[Solved] Find the error in this script: i=0 while [ $i -lt 5 ] do i=$((i+1)) if [ $i -eq 3 ]; then break fi echo $i done | Bash Scripting

Bash Scripting - Loops

Find the error in this script:

i=0
while [ $i -lt 5 ]
do
  i=$((i+1))
  if [ $i -eq 3 ]; then
    break
  fi
  echo $i
done

AMissing done keyword

BMissing semicolon or newline after while condition

CIncorrect arithmetic syntax

DNo error, script runs correctly

Step-by-Step Solution

Solution:

Step 1: Check while loop syntax
The while condition must end with a semicolon or newline before do.
Step 2: Identify missing syntax
Here, while [ $i -lt 5 ] is not followed by a semicolon or newline before do, causing syntax error.
Final Answer:
Missing semicolon or newline after while condition -> Option B
Quick Check:
while needs semicolon/newline before do = D [OK]

Quick Trick: Put semicolon or newline after while condition before do [OK]

Common Mistakes:

MISTAKES

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