Data providers pattern in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a simple data provider function that returns test data.

Selenium Python

def data_provider():
    return [1]

Drag options to blanks, or click blank then click option'

A[('user1', 'pass1'), ('user2', 'pass2')]

B{'user1': 'pass1', 'user2': 'pass2'}

C('user1', 'pass1', 'user2', 'pass2')

D['user1', 'pass1', 'user2', 'pass2']

Attempts:

3 left

💡 Hint

Common Mistakes

Returning a dictionary instead of a list of tuples.

Returning a flat list instead of tuples.

The data provider should return a list of tuples, each tuple representing a set of test data.

2fill in blank

medium

Complete the test function to use the data provider with pytest's parametrize decorator.

Selenium Python

@pytest.mark.parametrize('username, password', [1])
def test_login(username, password):
    assert username != '' and password != ''

Drag options to blanks, or click blank then click option'

Adata_provider()

Bdata_provider

Cdata_provider[]

Ddata_provider{}

Attempts:

3 left

💡 Hint

Common Mistakes

Calling the function with parentheses inside the decorator.

Using brackets or braces instead of parentheses.

The parametrize decorator expects the function name without parentheses to use it as a data provider.

3fill in blank

hard

Fix the error in the data provider function that causes a syntax error.

Selenium Python

def data_provider():
    return [
        ('user1', 'pass1'),
        ('user2', 'pass2')[1]
    ]

Drag options to blanks, or click blank then click option'

A,

B;

C.

D:

Attempts:

3 left

💡 Hint

Common Mistakes

Using semicolon or colon instead of comma.

Missing the separator entirely.

In Python lists, items are separated by commas. Missing a comma causes a syntax error.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps usernames to passwords from the data provider list.

Selenium Python

credentials = [1] for user, pwd in data_provider() if user [2] 'user1'

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A{user: pwd}

B{pwd: user}

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Swapping key and value in the dictionary.

Using '!=' instead of '==' in the condition.

The dictionary comprehension should map user to password, and filter where user equals 'user1'.

5fill in blank

hard

Fill all three blanks to create a test function that uses the data provider and asserts the password length is at least 5.

Selenium Python

@pytest.mark.parametrize('[1]', [2])
def test_password_length([3]):
    assert len(password) >= 5

Drag options to blanks, or click blank then click option'

A'username, password'

Bdata_provider()

Cusername, password

D'user, pass'

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong parameter names in the decorator string.

Not calling the data provider function.

Using quotes around function parameters.

The parametrize decorator needs the parameter names as a string, the data provider function call, and the test function parameters without quotes.