[Solved] Identify the error in this Swift code: let pi = 3.14 pi = 3.14159 print(pi) — Ans: Compile-time error: cannot assign to value: 'pi' is a 'let' constant | Swift

Swift - Variables and Constants

Identify the error in this Swift code:

let pi = 3.14
pi = 3.14159
print(pi)

ANo error, prints 3.14159

BCompile-time error: cannot assign to value: 'pi' is a 'let' constant

CRuntime error: variable not initialized

DSyntax error: missing semicolon

Step-by-Step Solution

Solution:

Step 1: Check reassignment of constant
The code tries to assign a new value to pi, which was declared with let and is immutable.
Step 2: Understand Swift's error
Swift does not allow changing a constant's value, so this causes a compile-time error.
Final Answer:
Compile-time error: cannot assign to value: 'pi' is a 'let' constant -> Option B
Quick Check:
Reassigning let constant causes compile error = D [OK]

Quick Trick: Constants cannot be changed after assignment [OK]

Common Mistakes:

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