Continue statement - Mini Project: Build & Apply

Using the Continue Statement in C

📖 Scenario: Imagine you are sorting through a list of numbers and want to skip certain numbers based on a rule, like ignoring even numbers.

🎯 Goal: You will write a C program that uses the continue statement inside a loop to skip printing even numbers from a list.

📋 What You'll Learn

Create an array of integers with specific values

Create a variable to hold the length of the array

Use a for loop to go through the array

Use the continue statement to skip even numbers

Print only the odd numbers

💡 Why This Matters

🌍 Real World

Skipping unwanted data while processing lists or arrays is common in many programs, such as filtering out invalid inputs or ignoring certain cases.

💼 Career

Understanding how to control loops with statements like continue is essential for writing efficient and clear code in software development.

1

Create an integer array

Create an integer array called numbers with these exact values: 2, 5, 8, 11, 14, 17.

C

#include 

int main() {
    // Create the integer array called numbers
    // Your code here

    return 0;
}

Need a hint?

Use the syntax int numbers[] = {values}; to create the array.

2

Create a variable for array length

Create an integer variable called length and set it to the number of elements in the numbers array using sizeof(numbers) / sizeof(numbers[0]).

C

#include 

int main() {
    int numbers[] = {2, 5, 8, 11, 14, 17};
    // Create the length variable for the array
    // Your code here

    return 0;
}

Need a hint?

Use sizeof to find the total size of the array and divide by the size of one element.

3

Use a for loop with continue to skip even numbers

Write a for loop using int i = 0; i < length; i++ to go through numbers. Inside the loop, use an if statement to check if numbers[i] is even (use numbers[i] % 2 == 0). If it is even, use the continue statement to skip to the next loop iteration.

C

#include 

int main() {
    int numbers[] = {2, 5, 8, 11, 14, 17};
    int length = sizeof(numbers) / sizeof(numbers[0]);

    // Loop through the array and skip even numbers using continue
    // Your code here

    return 0;
}

Need a hint?

Use continue; inside the if block to skip even numbers.

4

Print only the odd numbers

Inside the for loop, after the continue statement, add a printf statement to print the odd numbers with a space after each number. Use printf("%d ", numbers[i]);. After the loop, print a newline with printf("\n");.

C

#include 

int main() {
    int numbers[] = {2, 5, 8, 11, 14, 17};
    int length = sizeof(numbers) / sizeof(numbers[0]);

    for (int i = 0; i < length; i++) {
        if (numbers[i] % 2 == 0) {
            continue;
        }
        // Print the odd number
        // Your code here
    }
    // Print a newline after the loop
    // Your code here

    return 0;
}

Need a hint?

Use printf("%d ", numbers[i]); to print each odd number followed by a space.

Don't forget to print a newline after the loop.