Bash Scripting - User Input
How can you combine default value substitution with a conditional check to print "Valid" only if input is non-empty, else print "Default used"?
How can you combine default value substitution with a conditional check to print "Valid" only if input is non-empty, else print "Default used"?
hard🚀 Application Q9 of 15
Step-by-Step Solution
Solution:
Step 1: Understand conditional checks for non-empty input
[ -n "$input" ]tests ifinputis non-empty.Step 2: Use if-else to print correct message
If non-empty, print "Valid"; else print "Default used".Final Answer:
if [ -n "$input" ]; then echo "Valid"; else echo "Default used"; fi -> Option DQuick Check:
Check non-empty with -n for conditional output = A [OK]
Quick Trick: Use if [ -n "$var" ] to check non-empty before printing [OK]
Common Mistakes:
MISTAKES- Confusing -n and -z tests
- Using parameter expansion incorrectly for conditional output
- Using || or && incorrectly for conditional prints
Master "User Input" in Bash Scripting
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