Swift - Loops
Given the task to print all pairs (i, j) where i and j range from 1 to 3, but stop all loops immediately when i + j equals 4, which Swift code correctly uses labeled statements to achieve this?
Given the task to print all pairs (i, j) where i and j range from 1 to 3, but stop all loops immediately when i + j equals 4, which Swift code correctly uses labeled statements to achieve this?
hard📝 Application Q15 of 15
Step-by-Step Solution
Solution:
Step 1: Understand the stopping condition
We want to stop all loops immediately when i + j == 4, so we must break the outer loop.Step 2: Use labeled break correctly
outerLoop: for i in 1...3 { for j in 1...3 { if i + j == 4 { break outerLoop } print("\(i),\(j)") } } uses 'break outerLoop' to stop the outer loop from inside the inner loop, which is correct.Step 3: Check other options
for i in 1...3 { for j in 1...3 { if i + j == 4 { break } print(i, j) } } breaks only inner loop; C uses continue which skips iterations but doesn't stop loops; D continues inner loop only.Final Answer:
Code that breaks outerLoop when i + j == 4 -> Option AQuick Check:
Labeled break stops all loops = A [OK]
Quick Trick: Use labeled break to stop outer loop from inner loop [OK]
Common Mistakes:
- Using break without label stops only inner loop
- Using continue instead of break
- Not labeling the outer loop
Master "Loops" in Swift
Want More Practice?
15+ quiz questions · All difficulty levels · Free
Free Signup - Practice All QuestionsMore Swift Quizzes