Sets help you store unique items without order. They make it easy to check if something is there or combine groups without repeats.
You want to keep a list of unique names without duplicates.
You need to find common items between two groups, like friends in both your and your friend's contact list.
You want to add or remove items quickly without caring about order.
You want to find items that are only in one group but not another.
You want to check if an item exists in a collection fast.
Syntax
Swift
var mySet: Set<Type> = [item1, item2, item3]
// Or create an empty setvar emptySet = Set<Type>()
Use Set<Type> to declare a set with a specific type.
Sets automatically remove duplicate items.
Examples
This creates a set of strings with three fruits.
Swift
var fruits: Set<String> = ["apple", "banana", "orange"]
This creates a set of integers. The duplicate 3 is stored only once.
Swift
var numbers = Set([1, 2, 3, 3, 4])
This creates an empty set of integers.
Swift
var emptySet = Set<Int>()
Sample Program
This program creates two sets of numbers and shows how to combine and compare them using set operations. The results are sorted before printing for easier reading.
Swift
import Foundation
var setA: Set<Int> = [1, 2, 3, 4]
var setB: Set<Int> = [3, 4, 5, 6]
// Union: all unique items from both setslet unionSet = setA.union(setB)
// Intersection: items common to both setslet intersectionSet = setA.intersection(setB)
// Subtracting: items in setA not in setBlet subtractSet = setA.subtracting(setB)
// Symmetric difference: items in either set but not bothlet symDiffSet = setA.symmetricDifference(setB)
print("Union: \(unionSet.sorted())")
print("Intersection: \(intersectionSet.sorted())")
print("Subtracting: \(subtractSet.sorted())")
print("Symmetric Difference: \(symDiffSet.sorted())")
OutputSuccess
Important Notes
Sets do not keep order, so items may appear in any order unless you sort them.
Use sorted() to display sets in order when printing.
Set operations like union, intersection, subtracting, and symmetricDifference help compare groups easily.
Summary
Sets store unique items without order.
You can create sets with Set<Type> and use brackets to list items.
Set operations help combine and compare sets quickly.
Practice
(1/5)
1. What is true about a Set in Swift?
easy
A. It can only store numbers, not strings.
B. It stores duplicate values in the order they were added.
C. It stores unique values without any specific order.
D. It always keeps elements sorted alphabetically.
Solution
Step 1: Understand Set properties
A Set in Swift stores unique values and does not keep any order.
Step 2: Compare options with Set behavior
It stores unique values without any specific order. matches the unique and unordered nature of Sets. Others describe arrays or sorted collections.
Final Answer:
It stores unique values without any specific order. -> Option C
Quick Check:
Set = unique + unordered [OK]
Hint: Remember: Sets never keep duplicates or order [OK]
Common Mistakes:
Thinking Sets keep order like arrays
Assuming Sets allow duplicates
Believing Sets only store numbers
2. Which of the following is the correct way to create a Set of integers in Swift?
easy
A. let numbers = {1, 2, 3, 4} as Set<Int>
B. let numbers: Set<Int> = [1, 2, 3, 4]
C. let numbers = Set(1, 2, 3, 4)
D. let numbers = [1, 2, 3, 4] as Set
Solution
Step 1: Recall Set creation syntax
In Swift, a Set can be created by specifying type and using square brackets with values.
Step 2: Check each option's syntax
let numbers: Set<Int> = [1, 2, 3, 4] uses correct syntax: Set<Int> = [1, 2, 3, 4]. Others have syntax errors or wrong casting.
Final Answer:
let numbers: Set<Int> = [1, 2, 3, 4] -> Option B
Quick Check:
Set creation = type + brackets [OK]
Hint: Use Set<Type> with brackets for values [OK]
Common Mistakes:
Using parentheses instead of brackets
Trying to cast arrays directly to Set without syntax
Missing type declaration when needed
3. What will be the output of this Swift code?
let setA: Set<Int> = [1, 2, 3, 4] let setB: Set<Int> = [3, 4, 5, 6] let result = setA.intersection(setB) print(result.sorted())
medium
A. [3, 4]
B. [1, 2]
C. [5, 6]
D. [1, 2, 3, 4, 5, 6]
Solution
Step 1: Understand intersection operation
Intersection returns elements common to both sets. Here, common elements are 3 and 4.
Step 2: Check printed output
Result is converted to a sorted array, so output is [3, 4].
Final Answer:
[3, 4] -> Option A
Quick Check:
Intersection = common elements [OK]
Hint: Intersection = only items in both sets [OK]
Common Mistakes:
Confusing intersection with union
Forgetting to sort before printing
Expecting all elements combined
4. Identify the error in this Swift code snippet:
var fruits: Set<String> = ["apple", "banana", "orange"] fruits.append("grape")
medium
A. The brackets [] cannot be used to create a Set.
B. You cannot add strings to a Set of strings.
C. The Set must be declared as a constant, not variable.
D. Sets do not have an append method.
Solution
Step 1: Check Set modification methods
Sets use insert() to add elements, not append().
Step 2: Analyze the code error
Calling append() on a Set causes a compile error because it is not defined for Set.
Final Answer:
Sets do not have an append method. -> Option D
Quick Check:
Use insert() to add to Set [OK]
Hint: Use insert(), not append(), to add Set items [OK]
Common Mistakes:
Using append() instead of insert()
Thinking Sets are immutable by default
Confusing array and Set methods
5. Given two sets:
let setX: Set<Int> = [1, 2, 3, 4, 5] let setY: Set<Int> = [4, 5, 6, 7]
Which Swift code correctly creates a new set containing elements in either setX or setY but not in both?
hard
A. let result = setX.symmetricDifference(setY)
B. let result = setX.union(setY)
C. let result = setX.intersection(setY)
D. let result = setX.subtracting(setY)
Solution
Step 1: Understand symmetricDifference
Symmetric difference returns elements in either set but not in both.
Step 2: Compare with other operations
Union combines all elements, intersection finds common, subtracting removes elements of second from first.
Final Answer:
let result = setX.symmetricDifference(setY) -> Option A
Quick Check:
Symmetric difference = exclusive elements [OK]
Hint: SymmetricDifference = items in one set only [OK]
Common Mistakes:
Using union instead of symmetricDifference
Confusing intersection with symmetricDifference
Using subtracting which is one-sided
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