[Solved] You want a script that prints "Even" if a number is even, and "Odd" if it is odd. Which script correctly uses if-then-else to do this?num=4 # Choose correct script | Bash Scripting

Bash Scripting - Conditionals

You want a script that prints "Even" if a number is even, and "Odd" if it is odd. Which script correctly uses if-then-else to do this?

num=4
# Choose correct script

Aif [ $num % 2 -eq 0 ]; then echo "Even" else echo "Odd" fi

Bif (( num % 2 == 0 )); then echo "Even" else echo "Odd" fi

Cif [ $num % 2 == 0 ]; then echo "Even" else echo "Odd" fi

Dif [ $num / 2 -eq 0 ]; then echo "Even" else echo "Odd" fi

Step-by-Step Solution

Solution:

Step 1: Understand arithmetic evaluation in bash
Using double parentheses (( )) allows arithmetic expressions and comparisons directly.
Step 2: Check each option
if [ $num % 2 -eq 0 ]; then echo "Even" else echo "Odd" fi uses % inside [ ] without arithmetic evaluation. if [ $num % 2 == 0 ]; then echo "Even" else echo "Odd" fi uses % inside [ ] without arithmetic evaluation. if [ $num / 2 -eq 0 ]; then echo "Even" else echo "Odd" fi uses / instead of % for modulus. if (( num % 2 == 0 )); then echo "Even" else echo "Odd" fi correctly uses (( )) with modulus and comparison.
Final Answer:
if (( num % 2 == 0 )); then echo "Even" else echo "Odd" fi -> Option B
Quick Check:
Use (( )) for arithmetic if [OK]

Quick Trick: Use (( )) for math conditions in bash [OK]

Common Mistakes:

MISTAKES

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You want a script that prints "Even" if a number is even, and "Odd" if it is odd. Which script correctly uses if-then-else to do this?