Signed and unsigned integers in ARM Architecture - Mini Project: Build & Apply
signed_val and unsigned_val. Set signed_val to -10 and unsigned_val to 250. Use 8-bit integer notation.Use .byte to define 8-bit integers. Signed values can be negative; unsigned values are positive.
max_unsigned_8bit and set it to the maximum value for an unsigned 8-bit integer, which is 255.The maximum value for unsigned 8-bit integers is 255 because 8 bits can represent 28 = 256 values starting from 0.
signed_val explaining that signed 8-bit integers range from -128 to 127.Comments start with # in ARM assembly.
Summarize the key difference between signed and unsigned integers in a comment.
Practice
What is the main difference between signed and unsigned integers in ARM architecture?
Solution
Step 1: Understand signed integers
Signed integers use two's complement to represent both negative and positive numbers.Step 2: Understand unsigned integers
Unsigned integers represent only zero and positive numbers, allowing a larger positive range.Final Answer:
Signed integers can represent negative and positive numbers, unsigned only non-negative. -> Option BQuick Check:
Signed = negative and positive, Unsigned = only positive [OK]
- Thinking unsigned can represent negative numbers
- Assuming signed uses more memory
- Believing signed is always faster
Which of the following is the correct way to declare an unsigned 8-bit integer in ARM assembly?
Solution
Step 1: Understand unsigned 8-bit range
Unsigned 8-bit integers range from 0 to 255, so 255 is valid.Step 2: Check instructions
mov r0, #255moves the immediate value 255 into register r0 correctly.Final Answer:
mov r0, #255(assuming r0 is unsigned 8-bit) -> Option AQuick Check:
Unsigned 8-bit max = 255, mov loads immediate [OK]
- Using movs which sets flags unnecessarily
- Trying to move negative values to unsigned
- Using values above 255 for 8-bit
Consider a 4-bit signed integer using two's complement. What decimal value does the binary 1101 represent?
Solution
Step 1: Identify two's complement sign
In 4-bit two's complement, if the leftmost bit is 1, the number is negative.Step 2: Calculate decimal value
Binary 1101: invert bits -> 0010, add 1 -> 0011 (3 decimal), so value is -3. But careful: 1101 is -3 or -5? Let's check carefully:
1101 binary = (1x-8) + (1x4) + (0x2) + (1x1) = -8 + 4 + 0 + 1 = -3Final Answer:
-3 -> Option AQuick Check:
Two's complement 1101 = -3 decimal [OK]
- Treating binary as unsigned
- Forgetting two's complement negative calculation
- Mixing bit positions
In ARM assembly, a programmer tries to store the value -1 in an unsigned 8-bit register. What is the likely result?
Solution
Step 1: Understand unsigned storage
Unsigned 8-bit registers store values 0 to 255. Negative values wrap around using modulo 256.Step 2: Calculate wrap-around for -1
-1 modulo 256 equals 255, so the register stores 255.Final Answer:
The register stores 255 due to wrap-around. -> Option DQuick Check:
Unsigned wrap-around: -1 = 255 [OK]
- Expecting syntax error for negative immediate
- Assuming register stores zero
- Thinking program crashes
You have a 16-bit unsigned integer register holding the value 65535. You subtract 1 from it. What is the result stored in the register?
Solution
Step 1: Understand 16-bit unsigned range
16-bit unsigned integers range from 0 to 65535.Step 2: Perform subtraction
65535 - 1 = 65534, which fits in 16 bits without wrap-around.Final Answer:
65534 -> Option CQuick Check:
65535 - 1 = 65534 within unsigned 16-bit [OK]
- Thinking result becomes negative
- Assuming overflow to zero
- Confusing unsigned with signed behavior
Ready to prove it?
Pass the test and this pattern moves unknown
