until loop in Bash Scripting - Mini Project: Build & Apply

Counting with an until Loop in Bash

📖 Scenario: You are creating a simple bash script that counts numbers from 1 up to a limit. This is useful when you want to repeat a task a certain number of times.

🎯 Goal: Build a bash script that uses an until loop to count from 1 to 5 and print each number.

📋 What You'll Learn

Create a variable count starting at 1

Create a variable limit set to 5

Use an until loop that runs until count is greater than limit

Inside the loop, print the current count value

Increment count by 1 inside the loop

💡 Why This Matters

🌍 Real World

Counting loops are common in scripts that automate tasks like backups, monitoring, or repeated checks.

💼 Career

Understanding loops in bash scripting is essential for system administrators and DevOps engineers to automate repetitive tasks efficiently.

1

Set up the starting count variable

Create a variable called count and set it to 1.

Bash Scripting

# Create a variable called count and set it to 1
# Your code here

Hint

Use count=1 to set the variable.

2

Set the limit variable

Create a variable called limit and set it to 5.

Bash Scripting

count=1
# Create a variable called limit and set it to 5
# Your code here

Hint

Use limit=5 to set the maximum count.

3

Write the until loop to count

Write an until loop that runs until count is greater than limit. Inside the loop, print the value of count and then increase count by 1.

Bash Scripting

count=1
limit=5
# Write an until loop that runs until count is greater than limit
# Inside the loop, print count and increment count by 1
# Your code here

Hint

Use until [ "$count" -gt "$limit" ] to start the loop. Use echo "$count" to print. Use count=$((count + 1)) to increase count.

4

Run the script to see the output

Run the script to print numbers from 1 to 5 using the until loop.

Bash Scripting

count=1
limit=5
until [ "$count" -gt "$limit" ]
do
  echo "$count"
  count=$((count + 1))
done
# Run the script to see the output

Hint

Run the script in your terminal. You should see numbers 1 to 5 printed each on a new line.

Practice

1. What does an until loop do in bash scripting?

easy

A. It repeats commands until the condition becomes true.

B. It repeats commands while the condition is true.

C. It runs commands only once regardless of condition.

D. It runs commands only if the condition is false.

Solution

1. Step 1: Understand the until loop behavior

   An until loop runs repeatedly until its condition becomes true, meaning it stops when the condition is true.

2. Step 2: Compare options with definition

   It repeats commands until the condition becomes true. correctly states the loop repeats until the condition is true. It repeats commands while the condition is true. describes a while loop. Options C and D are incorrect behaviors.

3. Final Answer:

   It repeats commands until the condition becomes true. -> Option A

4. Quick Check:

   until loop = repeat until true [OK]

Hint: Remember: until stops when condition is true [OK]

Common Mistakes:

• Confusing until with while loop
• Thinking until runs only once
• Believing until runs while condition is true

2. Which of the following is the correct syntax for an until loop in bash?

easy

A. until [ condition ]; do commands; done

B. until ( condition ) { commands }

C. until { condition } do commands done

D. until condition do commands done

Solution

1. Step 1: Recall bash until loop syntax

   The correct syntax uses square brackets for condition, followed by do and done keywords: until [ condition ]; do commands; done

2. Step 2: Check each option

   until [ condition ]; do commands; done matches correct syntax. Options B, C, and D use incorrect brackets or missing semicolons.

3. Final Answer:

   until [ condition ]; do commands; done -> Option A

4. Quick Check:

   Syntax = until [ condition ]; do ... done [OK]

Hint: Use square brackets and do/done keywords [OK]

Common Mistakes:

• Using parentheses instead of square brackets
• Omitting do or done keywords
• Missing semicolon before do

3. What will be the output of this script?

count=1
until [ $count -gt 3 ]
do
  echo $count
  ((count++))
done

medium

A. 1 2

B. 1 2 3 4

C. 1 2 3

D. No output, infinite loop

Solution

1. Step 1: Analyze loop condition and increments

   The loop runs until count is greater than 3. Starting at 1, it prints count and increments it each time.

2. Step 2: Trace iterations

   count=1 (prints 1), count=2 (prints 2), count=3 (prints 3), count=4 stops loop because 4 > 3.

3. Final Answer:

   1 2 3 -> Option C

4. Quick Check:

   Prints 1 to 3 before stopping [OK]

Hint: Loop stops when count > 3, so prints 1 to 3 [OK]

Common Mistakes:

• Thinking it prints 4
• Confusing until with while loop condition
• Assuming infinite loop

4. Identify the error in this until loop script:

count=1
until [ $count -lt 5 ]
do
  echo $count
  ((count++))
done

medium

A. Missing semicolon after condition.

B. The loop will never run because condition is initially true.

C. The variable count is not initialized.

D. The condition should use -gt instead of -lt.

Solution

1. Step 1: Understand the until loop condition

   until runs while the condition is false and stops when true. Here, condition is count -lt 5, which is true at start (count=1).

2. Step 2: Analyze loop execution

   Since condition is true initially, loop does not run even once.

3. Final Answer:

   The loop will never run because condition is initially true. -> Option B

4. Quick Check:

   until stops immediately if condition true [OK]

Hint: until runs only while condition is false [OK]

Common Mistakes:

• Confusing -lt with -gt in condition
• Assuming loop runs at least once
• Missing that until stops when condition true

5. You want to write a bash script that waits until a file named ready.txt exists before continuing. Which until loop correctly implements this?

hard

A. until [ ! -f ready.txt ]; do sleep 1; done

B. until [ ! -f ready.txt ]; do echo 'Waiting'; done

C. until [ -d ready.txt ]; do sleep 1; done

D. until [ -f ready.txt ]; do sleep 1; done

Solution

1. Step 1: Understand the goal and condition

   The script should wait until the file exists. The loop runs while the condition is false, so condition should be "file exists" [ -f ready.txt ].

2. Step 2: Check each option's condition

   until [ -f ready.txt ]; do sleep 1; done loops while [ -f ] is false (file missing), sleeping until file exists. B, C (-d for directory), and D use wrong conditions.

3. Final Answer:

   until [ -f ready.txt ]; do sleep 1; done -> Option D

4. Quick Check:

   Loop while file missing, stops when exists [OK]

Hint: Condition [ -f file ] stops when file exists [OK]

Common Mistakes:

• Using -d instead of -f for file check
• Using ! -f negation incorrectly
• Not including sleep to avoid busy wait