Stack operations (PUSH, POP) in ARM Architecture - Mini Project: Build & Apply

Stack operations (PUSH, POP)

📖 Scenario: You are learning how a computer's processor uses a stack to manage data temporarily. The stack is like a pile of plates where you can only add or remove the top plate. In ARM assembly language, PUSH adds data to the stack, and POP removes data from the stack.Imagine you want to save two numbers on the stack and then retrieve them back in the correct order.

🎯 Goal: Build a simple ARM assembly code snippet that PUSHes two registers onto the stack and then POPs them back into registers, demonstrating how stack operations work.

📋 What You'll Learn

Create two registers with initial values

Use the PUSH instruction to save these registers on the stack

Use the POP instruction to retrieve the values back into registers

Ensure the order of values is preserved after POP

💡 Why This Matters

🌍 Real World

Stack operations are fundamental in managing temporary data during program execution, especially in function calls and interrupt handling.

💼 Career

Understanding stack operations is essential for embedded systems programming, low-level debugging, and performance optimization in software development.

1

Set up registers with initial values

Write ARM assembly code to load the value 10 into register r0 and the value 20 into register r1.

ARM Architecture

# Load 10 into r0 and 20 into r1
# Your code here

Hint

Use the MOV instruction to set values in registers.

2

Push registers onto the stack

Add ARM assembly code to PUSH the registers r0 and r1 onto the stack.

ARM Architecture

MOV r0, #10
MOV r1, #20
# Push r0 and r1 onto the stack
# Your code here

Hint

Use PUSH {r0, r1} to save both registers at once.

3

Pop registers from the stack

Write ARM assembly code to POP the values back from the stack into registers r2 and r3.

ARM Architecture

MOV r0, #10
MOV r1, #20
PUSH {r0, r1}
# Pop values into r2 and r3
# Your code here

Hint

Use POP {r3, r2} to retrieve the values in the same order.

4

Complete the stack operation example

Add a comment explaining that r3 now holds 20 and r2 holds 10, showing the LIFO order of the stack.

ARM Architecture

MOV r0, #10
MOV r1, #20
PUSH {r0, r1}
POP {r3, r2}
// Your comment here

Hint

Explain the order in which values come off the stack.

Practice

1. What does the PUSH instruction do in ARM architecture stack operations?

easy

A. It adds registers to the stack by decreasing the stack pointer.

B. It removes registers from the stack by increasing the stack pointer.

C. It clears the stack completely.

D. It duplicates the top value of the stack.

Solution

1. Step 1: Understand the role of PUSH

   PUSH adds data to the stack, which means it stores registers by moving the stack pointer downwards.

2. Step 2: Compare with POP

   POP removes data by moving the stack pointer upwards, opposite to PUSH.

3. Final Answer:

   It adds registers to the stack by decreasing the stack pointer. -> Option A

4. Quick Check:

   PUSH = add to stack [OK]

Hint: PUSH means add data, stack pointer moves down [OK]

Common Mistakes:

• Confusing PUSH with POP
• Thinking PUSH increases stack pointer
• Assuming PUSH clears the stack

2. Which of the following is the correct syntax to push registers R0 and R1 onto the stack in ARM assembly?

easy

A. PUSH [R0, R1]

B. PUSH (R0, R1)

C. PUSH {R0, R1}

D. PUSH R0 R1

Solution

1. Step 1: Recall ARM PUSH syntax

   ARM uses curly braces to list registers for PUSH, like PUSH {R0, R1}.

2. Step 2: Identify incorrect syntax

   Parentheses, spaces without braces, or square brackets are not valid for PUSH in ARM.

3. Final Answer:

   PUSH {R0, R1} -> Option C

4. Quick Check:

   Curly braces list registers in PUSH [OK]

Hint: Use curly braces {} to list registers in PUSH [OK]

Common Mistakes:

• Using parentheses instead of braces
• Listing registers without any brackets
• Using square brackets which are invalid

3. Given the following ARM instructions:
SUB SP, SP, #8
PUSH {R4, R5}
POP {R6, R7}
What happens to the stack pointer (SP) after these operations?

medium

A. SP decreases by 8, then decreases by 8, then increases by 8

B. SP decreases by 8, then increases by 8, then decreases by 8

C. SP decreases by 8, then decreases by 8, then increases by 16

D. SP decreases by 8, then decreases again by 8, then increases by 8

Solution

1. Step 1: Analyze SUB SP, SP, #8

   This subtracts 8 from SP, moving it down by 8 bytes.

2. Step 2: Understand PUSH {R4, R5}

   PUSH stores two registers, so SP decreases by another 8 bytes (4 bytes each register).

3. Step 3: Understand POP {R6, R7}

   POP removes two registers, so SP increases by 8 bytes.

4. Final Answer:

   SP decreases by 8, then decreases by 8, then increases by 8 -> Option A

5. Quick Check:

   SP moves down for SUB and PUSH, up for POP [OK]

Hint: PUSH decreases SP, POP increases SP by register size times count [OK]

Common Mistakes:

• Forgetting SUB changes SP before PUSH
• Assuming POP decreases SP
• Miscounting bytes per register

4. Identify the error in this ARM assembly snippet:
PUSH R0, R1
POP {R2, R3}

medium

A. PUSH cannot push more than one register at a time.

B. PUSH syntax is incorrect; registers must be in braces.

C. POP syntax is incorrect; registers must be in parentheses.

D. POP cannot pop into different registers.

Solution

1. Step 1: Check PUSH syntax

   PUSH requires registers to be enclosed in curly braces, so PUSH R0, R1 is invalid.

2. Step 2: Check POP syntax

   POP syntax with curly braces is correct, so POP {R2, R3} is valid.

3. Final Answer:

   PUSH syntax is incorrect; registers must be in braces. -> Option B

4. Quick Check:

   PUSH needs braces { } [OK]

Hint: Always use braces {} for multiple registers in PUSH/POP [OK]

Common Mistakes:

• Using commas without braces in PUSH
• Confusing parentheses with braces
• Thinking POP cannot pop multiple registers

5. You want to save registers R0, R1, and R2 on the stack, then restore them later. Which sequence correctly uses PUSH and POP to do this without corrupting the stack?

hard

A. PUSH {R2, R1, R0}...POP {R0, R1, R2}

B. PUSH {R0, R1, R2}...POP {R0, R1, R2}

C. PUSH {R0, R1, R2}...POP {R1, R2, R0}

D. PUSH {R0, R1, R2}...POP {R2, R1, R0}

Solution

1. Step 1: Understand stack order with PUSH

   PUSH stores registers in order: R0, then R1, then R2, with R2 at the lowest address.

2. Step 2: POP must restore in reverse order

   POP restores registers in reverse order of PUSH to correctly restore the original values.

3. Step 3: Check options

   PUSH {R0, R1, R2}
   ...
   POP {R2, R1, R0} pops in reverse order as pushed, preserving correct values.

4. Final Answer:

   PUSH {R0, R1, R2} ... POP {R2, R1, R0} -> Option D

5. Quick Check:

   POP order is reverse of PUSH order to restore correctly [OK]

Hint: POP registers in reverse order of PUSH to restore correctly [OK]

Common Mistakes:

• Reversing POP order incorrectly
• Changing register order between PUSH and POP
• Assuming POP order does not matter