GROUP BY with ORDER BY in SQL

Introduction

We use GROUP BY to group similar data together and ORDER BY to sort the results. Combining them helps us see grouped data in a sorted way.

When you want to count how many times each category appears and see the counts sorted.

When you want to find the total sales per product and list products from highest to lowest sales.

When you want to group students by their class and order the classes alphabetically.

When you want to group employees by department and order departments by the number of employees.

Syntax

SQL

SELECT column1, aggregate_function(column2)
FROM table_name
GROUP BY column1
ORDER BY column1 [ASC|DESC];

GROUP BY groups rows that have the same values in specified columns.

ORDER BY sorts the final grouped results by one or more columns, ascending (ASC) or descending (DESC).

Examples

Groups products by category and counts them, then sorts categories alphabetically.

SQL

SELECT category, COUNT(*)
FROM products
GROUP BY category
ORDER BY category ASC;

Groups employees by department, sums their salaries, and sorts departments by total salary from highest to lowest.

SQL

SELECT department, SUM(salary)
FROM employees
GROUP BY department
ORDER BY SUM(salary) DESC;

Groups customers by city, calculates average age, and sorts cities by average age from youngest to oldest.

SQL

SELECT city, AVG(age)
FROM customers
GROUP BY city
ORDER BY AVG(age) ASC;

Sample Program

This creates a sales table, adds some sales data, then groups sales by product, sums quantities, and orders products by total quantity sold from highest to lowest.

SQL

CREATE TABLE sales (
  product VARCHAR(20),
  quantity INT
);

INSERT INTO sales (product, quantity) VALUES
('Apple', 10),
('Banana', 5),
('Apple', 15),
('Banana', 7),
('Cherry', 20);

SELECT product, SUM(quantity) AS total_quantity
FROM sales
GROUP BY product
ORDER BY total_quantity DESC;

Important Notes

You can order by any column in the SELECT list, including aggregated columns.

ORDER BY happens after GROUP BY, so it sorts the grouped results, not the original rows.

If you don't specify ASC or DESC, ORDER BY defaults to ascending order.

Summary

GROUP BY groups rows with the same values in specified columns.

ORDER BY sorts the grouped results by one or more columns.

Use GROUP BY with ORDER BY to see grouped data in a sorted and clear way.

Practice

1. What does the GROUP BY clause do in an SQL query?

easy

A. It deletes duplicate rows from the table.

B. It sorts the rows in ascending order.

C. It groups rows that have the same values in specified columns.

D. It limits the number of rows returned.

Solution

1. Step 1: Understand the purpose of GROUP BY

   The GROUP BY clause collects rows with the same values in specified columns into summary rows.

2. Step 2: Differentiate from other clauses

   ORDER BY sorts rows, DELETE removes rows, and LIMIT restricts output count, which are different from grouping.

3. Final Answer:

   It groups rows that have the same values in specified columns. -> Option C

4. Quick Check:

   GROUP BY = grouping rows [OK]

Hint: GROUP BY groups rows by column values, not sorting [OK]

Common Mistakes:

• Confusing GROUP BY with ORDER BY
• Thinking GROUP BY deletes duplicates
• Assuming GROUP BY limits rows

2. Which of the following SQL queries correctly groups sales by product and orders the result by total sales descending?

easy

A. SELECT product, SUM(amount) FROM sales GROUP BY product ORDER BY SUM(amount) DESC;

B. SELECT product, SUM(amount) FROM sales ORDER BY product GROUP BY SUM(amount) DESC;

C. SELECT product, SUM(amount) FROM sales GROUP BY product ORDER BY product DESC;

D. SELECT product, SUM(amount) FROM sales ORDER BY SUM(amount) GROUP BY product DESC;

Solution

1. Step 1: Check GROUP BY and ORDER BY order

   The correct syntax is GROUP BY first, then ORDER BY to sort grouped results.

2. Step 2: Verify ordering by aggregated column

   Ordering by SUM(amount) DESC sorts by total sales descending, matching the requirement.

3. Final Answer:

   SELECT product, SUM(amount) FROM sales GROUP BY product ORDER BY SUM(amount) DESC; -> Option A

4. Quick Check:

   GROUP BY then ORDER BY with aggregate [OK]

Hint: GROUP BY before ORDER BY; order by aggregate for totals [OK]

Common Mistakes:

• Swapping GROUP BY and ORDER BY order
• Ordering by non-aggregated columns incorrectly
• Using ORDER BY before GROUP BY

3. Given the table orders with columns customer_id and order_total, what will this query return?

SELECT customer_id, COUNT(*) AS order_count FROM orders GROUP BY customer_id ORDER BY order_count ASC;

medium

A. Syntax error due to incorrect ORDER BY usage.

B. List of customers with their order counts sorted from highest to lowest.

C. List of customers with total order amounts sorted ascending.

D. List of customers with their order counts sorted from lowest to highest.

Solution

1. Step 1: Understand the GROUP BY and COUNT

   The query groups rows by customer_id and counts orders per customer.

2. Step 2: Analyze ORDER BY order_count ASC

   Ordering by order_count ascending sorts customers from fewest to most orders.

3. Final Answer:

   List of customers with their order counts sorted from lowest to highest. -> Option D

4. Quick Check:

   ORDER BY ASC sorts ascending [OK]

Hint: ORDER BY ASC sorts from smallest to largest [OK]

Common Mistakes:

• Assuming ORDER BY ASC sorts descending
• Confusing COUNT with SUM
• Thinking query returns total order amounts

4. Identify the error in this SQL query:

SELECT department, COUNT(*) FROM employees ORDER BY COUNT(*) DESC GROUP BY department;

medium

A. GROUP BY must come before ORDER BY in the query.

B. COUNT(*) cannot be used in ORDER BY clause.

C. Missing alias for COUNT(*) causes syntax error.

D. ORDER BY cannot sort aggregated columns.

Solution

1. Step 1: Check SQL clause order

   GROUP BY must appear before ORDER BY in SQL syntax.

2. Step 2: Identify the error in clause sequence

   The query places ORDER BY before GROUP BY, causing syntax error.

3. Final Answer:

   GROUP BY must come before ORDER BY in the query. -> Option A

4. Quick Check:

   GROUP BY before ORDER BY [OK]

Hint: GROUP BY always before ORDER BY in SQL [OK]

Common Mistakes:

• Placing ORDER BY before GROUP BY
• Assuming COUNT(*) can't be in ORDER BY
• Forgetting clause order rules

5. You have a sales table with columns region, salesperson, and amount. You want to find the total sales per region, but only show regions with total sales above 1000, sorted by total sales descending. Which query achieves this?

hard

A. SELECT region, SUM(amount) FROM sales WHERE SUM(amount) > 1000 GROUP BY region ORDER BY SUM(amount) DESC;

B. SELECT region, SUM(amount) FROM sales GROUP BY region HAVING SUM(amount) > 1000 ORDER BY SUM(amount) DESC;

C. SELECT region, SUM(amount) FROM sales GROUP BY region ORDER BY SUM(amount) DESC HAVING SUM(amount) > 1000;

D. SELECT region, SUM(amount) FROM sales ORDER BY SUM(amount) DESC HAVING SUM(amount) > 1000 GROUP BY region;

Solution

1. Step 1: Use GROUP BY to group sales by region

   Grouping by region allows aggregation of sales per region.

2. Step 2: Filter groups with HAVING clause

   HAVING filters groups after aggregation; WHERE cannot filter on aggregates.

3. Step 3: Sort results with ORDER BY descending

   ORDER BY SUM(amount) DESC sorts regions by total sales from highest to lowest.

4. Final Answer:

   SELECT region, SUM(amount) FROM sales GROUP BY region HAVING SUM(amount) > 1000 ORDER BY SUM(amount) DESC; -> Option B

5. Quick Check:

   GROUP BY + HAVING + ORDER BY correct order [OK]

Hint: Use HAVING to filter grouped results, ORDER BY last [OK]

Common Mistakes:

• Using WHERE to filter aggregated results
• Placing HAVING after ORDER BY
• Incorrect clause order