until loop in Bash Scripting - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create an until loop that stops when the variable count reaches 5.

Bash Scripting

count=1
until [ $count [1] 5 ]
do
  echo $count
  ((count++))
done

Drag options to blanks, or click blank then click option'

A-lt

B-gt

C-eq

D-ne

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt instead of -gt causes the loop to never run.

Using -eq stops the loop early.

The until loop runs until the condition is true. Here, it runs while count is less than 5.

2fill in blank

medium

Complete the code to increment the variable inside the until loop.

Bash Scripting

num=0
until [ $num -eq 3 ]
do
  echo $num
  [1]
done

Drag options to blanks, or click blank then click option'

A((num++))

Bnum += 1

Cnum=num+1

Dnum++

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'num=num+1' treats num as a string, not a number.

Using 'num++' alone is not valid in bash.

In bash, arithmetic expressions like ((num++)) correctly increment the variable.

3fill in blank

hard

Fix the error in the until loop condition to stop when var equals 10.

Bash Scripting

var=0
until [ $var [1] 10 ]
do
  echo $var
  ((var+=2))
done

Drag options to blanks, or click blank then click option'

A-lt

B-le

C-gt

D-ne

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt stops the loop too early.

Using -gt causes the loop to never run.

The until loop runs until the condition is true. Using -ne means it runs while var is not equal to 10.

4fill in blank

hard

Fill both blanks to create an until loop that prints numbers from 1 to 4.

Bash Scripting

i=1
until [ $i [1] 5 ]
do
  echo $i
  [2]
done

Drag options to blanks, or click blank then click option'

A-eq

B((i++))

C-lt

Di+=1

Attempts:

3 left

💡 Hint

Common Mistakes

Using -lt stops the loop immediately.

Using 'i+=1' alone is not valid syntax in bash.

The loop runs until i equals 5, so it runs while i is less than 5. Incrementing i with ((i++)) updates the variable correctly.

5fill in blank

hard

Fill all three blanks to create an until loop that prints even numbers from 2 to 8.

Bash Scripting

num=2
until [ $num [1] 10 ]
do
  echo $num
  [2]
done

Drag options to blanks, or click blank then click option'

A-ge

B((num+=2))

C-lt

Dnum++

Attempts:

3 left

💡 Hint

Common Mistakes

Using -ge stops the loop immediately.

Using num++ increments by 1, not 2.

The loop runs while num is less than 10. Incrementing num by 2 each time prints even numbers.