while loop in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print numbers from 1 to 5 using a while loop.

Bash Scripting

#!/bin/bash
count=1
while [ $count [1] 6 ]
do
  echo $count
  ((count++))
done

Drag options to blanks, or click blank then click option'

A-eq

B-gt

C-lt

D-ne

Attempts:

3 left

💡 Hint

Common Mistakes

Using -gt (greater than) will cause the loop not to run as expected.

Using -eq (equal) will only run if count equals 5, which is not the goal.

The operator -lt means "less than" in bash. The loop runs while count is less than 6.

2fill in blank

medium

Complete the code to stop the loop when the user enters 'exit'.

Bash Scripting

#!/bin/bash
input=""
while [ "$input" != "exit" ]
do
  read -p "Type something (or 'exit' to quit): " [1]
done

Drag options to blanks, or click blank then click option'

Aanswer

Btext

Cline

Dinput

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different variable name than the one in the condition causes the loop to never end.

Forgetting to quote the variable in the condition can cause errors.

The variable input stores what the user types. The loop checks if input is not 'exit'.

3fill in blank

hard

Fix the error in the loop condition to correctly check if count is less than or equal to 10.

Bash Scripting

#!/bin/bash
count=1
while [ $count [1] 10 ]
do
  echo $count
  ((count++))
done

Drag options to blanks, or click blank then click option'

A-le

B-eq

C-lt

D-ge

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt will stop the loop before count reaches 10.

Using -ge or -eq will cause the loop to behave incorrectly.

The operator -le means "less than or equal to" in bash, which matches the requirement.

4fill in blank

hard

Fill both blanks to create a loop that prints even numbers from 2 to 10.

Bash Scripting

#!/bin/bash
num=2
while [ $num [1] 10 ]
do
  echo $num
  num=$((num [2] 2))
done

Drag options to blanks, or click blank then click option'

A-le

B+

C-

D-lt

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt will exclude 10 from the output.

Subtracting 2 will cause an infinite loop.

The loop runs while num is less than or equal to 10 (-le). We add 2 each time (+) to get even numbers.

5fill in blank

hard

Fill all three blanks to create a loop that counts down from 5 to 1 and prints each number.

Bash Scripting

#!/bin/bash
count=5
while [ $count [1] 0 ]
do
  echo [2]
  count=[3]
done

Drag options to blanks, or click blank then click option'

A-gt

B$count

C$((count - 1))

D-lt

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt will cause the loop to never run.

Not decreasing count will cause an infinite loop.

The loop runs while count is greater than 0 (-gt). We print $count and then subtract 1 each time ($((count - 1))).