[Solved] How can you modify this script to skip printing even numbers? num=1 while [ $num -le 5 ]; do echo $num ((num++)) done | Bash Scripting

Bash Scripting - Loops

How can you modify this script to skip printing even numbers?

num=1
while [ $num -le 5 ]; do
  echo $num
  ((num++))
done

AAdd 'if (( num % 2 == 1 )); then echo $num; fi' inside the loop

BChange condition to '[ $num -eq 1 ]'

CRemove the increment statement

DUse 'continue' before echo

Step-by-Step Solution

Solution:

Step 1: Identify how to skip even numbers
Use modulo operator to check if number is odd.
Step 2: Add conditional echo
Print number only if it is odd using if statement inside loop.
Final Answer:
Add 'if (( num % 2 == 1 )); then echo $num; fi' inside the loop -> Option A
Quick Check:
Use modulo and if to skip evens [OK]

Quick Trick: Use modulo (%) to test odd/even inside while loop [OK]

Common Mistakes:

MISTAKES

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How can you modify this script to skip printing even numbers?