Bash Scripting - Loops
You want to write a bash script that prints all even numbers from 2 to 10 using a while loop. Which script correctly does this?
You want to write a bash script that prints all even numbers from 2 to 10 using a while loop. Which script correctly does this?
hard🚀 Application Q15 of 15
Step-by-Step Solution
Solution:
Step 1: Understand the goal
We want to print even numbers from 2 to 10 inclusive.Step 2: Check each option's logic
num=2 while [ $num -le 10 ]; do echo $num num=$((num + 1)) done starts at 2 and increments by 1 up to 10, printing 2 3 4 5 6 7 8 9 10 - incorrect.
num=1 while [ $num -le 10 ]; do if [ $((num % 2)) -eq 0 ]; then echo $num; fi num=$((num + 1)) done starts at 1, increments by 1, and prints only if even - correct.
num=2 while [ $num -lt 10 ]; do echo $num num=$((num + 2)) done stops before 10, missing 10.
num=0 while [ $num -le 10 ]; do echo $num num=$((num + 2)) done starts at 0, which is even but outside requested range (2 to 10).Step 3: Choose the best option
Only the script using modulo to explicitly check evenness prints exactly 2,4,6,8,10.Final Answer:
num=1 while [ $num -le 10 ]; do if [ $((num % 2)) -eq 0 ]; then echo $num; fi num=$((num + 1)) done -> Option AQuick Check:
Check even with modulo inside loop [OK]
Quick Trick: Use modulo inside loop to print even numbers [OK]
Common Mistakes:
MISTAKES- Stopping loop before 10
- Starting from 0 when 2 is required
- Not checking evenness explicitly
Master "Loops" in Bash Scripting
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