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Swiftprogramming~10 mins

Set creation and operations in Swift - Step-by-Step Execution

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Concept Flow - Set creation and operations
Start
Create Set
Add Elements
Perform Operations
Union
Use Results
End
Start by creating a set, add elements, then perform operations like union, intersection, and difference to get new sets.
Execution Sample
Swift
var setA: Set<Int> = [1, 2, 3]
let setB: Set<Int> = [3, 4, 5]

let unionSet = setA.union(setB)
let intersectSet = setA.intersection(setB)
let diffSet = setA.subtracting(setB)
This code creates two sets and finds their union, intersection, and difference.
Execution Table
StepActionSetASetBResult VariableResult Value
1Create setA[1, 2, 3][]
2Create setB[1, 2, 3][3, 4, 5]
3Union setA ∪ setB[1, 2, 3][3, 4, 5]unionSet[1, 2, 3, 4, 5]
4Intersection setA ∩ setB[1, 2, 3][3, 4, 5]intersectSet[3]
5Difference setA - setB[1, 2, 3][3, 4, 5]diffSet[1, 2]
6End of operations[1, 2, 3][3, 4, 5]
💡 All set operations completed; no more steps.
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 3After Step 4After Step 5Final
setAempty[1, 2, 3][1, 2, 3][1, 2, 3][1, 2, 3][1, 2, 3][1, 2, 3]
setBemptyempty[3, 4, 5][3, 4, 5][3, 4, 5][3, 4, 5][3, 4, 5]
unionSetundefinedundefinedundefined[1, 2, 3, 4, 5][1, 2, 3, 4, 5][1, 2, 3, 4, 5][1, 2, 3, 4, 5]
intersectSetundefinedundefinedundefinedundefined[3][3][3]
diffSetundefinedundefinedundefinedundefinedundefined[1, 2][1, 2]
Key Moments - 3 Insights
Why does the unionSet contain all elements from both sets without duplicates?
Because sets automatically store unique elements, the union combines all elements but keeps only one copy of duplicates, as shown in step 3 of the execution_table.
Why is the intersectionSet only [3]?
Intersection finds elements common to both sets. Only '3' is in both setA and setB, as shown in step 4 of the execution_table.
Why does diffSet contain [1, 2] and not 3?
Difference removes elements in setB from setA. Since '3' is in setB, it is removed from setA, leaving [1, 2], as shown in step 5.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution_table at step 3, what elements does unionSet contain?
A[1, 2]
B[1, 2, 3, 4, 5]
C[3]
D[4, 5]
💡 Hint
Check the 'Result Value' column at step 3 in execution_table.
At which step does intersectSet get its value assigned?
AStep 4
BStep 2
CStep 5
DStep 1
💡 Hint
Look at the 'Result Variable' column for 'intersectSet' in execution_table.
If setB was empty, what would diffSet contain after step 5?
A[]
B[3, 4, 5]
C[1, 2, 3]
D[1, 2]
💡 Hint
Difference removes elements of setB from setA; if setB is empty, nothing is removed.
Concept Snapshot
Set creation: var setA: Set<Int> = [elements]
Operations:
- union: combines unique elements
- intersection: common elements
- difference: elements in first set not in second
Sets hold unique values only.
Full Transcript
This visual trace shows how to create sets in Swift and perform basic operations. First, setA and setB are created with initial elements. Then unionSet is created by combining all unique elements from both sets. intersectSet contains only elements common to both sets. diffSet contains elements in setA that are not in setB. Each step updates or uses these sets, showing how Swift sets work with unique elements and operations.