Scene transitions in Unity - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to load a scene named "GameScene" using Unity's SceneManager.

Unity

SceneManager.[1]("GameScene");

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ALoadScene

BUnloadScene

CActivateScene

DStartScene

Attempts:

3 left

💡 Hint

Common Mistakes

Using UnloadScene instead of LoadScene.

Trying to use StartScene which does not exist.

The LoadScene method of SceneManager loads a new scene by name or index.

2fill in blank

medium

Complete the code to add the UnityEngine.SceneManagement namespace needed for scene transitions.

Unity

using [1];

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AUnityEngine.SceneManagement

BUnityEngine.Audio

CUnityEngine.UI

DUnityEngine.Physics

Attempts:

3 left

💡 Hint

Common Mistakes

Using unrelated namespaces like UI or Audio.

Forgetting to add the namespace and getting errors.

The SceneManager class is inside the UnityEngine.SceneManagement namespace.

3fill in blank

hard

Fix the error in the code to load a scene asynchronously named "Level1".

Unity

SceneManager.[1]("Level1");

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ALoadLevel

BLoadScene

CLoadAsyncScene

DLoadSceneAsync

Attempts:

3 left

💡 Hint

Common Mistakes

Using LoadScene which loads synchronously.

Using non-existent methods like LoadLevel.

The correct method to load a scene asynchronously is LoadSceneAsync.

4fill in blank

hard

Fill both blanks to check if the current active scene's name is "Menu".

Unity

if (SceneManager.[1]().[2] == "Menu") {
    // do something
}

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AGetActiveScene

Bname

CsceneName

DGetSceneByName

Attempts:

3 left

💡 Hint

Common Mistakes

Using GetSceneByName which requires a parameter.

Using sceneName which is not a valid property.

GetActiveScene() returns the current scene, and name gets its name.

5fill in blank

hard

Fill all three blanks to create a dictionary mapping scene names to their build indexes for scenes with index less than 3.

Unity

var scenes = new Dictionary<string, int> {
    {"[1]", [2]
};

for (int i = 0; i < 5; i++) {
    var scene = SceneManager.GetSceneByBuildIndex(i);
    if (i [3] 3) {
        scenes[scene.name] = i;
    }
}

Drag options to blanks, or click blank then click option'

AIntro

B0

C<

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '<' in the condition.

Using the variable 'i' instead of the number '0' for the dictionary value.

The dictionary starts with a scene named "Intro" and its index 0. The condition checks if i < 3.