Array iteration and enumerated in Swift - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print each element in the array.

Swift

let fruits = ["Apple", "Banana", "Cherry"]
for fruit in [1] {
    print(fruit)
}

Drag options to blanks, or click blank then click option'

Afruits

Bfruit

Carray

Ditems

Attempts:

3 left

💡 Hint

Common Mistakes

Using the loop variable name instead of the array name.

Using a variable name that is not declared.

The loop iterates over the array named fruits. So, fruits is the correct variable to use.

2fill in blank

medium

Complete the code to print the index and value of each element using enumerated().

Swift

let colors = ["Red", "Green", "Blue"]
for (index, color) in colors.[1]() {
    print("\(index): \(color)")
}

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Aenumerated

Benumerate

Cindexed

Ditems

Attempts:

3 left

💡 Hint

Common Mistakes

Using a method name that does not exist like 'enumerate' or 'indexed'.

Forgetting the parentheses after the method name.

The enumerated() method returns a sequence of pairs (index, element) for arrays.

3fill in blank

hard

Fix the error in the loop to correctly access index and value.

Swift

let numbers = [10, 20, 30]
for ([1], value) in numbers.enumerated() {
    print("Index: \([1]), Value: \(value)")
}

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Ai

Bvalue

Cnum

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names for the index in the loop and print statement.

Using the value variable name instead of index.

The variable index is used to hold the index from enumerated(). It must be consistent in the loop and print statement.

4fill in blank

hard

Fill both blanks to create a dictionary with words as keys and their lengths as values, filtering words longer than 4 letters.

Swift

let words = ["apple", "dog", "banana", "cat"]
let wordLengths = [[1]: [2] for word in words where word.count > 4]

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Aword

Bword.count

Cword.length

Dcount

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.length which is not valid in Swift.

Using a variable name not declared.

The dictionary comprehension uses word as the key and word.count as the value. The filter keeps words longer than 4 letters.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase words as keys, their lengths as values, filtering words with length greater than 3.

Swift

let words = ["sun", "moon", "star", "sky"]
let result = [[1]: [2] for word in words where [3]]

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Aword.uppercased()

Bword.count

Cword.count > 3

Dword.lowercased()

Attempts:

3 left

💡 Hint

Common Mistakes

Using word.lowercased() instead of uppercase.

Using incorrect filter condition.

The dictionary keys are uppercase words using word.uppercased(). Values are word lengths with word.count. The filter keeps words longer than 3 letters.