2. Step 2: Verify other parts

    The main function has correct return type and header file is correct.
  3. Final Answer:

    Missing semicolon after printf statement -> Option C
  4. Quick Check:

    Every statement ends with ; [OK]
Hint: Look for missing semicolons after statements [OK]
Common Mistakes:
  • Ignoring missing semicolon errors
  • Thinking return type is missing
  • Assuming wrong header file causes error
5. You want to write a C program that prints two lines: "Hello!" and "Welcome to C." Which code snippet correctly does this?
hard
A. #include int main() { printf("Hello!\n"); printf("Welcome to C.\n"); return 0; }
B. #include int main() { printf("Hello!Welcome to C.\n"); return 0; }
C. #include int main() { printf("Hello!"); printf("Welcome to C.\n"); return 0; }
D. #include int main() { printf("Hello!"); printf("Welcome to C."); return 0; }

Solution

  1. Step 1: Understand how to print two lines

    Each line should end with a newline character \n to move to the next line.
  2. Step 2: Check each option for correct newlines

    #include int main() { printf("Hello!\n"); printf("Welcome to C.\n"); return 0; } prints "Hello!" with \n and "Welcome to C." with \n, so two lines appear.
  3. Final Answer:

    Two printf statements, each ending with \n -> Option A
  4. Quick Check:

    Use \n at end of each line for separate lines [OK]
Hint: Use \n after each line to print on new lines [OK]
Common Mistakes:
  • Missing \n causing lines to join
  • Putting \n only on first line
  • Not returning 0 at end of main
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard