Continue statement - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to skip the current loop iteration when i equals 3.

C

for(int i = 0; i < 5; i++) {
    if(i == [1]) {
        continue;
    }
    printf("%d ", i);
}

Drag options to blanks, or click blank then click option'

A3

B5

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using a value other than 3 in the if condition.

Forgetting to use continue inside the if block.

The continue statement skips the rest of the loop body when i is 3, so 3 is not printed.

2fill in blank

medium

Complete the code to skip printing even numbers using continue.

C

for(int i = 1; i <= 5; i++) {
    if(i % [1] == 0) {
        continue;
    }
    printf("%d ", i);
}

Drag options to blanks, or click blank then click option'

A2

B3

C5

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong divisor in the modulus operation.

Not using continue to skip the iteration.

The condition i % 2 == 0 checks if i is even. If true, continue skips printing that number.

3fill in blank

hard

Fix the error in the code to correctly skip printing negative numbers.

C

int numbers[] = {1, -2, 3, -4, 5};
for(int i = 0; i < 5; i++) {
    if(numbers[i] [1] 0) {
        continue;
    }
    printf("%d ", numbers[i]);
}

Drag options to blanks, or click blank then click option'

A!=

B>

C<

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < in the condition.

Using == or != which do not check negativity.

The condition numbers[i] < 0 checks for negative numbers. When true, continue skips printing them.

4fill in blank

hard

Fill both blanks to skip printing numbers divisible by 3 or less than 0.

C

int arr[] = {3, -1, 4, 6, -5};
for(int i = 0; i < 5; i++) {
    if(arr[i] [1] 0 || arr[i] % [2] == 0) {
        continue;
    }
    printf("%d ", arr[i]);
}

Drag options to blanks, or click blank then click option'

A<

B>

C3

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < for negative check.

Using wrong divisor in modulus operation.

The condition skips numbers less than 0 and those divisible by 3.

5fill in blank

hard

Fill all three blanks to skip printing numbers that are negative, divisible by 2, or equal to 7.

C

int nums[] = {7, -2, 4, 9, -5};
for(int i = 0; i < 5; i++) {
    if(nums[i] [1] 0 || nums[i] % [2] == 0 || nums[i] [3] 7) {
        continue;
    }
    printf("%d ", nums[i]);
}

Drag options to blanks, or click blank then click option'

A<

B2

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < for negative check.

Using wrong divisor or operator for equality check.

The condition skips numbers less than 0, divisible by 2, or equal to 7.

Practice

1. What does the continue statement do inside a loop in C?

easy

A. Skips the rest of the current loop iteration and moves to the next iteration

B. Stops the entire loop immediately

C. Exits the current function

D. Restarts the program from the beginning

Solution

1. Step 1: Understand the role of continue

   The continue statement does not stop the loop but skips the remaining code in the current iteration.

2. Step 2: Effect on loop execution

   After continue, the loop immediately proceeds to the next iteration, ignoring any code below it in the current cycle.

3. Final Answer:

   Skips the rest of the current loop iteration and moves to the next iteration -> Option A

4. Quick Check:

   continue skips current iteration [OK]

Hint: Remember: continue skips current loop step, not whole loop [OK]

Common Mistakes:

• Confusing continue with break
• Thinking continue exits the function
• Assuming continue restarts the program

2. Which of the following is the correct syntax to use continue inside a for loop in C?

easy

A. continue;

B. continue()

C. continue{}

D. continue[]

Solution

1. Step 1: Recall correct statement syntax

   In C, continue is a statement and must end with a semicolon.

2. Step 2: Identify valid syntax

   Only continue; is valid; parentheses, braces, or brackets are incorrect.

3. Final Answer:

   continue; -> Option A

4. Quick Check:

   Statement ends with semicolon [OK]

Hint: Statements end with semicolon; continue is no exception [OK]

Common Mistakes:

• Adding parentheses after continue
• Using braces or brackets with continue
• Omitting the semicolon

3. What is the output of the following C code?

for (int i = 1; i <= 5; i++) {
    if (i == 3) continue;
    printf("%d ", i);
}

medium

A. 1 2 3 4 5

B. 1 2 4 5

C. 1 2 3 4

D. 2 3 4 5

Solution

1. Step 1: Analyze loop iterations

   The loop runs i from 1 to 5. When i equals 3, the continue statement skips printing.

2. Step 2: Determine printed values

   Values 1, 2, 4, and 5 are printed with spaces. The number 3 is skipped.

3. Final Answer:

   1 2 4 5 -> Option B

4. Quick Check:

   continue skips printing 3 [OK]

Hint: Skip printing when continue triggers, others print normally [OK]

Common Mistakes:

• Including the skipped number in output
• Confusing continue with break
• Ignoring the loop condition

4. Identify the error in this code snippet using continue:

int i = 0;
while (i < 5) {
    if (i == 2)
        continue;
    printf("%d ", i);
    i++;
}

medium

A. Syntax error: continue cannot be used in while loops

B. The printf statement is unreachable

C. The loop will run infinitely because 'i' is not incremented when i == 2

D. The variable 'i' is not declared properly

Solution

1. Step 1: Understand loop flow with continue

   When i equals 2, continue skips the rest of the loop body, so i++ is not executed.

2. Step 2: Consequence of skipping i++

   Since i is not incremented at i == 2, the loop condition remains true forever, causing an infinite loop.

3. Final Answer:

   The loop will run infinitely because 'i' is not incremented when i == 2 -> Option C

4. Quick Check:

   continue skips i++ causing infinite loop [OK]

Hint: Always increment loop variable before continue to avoid infinite loops [OK]

Common Mistakes:

• Thinking continue causes syntax error
• Assuming printf is unreachable
• Ignoring loop variable increment

5. How can you modify this code to print only odd numbers from 1 to 10 using continue?

for (int i = 1; i <= 10; i++) {
    printf("%d ", i);
}

hard

A. Add if (i == 2) continue; before printf

B. Add if (i % 2 != 0) continue; before printf

C. Replace printf with if (i % 2 != 0) printf("%d ", i);

D. Add if (i % 2 == 0) continue; before printf

Solution

1. Step 1: Identify condition to skip even numbers

   Even numbers satisfy i % 2 == 0. Using continue here skips printing even numbers.

2. Step 2: Place continue before printf

   Adding if (i % 2 == 0) continue; before printf skips printing even numbers, so only odd numbers print.

3. Final Answer:

   Add if (i % 2 == 0) continue; before printf -> Option D

4. Quick Check:

   continue skips even numbers, prints odd [OK]

Hint: Skip even numbers with continue to print only odds [OK]

Common Mistakes:

• Skipping odd numbers instead of even
• Using continue after printf
• Incorrect condition for even numbers