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Trains Passing Pole / Platform

Introduction

Problems about trains passing a pole or a platform are extremely common in Time, Speed & Distance. They test understanding of what distance the train actually needs to cover and require consistent unit conversion (km/h ↔ m/s) when time is in seconds.

This pattern is important because it combines length, speed and time - and once you know the exact distance to be covered (train length vs. train + platform length) the rest is mechanical.

Pattern: Trains Passing Pole / Platform

Pattern

Key concept: Time = Distance to be covered ÷ Speed (use consistent units).

  • Passing a pole or a stationary point: Distance = length of the train.
  • Passing a platform (standing length L_p): Distance = train length + platform length.
  • When two trains pass each other: If opposite directions → add speeds; if same direction → subtract speeds. Distance = sum of their lengths.
  • Units: If time in seconds and lengths in metres, convert speed from km/h → m/s using ×5/18 (or divide by 3.6 when converting m/s → km/h).

Step-by-Step Example

Question

A train 150 m long runs at 72 km/h. How long will it take to pass a pole?

Solution

  1. Step 1: Identify given values

    Train length = 150 m; speed = 72 km/h; passing a pole → distance to cover = train length = 150 m.
  2. Step 2: Convert speed to m/s (since distance in metres and time asked in seconds)

    72 km/h × (5/18) = 72 × 5 ÷ 18 = 20 m/s.
  3. Step 3: Apply Time = Distance ÷ Speed

    Time = 150 ÷ 20 = 7.5 seconds.
  4. Final Answer:

    The train will pass the pole in 7.5 s.
  5. Quick Check:

    In 7.5 s at 20 m/s the train travels 20 × 7.5 = 150 m ✅

Quick Variations

1. Two trains passing each other: Distance = sum of lengths. Use relative speed (add or subtract) and ensure units match.

2. Train passing a moving object (e.g., slow train/person): Distance = train length (+ gap if needed). Relative speed = train speed - object speed (same direction) or + (opposite).

3. Lengths in km or mixed units: Convert lengths to consistent units (metres when using seconds, or kilometres when using hours).

4. Platform length sometimes given as 'x times train length': compute numeric platform length first, then sum.

Trick to Always Use

  • Step 1: Ask: passing a pole (distance = train length) or platform (distance = train + platform length)?
  • Step 2: Convert units so distance and speed are compatible (m with m/s, km with km/h).
  • Step 3: If two objects are involved, decide same/opposite direction → relative speed = v1 - v2 or v1 + v2.
  • Step 4: Use Time = Distance ÷ Speed; round only at the end and provide seconds/minutes as required.

Summary

Summary

For trains passing poles or platforms:

  • Distance to cover = train length (pole) or train + platform length (platform).
  • Use consistent units: m and m/s when time in seconds; km and km/h when time in hours.
  • Formula: Time = Distance ÷ Speed. For two-train interactions use relative speed and sum of lengths.
  • Quick check: multiply computed time by speed to verify the distance equals what you expected.

Practice

(1/5)
1. A train 120 m long runs at a speed of 54 km/h. How long will it take to pass a pole?
easy
A. 8 s
B. 7 s
C. 6 s
D. 9 s

Solution

  1. Step 1: Identify Case

    Passing a pole → distance to cover = train length = 120 m.
  2. Step 2: Convert Speed

    54 km/h × (5/18) = 15 m/s.
  3. Step 3: Compute Time

    Time = Distance ÷ Speed = 120 ÷ 15 = 8 seconds.
  4. Final Answer:

    The train passes the pole in 8 s → Option A.
  5. Quick Check:

    15 × 8 = 120 m ✅
Hint: For a pole: Time = Train length ÷ (Speed in m/s).
Common Mistakes: Using km/h directly without converting to m/s.
2. A train 180 m long passes a platform 120 m long in 15 seconds. Find its speed.
easy
A. 60 km/h
B. 72 km/h
C. 75 km/h
D. 80 km/h

Solution

  1. Step 1: Identify Distance

    Passing a platform → distance = train + platform = 180 + 120 = 300 m.
  2. Step 2: Compute Speed in m/s

    Speed = Distance ÷ Time = 300 ÷ 15 = 20 m/s.
  3. Step 3: Convert to km/h

    20 × 3.6 = 72 km/h.
  4. Final Answer:

    Speed = 72 km/h → Option B.
  5. Quick Check:

    72 km/h = 20 m/s → 20 × 15 = 300 m ✅
Hint: Add platform length and use Time = Distance ÷ Speed.
Common Mistakes: Ignoring platform length or failing to convert units.
3. A train 150 m long crosses a bridge 350 m long in 20 seconds. Find its speed.
easy
A. 90 km/h
B. 100 km/h
C. 108 km/h
D. 126 km/h

Solution

  1. Step 1: Find Total Distance

    Distance = train + bridge = 150 + 350 = 500 m.
  2. Step 2: Compute Speed in m/s

    Speed = Distance ÷ Time = 500 ÷ 20 = 25 m/s.
  3. Step 3: Convert to km/h

    25 × 3.6 = 90 km/h.
  4. Final Answer:

    Speed = 90 km/h → Option A.
  5. Quick Check:

    90 km/h = 25 m/s → 25 × 20 = 500 m ✅
Hint: Add lengths, divide by time, then convert m/s → km/h.
Common Mistakes: Taking only train length instead of adding bridge length.
4. A train 100 m long takes 10 seconds to pass a man standing on a platform. Find the speed of the train in km/h.
medium
A. 30 km/h
B. 40 km/h
C. 36 km/h
D. 45 km/h

Solution

  1. Step 1: Distance

    Passing a person → distance = train length = 100 m.
  2. Step 2: Compute Speed in m/s

    Speed = 100 ÷ 10 = 10 m/s.
  3. Step 3: Convert to km/h

    10 × 3.6 = 36 km/h.
  4. Final Answer:

    Speed = 36 km/h → Option C.
  5. Quick Check:

    36 km/h = 10 m/s → 100 ÷ 10 = 10 s ✅
Hint: Speed = Length ÷ Time (convert to km/h by ×3.6).
Common Mistakes: Using platform length when none is given.
5. A train 160 m long crosses a platform of length 240 m in 16 seconds. Find its speed.
medium
A. 72 km/h
B. 81 km/h
C. 99 km/h
D. 90 km/h

Solution

  1. Step 1: Total Distance

    Distance = train + platform = 160 + 240 = 400 m.
  2. Step 2: Speed in m/s

    Speed = 400 ÷ 16 = 25 m/s.
  3. Step 3: Convert to km/h

    25 × 3.6 = 90 km/h.
  4. Final Answer:

    Speed = 90 km/h → Option D.
  5. Quick Check:

    90 × 5/18 = 25 m/s → 25 × 16 = 400 m ✅
Hint: Add platform and train lengths before dividing by time.
Common Mistakes: Using only train length for total distance.

Mock Test

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