[Solved] What will be the output of this bash script?var="world" echo "Hello $var!" echo "Hello ${var}!" echo "Hello $var123" echo "Hello ${var}123" | Bash Scripting

Bash Scripting - Variables

What will be the output of this bash script?

var="world"
echo "Hello $var!"
echo "Hello ${var}!"
echo "Hello $var123"
echo "Hello ${var}123"

AHello world! Hello world! Hello world123 Hello 123

BHello world! Hello world! Hello Hello world123

CHello world! Hello world! Hello Hello 123

DHello world! Hello world! Hello world123 Hello world123

Step-by-Step Solution

Solution:

Step 1: Analyze each echo line
First two lines print "Hello world!" because $var and ${var} both expand to "world". Third line prints "Hello " because $var123 looks for variable named var123 which is empty. Fourth line prints "Hello world123" because ${var} is "world" plus "123".
Step 2: Combine outputs
Outputs are:
Hello world!
Hello world!
Hello
Hello world123
Final Answer:
Hello world! Hello world! Hello Hello world123 -> Option B
Quick Check:
Braces separate variable name correctly = D [OK]

Quick Trick: Braces avoid variable name confusion with suffixes [OK]

Common Mistakes:

MISTAKES

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