Which Swift code correctly uses if-else statements to print "Positive", "Negative", or "Zero" based on the value of an integer variable value?

hard📝 Application Q8 of 15

Swift - Control Flow

Which Swift code correctly uses if-else statements to print "Positive", "Negative", or "Zero" based on the value of an integer variable value?

Aif value == 0 { print("Zero") } else if value > 0 { print("Positive") } else { print("Negative") }

Bif value >= 0 { print("Positive") } else if value <= 0 { print("Negative") } else { print("Zero") }

Cif value > 0 { print("Positive") } else if value > 0 { print("Negative") } else { print("Zero") }

Dif value > 0 { print("Positive") } else if value < 0 { print("Negative") } else { print("Zero") }

Step-by-Step Solution

Solution:

Step 1: Understand conditions
Check if value is greater than 0, less than 0, or zero.
Step 2: Analyze options
if value > 0 { print("Positive") } else if value < 0 { print("Negative") } else { print("Zero") } correctly checks >0, <0, else zero.
Step 3: Identify errors in other options
if value >= 0 { print("Positive") } else if value <= 0 { print("Negative") } else { print("Zero") } uses overlapping conditions; C repeats same condition; D order is incorrect for logic.
Final Answer:
if value > 0 { print("Positive") } else if value < 0 { print("Negative") } else { print("Zero") } correctly implements the logic.
Quick Check:
Conditions cover all cases without overlap [OK]

Quick Trick: Check conditions cover all cases without overlap [OK]

Common Mistakes:

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