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Circular Track / Same Starting Point

Introduction

Problems on a circular track with same starting point ask about meeting times, overtakes, number of rounds, and relative positions when two or more runners start together (same or opposite directions).

This pattern is important because it combines relative speed ideas with the concept of laps (track length) and helps solve many contest-style questions quickly using simple formulas.

Pattern: Circular Track / Same Starting Point

Pattern

Key concept: Convert motion on a circle into linear distance (laps) and use relative speed: when two people meet or overtake, they cover integer laps difference.

  • Same direction: Relative speed = (faster - slower). Time to first overtake = Track length ÷ relative speed.
  • Opposite directions: Relative speed = (sum of speeds). Time to first meeting = Track length ÷ relative speed.
  • Number of meetings in time T: If opposite directions → meetings = ⌊(relative speed × T) ÷ track length⌋ (count integer meetings). If same direction → overtakes = ⌊(relative speed × T) ÷ track length⌋.
  • When asked about positions after time T: Compute distance each covers (speed × T), reduce modulo track length to find position on track.
  • For integer lap questions: If faster completes n more laps than slower in time T, (faster - slower) × T = n × track length.

Step-by-Step Example

Question

Two runners start at the same point on a circular track of length 400 m and run in opposite directions. Their speeds are 6 m/s and 4 m/s. When will they meet first?

Solution

  1. Step 1: Identify relative speed

    Opposite directions → relative speed = 6 + 4 = 10 m/s.
  2. Step 2: Time to meet

    Time = Track length ÷ Relative speed = 400 ÷ 10 = 40 seconds.
  3. Final Answer:

    They meet first after 40 s.
  4. Quick Check:

    In 40 s, A covers 240 m and B covers 160 m; together 400 m → they meet ✅

Quick Variations

1. How many times they meet in T seconds: use (relative speed × T) ÷ track length and take integer part.

2. When will they be together after k meetings: set (relative speed × time) = k × track length and solve for time.

3. Positions after time T: compute (speed × T) mod track length for each runner to get exact location.

4. Opposite-direction multiple meetings: meetings are evenly spaced by time = track length ÷ (sum of speeds).

5. When counting overtakes: faster can overtake multiple times; each overtake corresponds to one extra lap covered relative to the slower runner.

Trick to Always Use

  • Step 1: Convert circular motion into linear laps: treat each lap as length L.
  • Step 2: Use relative speed: add for opposite, subtract for same direction.
  • Step 3: For meetings/overtakes set (relative speed × time) = n × L for integer n (number of meetings/overtakes).
  • Step 4: For final positions compute distance modulo L to find the place on the track.

Summary

Summary

For circular track problems with the same starting point:

  • Use relative speed (add if opposite, subtract if same direction).
  • Time to meet/overcome = track length ÷ relative speed (for first event).
  • Number of meetings/overtakes in time T = ⌊(relative speed × T) ÷ track length⌋.
  • Find exact location after time T by taking each runner’s distance (speed × T) modulo track length.
  • Always keep units consistent and use the actionable steps to structure your solution.

Practice

(1/5)
1. Two runners start from the same point on a circular track of length 300 m and run in opposite directions with speeds 5 m/s and 7 m/s. After how many seconds will they meet for the first time?
easy
A. 25 s
B. 20 s
C. 22 s
D. 30 s

Solution

  1. Step 1: Identify motion type

    Opposite directions → relative speed = 5 + 7 = 12 m/s.
  2. Step 2: Compute time

    Time = Track length ÷ Relative speed = 300 ÷ 12 = 25 s.
  3. Final Answer:

    They meet after 25 s → Option A.
  4. Quick Check:

    Together they cover 12 × 25 = 300 m → one full lap ✅
Hint: For opposite directions, add speeds and divide track length by sum.
Common Mistakes: Subtracting speeds instead of adding for opposite direction.
2. Two boys A and B start from the same point on a circular track of 400 m and run in the same direction at 6 m/s and 4 m/s. After how many seconds will A overtake B for the first time?
easy
A. 100 s
B. 200 s
C. 150 s
D. 250 s

Solution

  1. Step 1: Motion type

    Same direction → relative speed = 6 - 4 = 2 m/s.
  2. Step 2: Compute time

    Time = Track length ÷ Relative speed = 400 ÷ 2 = 200 s.
  3. Final Answer:

    A overtakes B after 200 s → Option B.
  4. Quick Check:

    In 200 s, A covers 6×200 = 1200 m and B 4×200 = 800 m → difference = 400 m (one lap) ✅
Hint: For same direction, subtract speeds and divide track length by the difference.
Common Mistakes: Using total speeds instead of difference for same direction.
3. Two cyclists start together on a circular track of 360 m in opposite directions. Their speeds are 8 m/s and 4 m/s. How long will they take to meet for the second time?
easy
A. 30 s
B. 40 s
C. 60 s
D. 45 s

Solution

  1. Step 1: Relative speed

    Opposite directions → relative speed = 8 + 4 = 12 m/s.
  2. Step 2: Time for first meeting

    Time₁ = 360 ÷ 12 = 30 s.
  3. Step 3: Second meeting

    The second meeting occurs after 2 × Time₁ = 60 s.
  4. Final Answer:

    They meet the second time after 60 s → Option C.
  5. Quick Check:

    After 60 s they cover 12×60 = 720 m combined → two laps (2×360) ✅
Hint: Second meeting = 2 × (track ÷ relative speed) for opposite-direction starters.
Common Mistakes: Counting the starting instant as a meeting or using only first-meeting time.
4. On a circular track of 500 m, A runs at 10 m/s and B at 6 m/s in the same direction. After how many seconds will A be 1 lap ahead of B?
medium
A. 125 s
B. 120 s
C. 130 s
D. 150 s

Solution

  1. Step 1: Relative speed

    Same direction → relative speed = 10 - 6 = 4 m/s.
  2. Step 2: Time to gain one lap

    Time = Track length ÷ Relative speed = 500 ÷ 4 = 125 s.
  3. Final Answer:

    A will be one lap ahead after 125 s → Option A.
  4. Quick Check:

    In 125 s A covers 10×125 = 1250 m, B covers 6×125 = 750 m → difference = 500 m (one lap) ✅
Hint: One-lap lead → track length ÷ (faster - slower).
Common Mistakes: Confusing lap distance with total distance run.
5. Two runners start simultaneously from the same point on a circular track of 600 m in opposite directions. Speeds are 5 m/s and 7 m/s. How many times will they meet in 10 minutes?
medium
A. 4 times
B. 5 times
C. 6 times
D. 12 times

Solution

  1. Step 1: Relative speed

    Opposite directions → relative speed = 5 + 7 = 12 m/s.
  2. Step 2: Time per meeting

    Time per meeting = Track length ÷ Relative speed = 600 ÷ 12 = 50 s.
  3. Step 3: Meetings in 10 minutes

    Total time = 10 × 60 = 600 s → Meetings = 600 ÷ 50 = 12 times.
  4. Final Answer:

    They meet 12 times in 10 minutes → Option D.
  5. Quick Check:

    Every 50 s they meet → 600/50 = 12 meetings (first meeting at 50 s, last at 600 s) ✅
Hint: Number of meetings = (relative speed × total time) ÷ track length.
Common Mistakes: Forgetting to convert minutes to seconds or excluding meetings at exact endpoints incorrectly.

Mock Test

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