Solution:Step 1: Understand symmetricDifferenceSymmetric difference returns elements in either set but not in both.Step 2: Compare with other operationsUnion combines all elements, intersection finds common, subtracting removes elements of second from first.Final Answer:let result = setX.symmetricDi

[Solved] Given two sets:let setX: Set<Int> = [1, 2, 3, 4, 5]let setY: Set<Int> = [4, 5, 6, 7]Which Swift code correctly creates a new set containing elements in either setX or setY but not in both? | Swift

Swift - Collections

Given two sets:

let setX: Set<Int> = [1, 2, 3, 4, 5]
let setY: Set<Int> = [4, 5, 6, 7]

Which Swift code correctly creates a new set containing elements in either setX or setY but not in both?

Alet result = setX.symmetricDifference(setY)

Blet result = setX.union(setY)

Clet result = setX.intersection(setY)

Dlet result = setX.subtracting(setY)

Step-by-Step Solution

Solution:

Step 1: Understand symmetricDifference
Symmetric difference returns elements in either set but not in both.
Step 2: Compare with other operations
Union combines all elements, intersection finds common, subtracting removes elements of second from first.
Final Answer:
let result = setX.symmetricDifference(setY) -> Option A
Quick Check:
Symmetric difference = exclusive elements [OK]

Quick Trick: SymmetricDifference = items in one set only [OK]

Common Mistakes:

Using union instead of symmetricDifference
Confusing intersection with symmetricDifference
Using subtracting which is one-sided

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Given two sets:

Step 1: Understand symmetricDifference

Step 2: Compare with other operations

Final Answer:

Quick Check:

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