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SQLquery~5 mins

Querying through views in SQL - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a SQL view?
A SQL view is like a saved query. It looks like a table but does not store data itself. It shows data from one or more tables when you ask it.
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beginner
How do you query data from a view?
You use a SELECT statement just like with a normal table. For example: SELECT * FROM view_name;
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beginner
Can you filter data when querying a view?
Yes! You can add WHERE, ORDER BY, and other clauses to a query on a view to get only the data you want.
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beginner
Does a view store data permanently?
No, a view does not store data. It shows data from the underlying tables each time you query it.
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intermediate
Why use views instead of tables?
Views help simplify complex queries, hide details, and provide a consistent way to see data without copying it.
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What does a SQL view represent?
AA saved query that looks like a table
BA physical table storing data
CA backup of a database
DA user account in the database
How do you get data from a view named 'employee_view'?
ASELECT * FROM employee_view;
BGET employee_view;
CSHOW employee_view;
DOPEN employee_view;
Can you use WHERE clause when querying a view?
AOnly with special permissions
BNo, views do not support filtering
COnly if the view is indexed
DYes, just like with tables
Does a view store data permanently?
AOnly if created with special options
BYes, it stores a copy of data
CNo, it shows data from tables dynamically
DYes, but only for a short time
Which is a benefit of using views?
AIncrease storage space
BSimplify complex queries
CMake data permanent
DReplace tables completely
Explain what a SQL view is and how you can use it to get data.
Think of a view as a window to see data from tables.
You got /4 concepts.
    Describe why views are useful in databases.
    Consider how views help users see data easily without changing tables.
    You got /4 concepts.

      Practice

      (1/5)
      1. What is a view in SQL?
      SELECT * FROM view_name; works because a view is:
      easy
      A. A saved query that acts like a virtual table
      B. A physical table storing data permanently
      C. A type of index to speed up queries
      D. A backup copy of a database

      Solution

      1. Step 1: Understand what a view represents

        A view is not a physical table but a stored SQL query that behaves like a table.
      2. Step 2: Recognize how views are queried

        You can query a view just like a table because it returns the result of its saved query.
      3. Final Answer:

        A saved query that acts like a virtual table -> Option A
      4. Quick Check:

        View = saved query acting like table [OK]
      Hint: Remember: views are virtual tables, not physical data [OK]
      Common Mistakes:
      • Thinking views store data physically
      • Confusing views with indexes
      • Assuming views are backups
      2. Which of the following is the correct syntax to create a view named employee_view showing all columns from employees table?
      easy
      A. CREATE employee_view VIEW AS SELECT * FROM employees;
      B. CREATE VIEW employee_view FROM employees;
      C. VIEW CREATE employee_view AS SELECT * FROM employees;
      D. CREATE VIEW employee_view AS SELECT * FROM employees;

      Solution

      1. Step 1: Recall the standard syntax for creating a view

        The correct syntax is: CREATE VIEW view_name AS SELECT ...
      2. Step 2: Match the syntax with options

        CREATE VIEW employee_view AS SELECT * FROM employees; matches the correct syntax exactly.
      3. Final Answer:

        CREATE VIEW employee_view AS SELECT * FROM employees; -> Option D
      4. Quick Check:

        CREATE VIEW ... AS SELECT ... [OK]
      Hint: Use 'CREATE VIEW view_name AS SELECT ...' format [OK]
      Common Mistakes:
      • Swapping keywords CREATE and VIEW
      • Using FROM instead of AS
      • Incorrect keyword order
      3. Given a view high_salary defined as:
      CREATE VIEW high_salary AS SELECT name, salary FROM employees WHERE salary > 70000;

      What will this query return?
      SELECT * FROM high_salary WHERE salary > 80000;
      medium
      A. Syntax error because salary filter is repeated
      B. All employees with salary greater than 70000
      C. All employees with salary greater than 80000
      D. Empty result because salary > 70000 is overridden

      Solution

      1. Step 1: Understand the view definition

        The view returns employees with salary > 70000 only.
      2. Step 2: Apply the query filter on the view

        The query further filters those results to salary > 80000, so only employees with salary above 80000 are returned.
      3. Final Answer:

        All employees with salary greater than 80000 -> Option C
      4. Quick Check:

        View filters 70000+, query filters 80000+ [OK]
      Hint: Filters on views stack, narrowing results [OK]
      Common Mistakes:
      • Thinking the second filter overrides the first
      • Assuming syntax error due to repeated conditions
      • Believing the result will be empty
      4. You have this view:
      CREATE VIEW dept_count AS SELECT department, COUNT(*) AS emp_count FROM employees GROUP BY department;

      Which query will cause an error when run on this view?
      medium
      A. SELECT department FROM dept_count;
      B. SELECT department, salary FROM dept_count;
      C. SELECT emp_count FROM dept_count WHERE department = 'Sales';
      D. SELECT * FROM dept_count WHERE emp_count > 5;

      Solution

      1. Step 1: Identify columns in the view

        The view has columns: department and emp_count only.
      2. Step 2: Check each query's column usage

        SELECT department, salary FROM dept_count; tries to select 'salary' which does not exist in the view, causing an error.
      3. Final Answer:

        SELECT department, salary FROM dept_count; causes error -> Option B
      4. Quick Check:

        Querying non-existent column = error [OK]
      Hint: Select only columns defined in the view [OK]
      Common Mistakes:
      • Selecting columns not in the view
      • Assuming all original table columns exist in view
      • Ignoring GROUP BY effects on columns
      5. You want to create a view active_customers that shows customers with at least one order in the last 30 days.
      Given tables:
      customers(id, name)
      orders(id, customer_id, order_date)
      Which is the correct SQL to create this view?
      hard
      A. CREATE VIEW active_customers AS SELECT id, name FROM customers WHERE EXISTS (SELECT 1 FROM orders WHERE customer_id = customers.id AND order_date > CURRENT_DATE - INTERVAL '30 days');
      B. CREATE VIEW active_customers AS SELECT * FROM customers WHERE id IN (SELECT customer_id FROM orders WHERE order_date > CURRENT_DATE - 30);
      C. CREATE VIEW active_customers AS SELECT c.id, c.name FROM customers c LEFT JOIN orders o ON c.id = o.customer_id WHERE o.order_date > CURRENT_DATE - INTERVAL 30 DAY;
      D. CREATE VIEW active_customers AS SELECT c.id, c.name FROM customers c JOIN orders o ON c.id = o.customer_id WHERE o.order_date > CURRENT_DATE - INTERVAL '30 days';

      Solution

      1. Step 1: Understand the requirement

        The view must include customers with orders in last 30 days only.
      2. Step 2: Analyze each option's correctness

        CREATE VIEW active_customers AS SELECT id, name FROM customers WHERE EXISTS (SELECT 1 FROM orders WHERE customer_id = customers.id AND order_date > CURRENT_DATE - INTERVAL '30 days'); uses EXISTS with correct date interval syntax and correlates orders to customers properly. CREATE VIEW active_customers AS SELECT c.id, c.name FROM customers c JOIN orders o ON c.id = o.customer_id WHERE o.order_date > CURRENT_DATE - INTERVAL '30 days'; uses JOIN but may duplicate customers if multiple orders exist. CREATE VIEW active_customers AS SELECT * FROM customers WHERE id IN (SELECT customer_id FROM orders WHERE order_date > CURRENT_DATE - 30); has incorrect date subtraction syntax. CREATE VIEW active_customers AS SELECT c.id, c.name FROM customers c LEFT JOIN orders o ON c.id = o.customer_id WHERE o.order_date > CURRENT_DATE - INTERVAL 30 DAY; uses LEFT JOIN but filters on order_date, which can exclude customers without recent orders incorrectly.
      3. Final Answer:

        CREATE VIEW active_customers AS SELECT id, name FROM customers WHERE EXISTS (SELECT 1 FROM orders WHERE customer_id = customers.id AND order_date > CURRENT_DATE - INTERVAL '30 days'); -> Option A
      4. Quick Check:

        Use EXISTS with correct date interval for filtering [OK]
      Hint: Use EXISTS with correct date interval for filtering [OK]
      Common Mistakes:
      • Using incorrect date interval syntax
      • Using JOIN causing duplicate rows
      • Filtering on LEFT JOIN columns incorrectly