0
0

Tabular Puzzle

Introduction

Tabular Puzzle में multi-attribute data (people, places, jobs, colours, months आदि) को दिए गए clues की मदद से एक table में organise करना होता है। यह pattern systematic elimination, attributes के बीच linking clues, और accurate final matching का अभ्यास करवाता है।

इसे competitive exams (SBI PO, IBPS, SSC, CAT) में बहुत पूछा जाता है क्योंकि यह careful deduction और attention to detail को test करता है। अच्छा table design और stepwise elimination इन problems को आसान और reproducible बनाते हैं।

Pattern: Tabular Puzzle

Pattern

Clues को table entries में बदलें और elimination + linking से हर cell भरें।

  • हर entity (person/item) को row बनाएं; attributes (city, job, day) को columns।
  • Direct facts पहले mark करें, फिर “not” clues से options eliminate करें।
  • Linking clues (“the person from X is a Y”) दो attributes को lock कर देते हैं - इन्हें तुरंत लागू करें।
  • Iterate करें: एक cell भरने से बाकी forced cells भी तय होते हैं - table को लगातार अपडेट रखें।

Step-by-Step Example

Question

चार दोस्त - A, B, C और D - अलग-अलग cities में रहते हैं: Delhi, Mumbai, Kolkata और Chennai। हर एक की अलग profession है: Doctor, Engineer, Teacher और Lawyer.

Clues:

  1. B, Delhi या Chennai का नहीं है।
  2. Kolkata वाला व्यक्ति Teacher है।
  3. D एक Lawyer है और Mumbai में नहीं रहता।
  4. A, Delhi में रहता है।

Question: Chennai में कौन रहता है?

Options:
A) B    B) C    C) D    D) A

Solution

  1. Step 1: Mark direct facts

    A → Delhi; D → Lawyer; D ≠ Mumbai; Kolkata → Teacher (city-profession link)。

  2. Step 2: Build an initial table (partial)

    PersonCityProfession
    ADelhi-
    BNot Delhi, Not Chennai-
    C-Teacher (if Kolkata)
    DNot MumbaiLawyer

  3. Step 3: Apply elimination and linking

    B Delhi/Chennai नहीं हो सकता → B = Mumbai या Kolkata। D Mumbai नहीं है और Lawyer है → D, Kolkata नहीं हो सकता (क्योंकि Kolkata → Teacher)। A = Delhi → बाकी cities (Mumbai, Kolkata, Chennai) B, C, D में बाँटनी हैं। Kolkata → Teacher और D Lawyer है → C = Kolkata & Teacher।

  4. Step 4: Complete the final table

    PersonCityProfession
    ADelhiEngineer
    BMumbaiDoctor
    CKolkataTeacher
    DChennaiLawyer

  5. Final Answer:

    D (D, Chennai में रहता है) → Option C

  6. Quick Check:

    A = Delhi ✔; D = Lawyer & ≠ Mumbai → D = Chennai ✔; Kolkata = Teacher → C ✔; B ≠ Delhi/Chennai → B = Mumbai ✔

Quick Variations

1. Two-attribute tables: Person × City।

2. Three-attribute tables: Person × City × Profession (2D grid + linked cells)।

3. Conditional tables: “either-or”, “exactly one matches” clues।

4. बड़ी tables (5×5): stepwise elimination और partial tables helpful।

Trick to Always Use

  • Step 1: साफ table बनाएं और direct facts पहले mark करें (tick / ‘not’ mentally)।
  • Step 2: Linked clues (Kolkata = Teacher) तुरंत lock करें - ये options तेजी से कम करते हैं।
  • Step 3: Forced cells भरें; हर fill से नई eliminations मिलती हैं।
  • Step 4: Final solution table ज़रूर दिखाएँ - इससे verification आसान और foolproof बनती है।

Summary

Summary

  • Grid में direct facts और obvious ‘not’ entries mark करें।
  • City-profession जैसे combined clues तुरंत lock करें।
  • Forced cells भरते जाएँ और table को लगातार अपडेट रखें।
  • Final table दिखाना हमेशा उपयोगी है - verification तेज़ और साफ रहती है।

याद रखने योग्य उदाहरण:
जब किसी clue में दो attributes link हों (जैसे Kolkata = Teacher), उस जोड़ी को तुरंत assign करें - फिर बाकी लोगों के लिए वह city और profession eliminate करें।

Practice

(1/5)
1. Four friends - A, B, C, and D - each like a different color (Red, Blue, Green, Yellow) and drive a different car (Honda, Ford, Tata, Maruti). The clues are:<br>1. A likes Red and does not drive Ford.<br>2. The person who drives Tata likes Green.<br>3. D drives Maruti.<br>4. B does not like Yellow or Green.<br>Who drives the Ford?
easy
A. B
B. C
C. D
D. A

Solution

  1. Step 1: Note direct facts

    A → Red, not Ford; D → Maruti; Tata → Green.

  2. Step 2: Partial table from given facts

    PersonColorCar
    ARedNot Ford
    BNot Yellow/Green-
    CGreenTata
    D-Maruti

  3. Step 3: Apply eliminations

    B cannot be Yellow/Green, so B = Blue. A already has Red → remaining colors match correctly. Since Ford is not used yet and A ≠ Ford → Ford = B.

  4. Step 4: Final table

    PersonColorCar
    ARedHonda
    BBlueFord
    CGreenTata
    DYellowMaruti

  5. Final Answer:

    B → Option A

  6. Quick Check:

    All clues consistent ✅
Hint: Start with fixed pairs and direct negatives before using eliminations.
Common Mistakes: Ignoring 'not' clues early, leading to overlap errors.
2. Five employees - P, Q, R, S, and T - work in five departments: HR, IT, Finance, Marketing, and Admin. The clues are:<br>1. Q works in IT.<br>2. P works neither in HR nor in Admin.<br>3. The Marketing employee sits next to HR.<br>4. R works in Finance.<br>5. T does not work in Marketing.<br>Who works in Marketing?
easy
A. S
B. P
C. T
D. Q

Solution

  1. Step 1: Fixed data

    Q = IT; R = Finance.

  2. Step 2: Partial table

    EmployeeDepartment
    PNot HR/Admin
    QIT
    RFinance
    S-
    TNot Marketing

  3. Step 3: Deduction

    P ≠ HR/Admin → possible: IT/Finance/Marketing. IT, Finance taken → P = Marketing.

  4. Step 4: Final table

    EmployeeDepartment
    PMarketing
    QIT
    RFinance
    SHR
    TAdmin

  5. Final Answer:

    P → Option B

  6. Quick Check:

    P not HR/Admin ✅, Marketing next to HR ✅
Hint: Use exclusion clues before adjacency clues.
Common Mistakes: Treating ‘next to HR’ as same department.
3. Four students - A, B, C, and D - study four subjects: Maths, Physics, Chemistry, and Biology. The clues are:<br>1. A does not study Maths or Physics.<br>2. C studies Chemistry.<br>3. D studies a subject alphabetically before C’s.<br>4. B does not study Biology.<br>Who studies Physics?
medium
A. A
B. D
C. C
D. B

Solution

  1. Step 1: Direct clues

    C = Chemistry; A ≠ Maths/Physics → A = Biology.

  2. Step 2: Partial table

    StudentSubject
    ABiology
    BNot Biology
    CChemistry
    D-

  3. Step 3: Apply alphabetical rule

    D’s subject alphabetically before Chemistry → only Maths fits. D = Maths.

  4. Step 4: Fill remaining

    Subjects used: Bio, Chem, Maths → remaining Physics → B = Physics.

  5. Final Table:

    StudentSubject
    ABiology
    BPhysics
    CChemistry
    DMaths

  6. Final Answer:

    B → Option D

  7. Quick Check:

    Alphabetical before Chemistry → D = Maths ✅
Hint: Alphabetical hints often give hidden order of assignment.
Common Mistakes: Overlooking implicit alphabetical constraints.
4. Four athletes - P, Q, R, and S - play four different sports: Cricket, Football, Tennis, and Hockey. The clues are:<br>1. P does not play Tennis.<br>2. The Football player’s name alphabetically follows the Tennis player.<br>3. R plays Cricket.<br>4. Q’s name comes alphabetically before the Hockey player’s.<br>Who plays Tennis?
medium
A. P
B. Q
C. R
D. S

Solution

  1. Step 1: Fixed fact

    R = Cricket.

  2. Step 2: Partial table

    AthleteSport
    PNot Tennis
    Q-
    RCricket
    S-

  3. Step 3: Test alphabetical relations

    If Q = Tennis → Football must follow alphabetically → choose S = Football; Hockey after Q → assign P = Hockey.

  4. Step 4: Final Table

    AthleteSport
    PHockey
    QTennis
    RCricket
    SFootball

  5. Final Answer:

    Q → Option B

  6. Quick Check:

    Tennis (Q) alphabetically before Football (S) ✅
Hint: Use alphabetical order as a hidden sequencing clue.
Common Mistakes: Misreading alphabetical relation as performance ranking.
5. Five friends - A, B, C, D, and E - each own a different pet (Dog, Cat, Parrot, Fish, Rabbit) and live in different cities (Delhi, Mumbai, Chennai, Kolkata, Pune). The clues are:<br>1. A lives in Mumbai and owns a Parrot.<br>2. The person from Chennai owns a Dog.<br>3. D lives in Delhi.<br>4. C owns a Cat.<br>5. E does not live in Pune or Chennai.<br>Who owns the Fish?
medium
A. B
B. D
C. E
D. C

Solution

  1. Step 1: Direct mapping

    A = Mumbai + Parrot; D = Delhi; C = Cat; Chennai → Dog.

  2. Step 2: Partial table

    PersonCityPet
    AMumbaiParrot
    B--
    CChennaiCat
    DDelhiDog
    ENot Pune/Chennai-

  3. Step 3: Fill remaining

    E cannot be Pune or Chennai → E = Kolkata. Remaining pets → Fish & Rabbit → assign E = Fish, B = Rabbit.

  4. Step 4: Final Table

    PersonCityPet
    AMumbaiParrot
    BPuneRabbit
    CChennaiCat
    DDelhiDog
    EKolkataFish

  5. Final Answer:

    E → Option C

  6. Quick Check:

    Each city and pet uniquely assigned ✅
Hint: Start with fixed city-pet pairs to reduce variables quickly.
Common Mistakes: Assigning E to a restricted city.

Mock Test

Ready for a challenge?

Take a 10-minute AI-powered test with 10 questions (Easy-Medium-Hard mix) and get instant SWOT analysis of your performance!

10 Questions
5 Minutes