State machine in ladder logic in PLC Programming - Time & Space Complexity
We want to understand how the time it takes to run a state machine in ladder logic changes as the number of states grows.
Specifically, we ask: How does the program's execution time grow when we add more states?
Analyze the time complexity of the following code snippet.
// Ladder logic style pseudocode for state machine
// States: IDLE, RUN, STOP
// Transitions based on inputs
IF current_state == IDLE THEN
IF start_button_pressed THEN
current_state := RUN
END_IF
ELSIF current_state == RUN THEN
IF stop_button_pressed THEN
current_state := STOP
END_IF
ELSIF current_state == STOP THEN
IF reset_button_pressed THEN
current_state := IDLE
END_IF
END_IF
This code checks the current state and input buttons to decide the next state.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Checking each state condition once per scan cycle.
- How many times: Once per scan cycle; no loops inside the state checks.
As the number of states increases, the program checks more conditions each scan.
| Input Size (number of states) | Approx. Operations (state checks) |
|---|---|
| 3 | 3 checks |
| 10 | 10 checks |
| 100 | 100 checks |
Pattern observation: The number of checks grows directly with the number of states.
Time Complexity: O(n)
This means the time to run the state machine grows linearly as you add more states.
[X] Wrong: "The state machine runs in constant time no matter how many states there are."
[OK] Correct: Each state condition is checked every scan, so more states mean more checks and more time.
Understanding how state machines scale helps you design efficient control programs and shows you can think about program performance clearly.
"What if the state machine used a jump table or direct indexing instead of checking each state condition? How would the time complexity change?"
Practice
Solution
Step 1: Understand state machine concept
A state machine controls a process by remembering the current step or state and moving to the next based on conditions.Step 2: Compare options to concept
Only To control a process by remembering and switching between states describes controlling process flow by switching states, which matches the state machine purpose.Final Answer:
To control a process by remembering and switching between states -> Option AQuick Check:
State machine controls steps = D [OK]
- Confusing state machine with data storage
- Thinking it only does math
- Assuming it controls display only
Solution
Step 1: Identify state representation in ladder logic
States are usually represented by bits or coils that can be ON or OFF to show current state.Step 2: Eliminate other options
Timers and counters are for timing/counting, analog inputs read values, so only bits/coils represent states.Final Answer:
Bit or coil -> Option BQuick Check:
States use bits/coils = C [OK]
- Choosing timers or counters as states
- Confusing analog inputs with states
- Not knowing bits represent ON/OFF
--[ State1 ]--+--[ Condition ]--( State2 )
|
+--( Reset State1 )What happens when
Condition is TRUE?Solution
Step 1: Analyze ladder logic behavior on Condition TRUE
When Condition is TRUE, the coil for State2 energizes and the Reset coil for State1 de-energizes State1.Step 2: Understand state transition
This means State1 turns OFF and State2 turns ON, moving the machine to the next state.Final Answer:
State1 turns OFF and State2 turns ON -> Option DQuick Check:
Condition TRUE switches states = A [OK]
- Thinking both states turn ON simultaneously
- Assuming no change happens
- Confusing which state resets
--[ State1 ]--+--[ Condition ]--( State2 )
+--( State1 )Why does the state machine never leave State1?
Solution
Step 1: Check how State1 coil is controlled
State1 coil is energized again on the same rung without a reset coil, so it stays ON continuously.Step 2: Understand why state never changes
Without turning OFF State1, the machine cannot move to State2 even if Condition is TRUE.Final Answer:
Because State1 coil is never reset, so it stays ON -> Option AQuick Check:
No reset keeps state ON = B [OK]
- Ignoring need to reset current state
- Assuming Condition is always FALSE
- Thinking missing coil causes lock
Solution
Step 1: Understand state machine design
A proper state machine uses separate bits for each state and transitions that turn OFF the current state bit and ON the next state bit.Step 2: Evaluate options for correct implementation
Use bits for each state; each transition resets current state bit and sets next state bit based on conditions matches this approach; the other options do not correctly represent state transitions in ladder logic.Final Answer:
Use bits for each state; each transition resets current state bit and sets next state bit based on conditions -> Option CQuick Check:
Separate bits with reset/set transitions = A [OK]
- Using one bit for all states
- Relying only on timers or counters
- Not resetting current state bit
Ready to prove it?
Pass the test and this pattern moves unknown
