[Solved] Why does this script cause an infinite loop? count=1 until [ $count -gt 3 ] do echo $count done - Ans: Variable count is never incremented inside the loop | Bash Scripting

Bash Scripting - Loops

Why does this script cause an infinite loop?

count=1
until [ $count -gt 3 ]
do
  echo $count
done

AVariable count is never incremented inside the loop

BCondition syntax is incorrect

CMissing done keyword

DUsing -gt instead of -lt in condition

Step-by-Step Solution

Solution:

Step 1: Analyze loop body
The loop prints count but never changes its value.
Step 2: Understand loop condition effect
Since count stays 1, condition count -gt 3 never becomes true, causing infinite loop.
Final Answer:
Variable count is never incremented inside the loop -> Option A
Quick Check:
Increment loop variable to avoid infinite loop [OK]

Quick Trick: Always update loop variable inside until loop [OK]

Common Mistakes:

MISTAKES

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