PCB Design - Design Review and Testing
Given a PCB with 3 scan chains of lengths 10, 15, and 20, what is the total number of flip-flops tested if each chain tests one flip-flop per stage?
Given a PCB with 3 scan chains of lengths 10, 15, and 20, what is the total number of flip-flops tested if each chain tests one flip-flop per stage?
medium📝 Formula Result Q4 of 15
Step-by-Step Solution
Solution:
Step 1: Sum the lengths of all scan chains
10 + 15 + 20 = 45 flip-flops total.Step 2: Confirm each stage tests one flip-flop
Each stage corresponds to one flip-flop, so total is sum.Final Answer:
45 flip-flops -> Option AQuick Check:
Total flip-flops = 45 [OK]
Quick Trick: Add all chain lengths for total flip-flops tested [OK]
Common Mistakes:
MISTAKES- Choosing only the longest chain
- Adding incorrectly
- Confusing flip-flops with pins
Master "Design Review and Testing" in PCB Design
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore PCB Design Quizzes