Zero-order hold in Simulink - Time & Space Complexity
We want to understand how the time needed to run a zero-order hold block changes as the input size grows.
How does the block's processing time grow when the input signal length increases?
Analyze the time complexity of the following Simulink zero-order hold block behavior.
% Zero-order hold block behavior in Simulink
last_sample_index = 1;
for k = 1 : length(input_signal)
output_signal(k) = input_signal(last_sample_index);
if mod(k, sample_time) == 0
last_sample_index = k;
end
end
This code holds the last sampled input value constant until the next sample time, producing the output signal.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Looping through each element of the input signal to assign output values.
- How many times: Once for every element in the input signal (n times).
As the input signal length grows, the number of operations grows directly with it.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 10 |
| 100 | 100 |
| 1000 | 1000 |
Pattern observation: The operations increase in a straight line as input size increases.
Time Complexity: O(n)
This means the time to process grows directly in proportion to the input size.
[X] Wrong: "The zero-order hold processes all samples instantly regardless of input size."
[OK] Correct: Even though it holds values constant, it still needs to process each input element once, so time grows with input length.
Understanding how simple blocks like zero-order hold scale helps you reason about system performance and efficiency in real projects.
"What if the zero-order hold sampled at twice the rate? How would the time complexity change?"
Practice
What is the main function of a Zero-order hold block in Simulink?
Solution
Step 1: Understand the role of Zero-order hold and compare options
The Zero-order hold block keeps the input value constant during the sample period. It does not differentiate, integrate, or convert continuous to discrete signals.Final Answer:
It holds the input value constant between sample times. -> Option DQuick Check:
Zero-order hold = hold input constant [OK]
- Confusing zero-order hold with differentiation or integration
- Thinking it converts continuous to discrete signals
- Assuming it changes the signal value continuously
Which of the following is the correct way to set the fixed sample time parameter in a Zero-order hold block in Simulink?
Solution
Step 1: Understand sample time settings and evaluate options
Fixed sample time must be a positive number (e.g., 0.1s) to specify hold duration. -1 inherits from input; 0 means continuous (no hold); other negatives invalid.Final Answer:
Set sample time to a positive number like 0.1 seconds. -> Option AQuick Check:
Sample time positive number = correct setting [OK]
- Using zero or negative sample times incorrectly
- Confusing inherited sample time (-1) with explicit sample time
- Setting sample time to continuous (0) for discrete hold
Consider this Simulink model snippet using a Zero-order hold block with sample time 0.5 seconds. The input signal is a step that changes from 0 to 1 at time 0.3 seconds. What will be the output of the Zero-order hold block at time 0.7 seconds?
Solution
Step 1: Analyze sample intervals and input timing
With sample time 0.5s, samples at 0, 0.5, 1.0s. Step changes at 0.3s, so input(0)=0, input(0.5)=1. At 0.7s (in [0.5,1.0)), holds 1.Final Answer:
1 -> Option CQuick Check:
Output holds last sampled input = 1 [OK]
- Thinking sample at 0.5s captures 0 despite change at 0.3s
- Ignoring sample time intervals
- Confusing step change time with sample time
In a Simulink model, a Zero-order hold block is set with sample time 0.2 seconds. The output signal is not holding values as expected and changes continuously. What is the most likely cause?
Solution
Step 1: Identify cause of continuous output behavior
If sample time=0, block operates continuously (follows input without holding). Other causes less likely to produce continuous change.Final Answer:
Sample time is set to 0 (continuous) instead of 0.2. -> Option AQuick Check:
Continuous sample time = no hold [OK]
- Ignoring sample time setting
- Assuming input signal type causes issue
- Misconnecting blocks without checking parameters
You want to convert a discrete sensor signal sampled every 0.1 seconds into a continuous signal for further processing in Simulink. Which approach using a Zero-order hold block is correct?
Choose the best option.
Solution
Step 1: Understand goal and evaluate ZOH configurations
Goal: hold discrete samples constant between 0.1s intervals for continuous output. Set Ts=0.1s matches sensor rate. Ts=0 continuous (no hold); -1 inherits (risk mismatch); integrator changes values.Final Answer:
Set the Zero-order hold sample time to 0.1 seconds to hold each sample value constant until the next sample. -> Option BQuick Check:
Sample time = sensor rate for correct hold [OK]
- Setting sample time to zero for hold
- Using inherited sample time without checking input
- Replacing hold with integrator incorrectly
Ready to prove it?
Pass the test and this pattern moves unknown
