tone() function for frequency generation in Arduino - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to play a 440 Hz tone on pin 8.

Arduino

tone(8, [1]);

Drag options to blanks, or click blank then click option'

AdigitalWrite

BpinMode

C440

Ddelay

Attempts:

3 left

💡 Hint

Common Mistakes

Using a function name instead of a frequency number.

Confusing pin number with frequency.

The tone() function needs the pin number and the frequency in hertz. 440 Hz is the frequency for the A note.

2fill in blank

medium

Complete the code to stop the tone on pin 8.

Arduino

tone([1], 440);
// some delay here
noTone([1]);

Drag options to blanks, or click blank then click option'

A9

B7

C10

D8

Attempts:

3 left

💡 Hint

Common Mistakes

Using different pin numbers for tone() and noTone().

Using a pin number that is not connected.

The noTone() function stops the tone on the same pin where tone() was called. Here, pin 8 is used.

3fill in blank

hard

Fix the error in the code to play a 1000 Hz tone for 500 milliseconds on pin 6.

Arduino

tone(6, [1], 500);

Drag options to blanks, or click blank then click option'

Adelay

B1000

Ctone

DpinMode

Attempts:

3 left

💡 Hint

Common Mistakes

Using function names instead of frequency numbers.

Omitting the frequency argument.

The second argument of tone() is the frequency in hertz. 1000 Hz is the correct frequency to play.

4fill in blank

hard

Fill both blanks to play a 523 Hz tone on pin 5 for 1000 milliseconds.

Arduino

tone([1], [2], 1000);

Drag options to blanks, or click blank then click option'

A5

B523

C8

D440

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up pin number and frequency.

Using wrong frequency values.

The first blank is the pin number 5, and the second blank is the frequency 523 Hz (note C5).

5fill in blank

hard

Fill all three blanks to create a dictionary of notes with their frequencies and play the tone for 300 ms on pin 3 for the note 'E'.

Arduino

const int notes[] = { [1] };
int freq = notes[[2]];
tone(3, [3], 300);

Drag options to blanks, or click blank then click option'

A262, 294, 330

B2

Cfreq

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong index for the note.

Passing the frequency number directly instead of the variable.

The array contains frequencies for notes C, D, E (262, 294, 330). Index 2 is the third note 'E'. The variable freq holds the frequency to play.

Practice

1. What does the tone() function do in Arduino?

easy

A. Generates a sound of a specific frequency on a pin

B. Reads the voltage from a sensor

C. Turns on an LED

D. Sends data over serial communication

Solution

1. Step 1: Understand the purpose of tone()

   The tone() function is used to create sound by generating a square wave of a specific frequency on a pin.

2. Step 2: Compare options with function behavior

   Only Generates a sound of a specific frequency on a pin describes generating sound with frequency, which matches tone() usage.

3. Final Answer:

   Generates a sound of a specific frequency on a pin -> Option A

4. Quick Check:

   tone() = sound frequency generation [OK]

Hint: Remember: tone() makes sound, not reads or sends data [OK]

Common Mistakes:

• Confusing tone() with digitalWrite()
• Thinking tone() reads sensor data
• Assuming tone() controls LEDs

2. Which of the following is the correct syntax to play a 1000 Hz tone on pin 8 for 500 milliseconds?

easy

A. tone(8, 1000, 500);

B. tone(1000, 8, 500);

C. tone(8, 500, 1000);

D. tone(8, 1000); delay(500);

Solution

1. Step 1: Recall tone() function parameters

   The correct order is tone(pin, frequency, duration). So pin 8, frequency 1000 Hz, duration 500 ms means tone(8, 1000, 500);.

2. Step 2: Check each option

   tone(8, 1000, 500); matches the correct order. tone(1000, 8, 500); swaps pin and frequency. tone(8, 500, 1000); swaps frequency and duration. tone(8, 1000); delay(500); starts continuous tone but does not stop after 500 ms, unlike duration parameter.

3. Final Answer:

   tone(8, 1000, 500); -> Option A

4. Quick Check:

   tone(pin, freq, duration) = tone(8, 1000, 500) [OK]

Hint: Remember parameter order: pin, frequency, duration [OK]

Common Mistakes:

• Swapping frequency and pin parameters
• Confusing duration with frequency
• Omitting duration when required

3. What will be the output behavior of this Arduino code snippet?

void setup() {
  tone(9, 440, 1000);
  delay(1500);
  noTone(9);
}
void loop() {}

medium

A. Pin 9 outputs a 440 Hz tone for 1.5 seconds, then stops

B. Pin 9 outputs a 440 Hz tone continuously without stopping

C. Pin 9 outputs a 440 Hz tone for 1 second, then stops

D. No sound is produced because noTone() is called immediately

Solution

1. Step 1: Analyze tone() with duration

   The tone(9, 440, 1000); plays a 440 Hz tone on pin 9 for 1000 milliseconds (1 second).

2. Step 2: Understand delay and noTone()

   The program waits 1500 ms, which is longer than the tone duration, so the tone stops automatically after 1 second. Then noTone(9); stops any tone if still playing (safe call).

3. Final Answer:

   Pin 9 outputs a 440 Hz tone for 1 second, then stops -> Option C

4. Quick Check:

   tone(9, 440, 1000) plays 1s tone [OK]

Hint: Duration in tone() controls length; noTone() stops early [OK]

Common Mistakes:

• Thinking tone plays for delay length
• Assuming noTone() stops tone immediately before playing
• Confusing tone duration with delay time

4. Identify the error in this code snippet that tries to play a 500 Hz tone on pin 7:

void setup() {
  tone(7, 500);
  delay(3000);
  noTone(7);
}
void loop() {
  tone(7, 500, 1000);
}

medium

A. tone() requires frequency before pin number

B. Calling tone() inside loop() with duration causes overlapping tones

C. noTone() should be called before tone() in setup()

D. delay() cannot be used with tone()

Solution

1. Step 1: Review tone() usage in loop()

   Calling tone(7, 500, 1000); repeatedly in loop() will restart the tone every cycle, causing overlapping or interrupted sounds.

2. Step 2: Check other options

   noTone() can be called after tone(), tone() parameters order is correct, and delay() can be used with tone(). So only Calling tone() inside loop() with duration causes overlapping tones describes the real problem.

3. Final Answer:

   Calling tone() inside loop() with duration causes overlapping tones -> Option B

4. Quick Check:

   Repeated tone() with duration in loop causes overlap [OK]

Hint: Avoid tone() with duration inside loop() to prevent overlap [OK]

Common Mistakes:

• Calling noTone() before tone() unnecessarily
• Mixing parameter order in tone()
• Thinking delay() blocks tone() sound

5. You want to play a melody using tone() on pin 6 with these notes and durations: 262 Hz for 500 ms, 294 Hz for 500 ms, and 330 Hz for 1000 ms. Which code correctly plays this sequence without overlapping tones?

hard

A. void setup() {
tone(6, 262, 500);
delay(1000);
tone(6, 294, 500);
delay(1000);
tone(6, 330, 1000);
delay(1000);
}
void loop() {}

B. void setup() {
tone(6, 262);
delay(500);
tone(6, 294);
delay(500);
tone(6, 330);
delay(1000);
}
void loop() {}

C. void setup() {
tone(6, 262, 500);
tone(6, 294, 500);
tone(6, 330, 1000);
}
void loop() {}

D. void setup() {
tone(6, 262, 500);
delay(500);
tone(6, 294, 500);
delay(500);
tone(6, 330, 1000);
delay(1000);
}
void loop() {}

Solution

1. Step 1: Understand tone() with duration and delay

   Using tone(pin, freq, duration) plays the note for the duration. To avoid overlap, delay should match the tone duration before playing the next note.

2. Step 2: Evaluate each option

   void setup() { tone(6, 262, 500); delay(500); tone(6, 294, 500); delay(500); tone(6, 330, 1000); delay(1000); } void loop() {} plays each tone with correct duration and delays matching durations, so notes play sequentially without overlap. void setup() { tone(6, 262); delay(500); tone(6, 294); delay(500); tone(6, 330); delay(1000); } void loop() {} omits duration in tone(), causing continuous tones. void setup() { tone(6, 262, 500); tone(6, 294, 500); tone(6, 330, 1000); } void loop() {} calls tone() three times without delay, overlapping sounds. void setup() { tone(6, 262, 500); delay(1000); tone(6, 294, 500); delay(1000); tone(6, 330, 1000); delay(1000); } void loop() {} uses delays longer than tone durations, causing unwanted silence.

3. Final Answer:

   tone(6, 262, 500); delay(500); tone(6, 294, 500); delay(500); tone(6, 330, 1000); delay(1000); -> Option D

4. Quick Check:

   Match delay to tone duration for clean melody [OK]

Hint: Use delay equal to tone duration to separate notes [OK]

Common Mistakes:

• Omitting delay after tone() with duration
• Calling multiple tone() without delay causing overlap
• Using longer delays causing silence gaps