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Meeting and Overtaking Problems

Introduction

Meeting and overtaking problems are a core part of Time, Speed & Distance. They ask when two moving objects will meet (coming towards each other) or when one will catch up with and pass another (same direction). These problems become simple once you convert the scenario into a single formula using relative speed and the correct distance to be covered.

This pattern is important because it appears often in competitive exams and daily reasoning - trains, cars, runners - and is solved with the same small set of steps every time.

Pattern: Meeting and Overtaking Problems

Pattern

Key concept: Reduce the two-body problem to one-body by using relative speed and the specific distance that must be closed.

  • Meeting (moving towards each other): Relative speed = v₁ + v₂. Time = Initial separation ÷ (v₁ + v₂).
  • Overtaking (same direction): Relative speed = |v₁ - v₂| (faster - slower). Time = Distance to be covered ÷ (v_faster - v_slower).
  • Distance to be covered: For meeting = initial gap; for overtaking an object (train/person) = length of object + any initial gap (if required).
  • Unit consistency: Use km/h with hours or m/s with seconds - convert before computing.

Step-by-Step Example

Question

Two cars are 150 km apart and drive towards each other at 70 km/h and 50 km/h. When will they meet?

Solution

  1. Step 1: Identify given values

    Distance = 150 km; speeds v₁ = 70 km/h, v₂ = 50 km/h.
  2. Step 2: Decide case and compute relative speed

    They move towards each other → Relative speed = v₁ + v₂ = 70 + 50 = 120 km/h.
  3. Step 3: Apply time formula

    Time = Distance ÷ Relative speed = 150 ÷ 120 = 1.25 hours = 1 hour 15 minutes.
  4. Final Answer:

    They meet in 1 hour 15 minutes.
  5. Quick Check:

    In 1.25 h, first covers 87.5 km and second 62.5 km → total 150 km ✅

Quick Variations

1. Two objects meet after starting at different times: compute distances covered till meeting (use relative speed and adjust for head-start time).

2. Overtaking two long objects: Distance to cover = sum of both lengths (if one must fully clear the other).

3. Meeting on circular track: use relative speed; if looking for repeated meetings, consider LCM of lap-times or use time = circumference ÷ relative speed.

4. Units mixed (km/h and m/s): convert to common units before computing.

Trick to Always Use

  • Step 1: Ask: "Are they moving towards each other (meeting) or same direction (overtaking)?"
  • Step 2: For meeting → relative speed = v₁ + v₂. For overtaking → relative speed = v_faster - v_slower.
  • Step 3: Figure the correct distance to be closed: initial gap, length(s), or head-start distance.
  • Step 4: Ensure units match. Convert km/h ↔ m/s when time is required in seconds.
  • Step 5: Time = Distance ÷ Relative speed. If needed, convert the answer into minutes/seconds for clarity.

Summary

Summary

  • Identify whether the situation is meeting or overtaking to choose the correct relative speed formula.
  • Always compute relative speed by adding (meeting) or subtracting (overtaking).
  • Use the correct distance - initial separation, object length, or combined lengths - before applying the formula.
  • Maintain consistent units (km/h ↔ m/s) and convert time to minutes or seconds when required.

Example to remember:
“Meeting → add speeds, Overtaking → subtract speeds, then Time = Distance ÷ Relative Speed.”

Practice

(1/5)
1. Two cars start from opposite points 200 km apart and move towards each other at speeds of 60 km/h and 40 km/h. How long will they take to meet?
easy
A. 2 hours
B. 2.5 hours
C. 3 hours
D. 4 hours

Solution

  1. Step 1: Identify the Case

    They are moving towards each other → meeting problem.
  2. Step 2: Compute Relative Speed

    Relative speed = 60 + 40 = 100 km/h.
  3. Step 3: Compute Time

    Time = Distance ÷ Relative speed = 200 ÷ 100 = 2 hours.
  4. Final Answer:

    They will meet in 2 hours → Option A.
  5. Quick Check:

    60×2 + 40×2 = 120 + 80 = 200 ✅
Hint: Meeting → Add speeds to get relative speed.
Common Mistakes: Subtracting speeds instead of adding for opposite directions.
2. Two runners start from the same point in the same direction. The first runs at 8 km/h and the second at 10 km/h. How long will it take for the faster runner to be 2 km ahead?
easy
A. 0.5 hours
B. 1 hour
C. 1.5 hours
D. 2 hours

Solution

  1. Step 1: Identify the Case

    Same direction → overtaking type (faster gains on slower).
  2. Step 2: Compute Relative Speed

    Relative speed = 10 - 8 = 2 km/h.
  3. Step 3: Compute Time

    Time = Distance ÷ Relative speed = 2 ÷ 2 = 1 hour.
  4. Final Answer:

    The faster runner will be 2 km ahead in 1 hour → Option B.
  5. Quick Check:

    In 1 h: faster = 10 km, slower = 8 km → gap = 2 km ✅
Hint: Same direction → Subtract speeds (faster - slower).
Common Mistakes: Adding speeds instead of subtracting for overtaking cases.
3. Two trains, each 100 m long, run on parallel tracks in opposite directions at 54 km/h and 36 km/h. How long will they take to cross each other completely?
easy
A. 6 s
B. 7 s
C. 8 s
D. 9 s

Solution

  1. Step 1: Convert Speeds to m/s

    54×5/18 = 15 m/s; 36×5/18 = 10 m/s.
  2. Step 2: Relative Speed

    Opposite directions → add speeds: 15 + 10 = 25 m/s.
  3. Step 3: Distance to Cover

    Total distance = 100 + 100 = 200 m. Time = 200 ÷ 25 = 8 s.
  4. Final Answer:

    They cross each other in 8 seconds → Option C.
  5. Quick Check:

    25 × 8 = 200 m ✅
Hint: Opposite direction → Add speeds, convert to m/s when lengths are in metres.
Common Mistakes: Using difference of speeds for opposite-direction crossing.
4. A train 180 m long travels at 54 km/h and overtakes another train 120 m long running at 36 km/h in the same direction. Find the time to overtake completely.
medium
A. 20 s
B. 30 s
C. 40 s
D. 60 s

Solution

  1. Step 1: Convert Speeds to m/s

    54×5/18 = 15 m/s; 36×5/18 = 10 m/s.
  2. Step 2: Relative Speed

    Same direction → relative speed = 15 - 10 = 5 m/s.
  3. Step 3: Distance to Cover

    Distance = 180 + 120 = 300 m (faster must cover both lengths to pass completely).
  4. Step 4: Compute Time

    Time = 300 ÷ 5 = 60 s.
  5. Final Answer:

    They overtake in 60 seconds → Option D.
  6. Quick Check:

    5 × 60 = 300 m ✅
Hint: Same direction overtaking → subtract speeds (in m/s) and add lengths.
Common Mistakes: Forgetting to convert units or to add both train lengths.
5. Two cyclists start 60 km apart and travel towards each other at 15 km/h and 25 km/h. After how much time will they meet?
medium
A. 1.5 hours
B. 2 hours
C. 2.5 hours
D. 3 hours

Solution

  1. Step 1: Identify the Case

    They move towards each other → meeting problem.
  2. Step 2: Compute Relative Speed

    Relative speed = 15 + 25 = 40 km/h.
  3. Step 3: Compute Time

    Time = Distance ÷ Relative speed = 60 ÷ 40 = 1.5 hours.
  4. Final Answer:

    They will meet in 1.5 hours → Option A.
  5. Quick Check:

    15×1.5 + 25×1.5 = 22.5 + 37.5 = 60 ✅
Hint: Meeting → Add speeds then divide the separation by total speed.
Common Mistakes: Subtracting speeds when objects move toward each other.

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