How can you use enumerated() to find the first element in an array nums that is greater than 10 and print its index?

hard📝 Application Q9 of 15

Swift - Collections

How can you use enumerated() to find the first element in an array nums that is greater than 10 and print its index?

Anums.firstIndex(where: { $0 > 10 })

Bfor num in nums { if num > 10 { print(num) break } }

Cfor (index, num) in nums.enumerated() { if num > 10 { print(index) break } }

Dnums.enumerated().filter { $0.element > 10 }.first?.offset

Step-by-Step Solution

Solution:

Step 1: Understand enumerated() usage for index and element
Using enumerated() allows access to both index and element in the loop.
Step 2: Check which option finds first element > 10 and prints index
for (index, num) in nums.enumerated() { if num > 10 { print(index) break } } loops with enumerated(), checks condition, prints index, and breaks to stop at first match. for num in nums { if num > 10 { print(num) break } } prints element, not index. nums.enumerated().filter { $0.element > 10 }.first?.offset returns optional index but does not print. nums.firstIndex(where: { $0 > 10 }) uses a different method.
Final Answer:
for (index, num) in nums.enumerated() { if num > 10 { print(index) break } } -> Option C
Quick Check:
Loop with enumerated() and break on first match [OK]

Quick Trick: Use break after first match in enumerated() loop [OK]

Common Mistakes:

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