Why AI makes games challenging in Unity - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to make the AI move towards the player.

Unity

Vector3 direction = player.position - [1].position;

Drag options to blanks, or click blank then click option'

Atransform

Bplayer

Ctarget

Denemy

Attempts:

3 left

💡 Hint

Common Mistakes

Using player.position twice instead of AI's position.

Using an undefined variable instead of transform.

The AI uses its own transform.position to calculate direction towards the player.

2fill in blank

medium

Complete the code to make the AI rotate smoothly towards the player.

Unity

transform.rotation = Quaternion.Slerp(transform.rotation, Quaternion.LookRotation(direction), [1] * Time.deltaTime);

Drag options to blanks, or click blank then click option'

Adistance

Bangle

Cspeed

Dhealth

Attempts:

3 left

💡 Hint

Common Mistakes

Using distance instead of speed for rotation.

Forgetting to multiply by Time.deltaTime.

The speed variable controls how fast the AI rotates towards the player.

3fill in blank

hard

Fix the error in the code that makes the AI chase the player only if within range.

Unity

if (Vector3.Distance(transform.position, player.position) [1] chaseRange) {
    ChasePlayer();
}

Drag options to blanks, or click blank then click option'

A<=

B!=

C==

D>=

Attempts:

3 left

💡 Hint

Common Mistakes

Using > instead of <= causes chasing when too far.

Using == is too strict and rarely true.

The AI should chase the player only if the distance is less than or equal to the chase range.

4fill in blank

hard

Fill both blanks to create a dictionary of enemy names and their health if health is above 0.

Unity

var aliveEnemies = new Dictionary<string, int> { { [1], [2] } };

Drag options to blanks, or click blank then click option'

A"Goblin"

B100

C"Orc"

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 as health includes dead enemies.

Using non-string keys causes errors.

The dictionary key is the enemy name as a string, and the value is the health as an integer.

5fill in blank

hard

Fill all three blanks to filter enemies with health above 50 and create a dictionary with their names and health.

Unity

var strongEnemies = enemies.Where(e => e.Value [1] [2]).ToDictionary(e => e.Key, e => e.Value [3] 10);

Drag options to blanks, or click blank then click option'

A>

B50

C+

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using < instead of > filters wrong enemies.

Forgetting to add 10 to health.

The code filters enemies with health greater than 50 and adds 10 to their health in the new dictionary.