Continue statement - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to skip the current loop iteration when i equals 3.

C

for(int i = 0; i < 5; i++) {
    if(i == [1]) {
        continue;
    }
    printf("%d ", i);
}

Drag options to blanks, or click blank then click option'

A3

B5

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using a value other than 3 in the if condition.

Forgetting to use continue inside the if block.

The continue statement skips the rest of the loop body when i is 3, so 3 is not printed.

2fill in blank

medium

Complete the code to skip printing even numbers using continue.

C

for(int i = 1; i <= 5; i++) {
    if(i % [1] == 0) {
        continue;
    }
    printf("%d ", i);
}

Drag options to blanks, or click blank then click option'

A2

B3

C5

D4

Attempts:

3 left

💡 Hint

Common Mistakes

Using the wrong divisor in the modulus operation.

Not using continue to skip the iteration.

The condition i % 2 == 0 checks if i is even. If true, continue skips printing that number.

3fill in blank

hard

Fix the error in the code to correctly skip printing negative numbers.

C

int numbers[] = {1, -2, 3, -4, 5};
for(int i = 0; i < 5; i++) {
    if(numbers[i] [1] 0) {
        continue;
    }
    printf("%d ", numbers[i]);
}

Drag options to blanks, or click blank then click option'

A!=

B>

C<

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < in the condition.

Using == or != which do not check negativity.

The condition numbers[i] < 0 checks for negative numbers. When true, continue skips printing them.

4fill in blank

hard

Fill both blanks to skip printing numbers divisible by 3 or less than 0.

C

int arr[] = {3, -1, 4, 6, -5};
for(int i = 0; i < 5; i++) {
    if(arr[i] [1] 0 || arr[i] % [2] == 0) {
        continue;
    }
    printf("%d ", arr[i]);
}

Drag options to blanks, or click blank then click option'

A<

B>

C3

D2

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < for negative check.

Using wrong divisor in modulus operation.

The condition skips numbers less than 0 and those divisible by 3.

5fill in blank

hard

Fill all three blanks to skip printing numbers that are negative, divisible by 2, or equal to 7.

C

int nums[] = {7, -2, 4, 9, -5};
for(int i = 0; i < 5; i++) {
    if(nums[i] [1] 0 || nums[i] % [2] == 0 || nums[i] [3] 7) {
        continue;
    }
    printf("%d ", nums[i]);
}

Drag options to blanks, or click blank then click option'

A<

B2

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of < for negative check.

Using wrong divisor or operator for equality check.

The condition skips numbers less than 0, divisible by 2, or equal to 7.