Bash Scripting - Variables
Given this script:
```bash
export GLOBAL_VAR=100
function modify_vars() {
local LOCAL_VAR=200
GLOBAL_VAR=300
}
modify_vars
echo "$GLOBAL_VAR $LOCAL_VAR"
```
What will be the output and why?
Given this script: ```bash export GLOBAL_VAR=100 function modify_vars() { local LOCAL_VAR=200 GLOBAL_VAR=300 } modify_vars echo "$GLOBAL_VAR $LOCAL_VAR" ``` What will be the output and why?
hard🚀 Application Q9 of 15
Step-by-Step Solution
Solution:
Step 1: Analyze GLOBAL_VAR change
GLOBAL_VAR is exported and reassigned inside function without 'local', so it changes globally to 300.Step 2: Analyze LOCAL_VAR scope
LOCAL_VAR is declared local inside function, so it does not exist outside; echo prints empty for it.Final Answer:
300 (space) empty, because GLOBAL_VAR changed globally, LOCAL_VAR is local -> Option CQuick Check:
Global vars change globally; local vars stay inside functions [OK]
Quick Trick: Local vars vanish outside; globals persist and change [OK]
Common Mistakes:
MISTAKES- Expecting local variable to print outside function
- Assuming GLOBAL_VAR unchanged
- Confusing export effect
Master "Variables" in Bash Scripting
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