Handling pop-up windows in Selenium Python - Test Execution Trace

Test Overview

This test opens a web page, clicks a button that opens a pop-up window, switches to the pop-up, verifies its title, closes it, and returns to the main window.

Test Code - Selenium

Selenium Python

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import unittest

class TestPopupHandling(unittest.TestCase):
    def setUp(self):
        self.driver = webdriver.Chrome()
        self.driver.get('https://example.com/popup')

    def test_popup_window(self):
        driver = self.driver
        main_window = driver.current_window_handle

        # Click button that opens popup
        button = WebDriverWait(driver, 10).until(
            EC.element_to_be_clickable((By.ID, 'open-popup-btn'))
        )
        button.click()

        # Wait for new window
        WebDriverWait(driver, 10).until(
            lambda d: len(d.window_handles) > 1
        )

        # Switch to popup window
        for handle in driver.window_handles:
            if handle != main_window:
                driver.switch_to.window(handle)
                break

        # Verify popup title
        popup_title = driver.title
        self.assertEqual(popup_title, 'Popup Window')

        # Close popup
        driver.close()

        # Switch back to main window
        driver.switch_to.window(main_window)

        # Verify main window title
        main_title = driver.title
        self.assertEqual(main_title, 'Main Page')

    def tearDown(self):
        self.driver.quit()

if __name__ == '__main__':
    unittest.main()

Execution Trace - 9 Steps

Step	Action	System State	Assertion	Result
1	Test starts and opens browser	Browser opens and navigates to https://example.com/popup	—	PASS
2	Finds button with ID 'open-popup-btn' and clicks it	Main page displayed with button visible	—	PASS
3	Waits until a new window appears	Two windows open: main and popup	Check that number of window handles > 1	PASS
4	Switches to the popup window	Popup window is active	—	PASS
5	Checks popup window title equals 'Popup Window'	Popup window title is visible	Assert popup_title == 'Popup Window'	PASS
6	Closes popup window	Popup window closed, main window still open	—	PASS
7	Switches back to main window	Main window active	—	PASS
8	Checks main window title equals 'Main Page'	Main window title visible	Assert main_title == 'Main Page'	PASS
9	Test ends and browser closes	Browser closed	—	PASS

Failure Scenario

Failing Condition: Popup window does not open or has wrong title

Execution Trace Quiz - 3 Questions

What does the test do after clicking the popup button?

A Closes the main window immediately

B Refreshes the page

C Waits for a new window to open

D Switches to an iframe

Key Result

Always store the main window handle before opening a popup, so you can switch back to it after closing the popup window.

Practice

1. What is the correct way to switch to a browser alert pop-up in Selenium with Python?

easy

A. driver.switch_to.window('alert')

B. driver.switch_to.alert

C. driver.switch_to.frame('alert')

D. driver.switch_to.default_content()

Solution

1. Step 1: Understand alert handling in Selenium

   Alerts are special pop-ups that require switching to alert context using driver.switch_to.alert.

2. Step 2: Identify the correct method to switch

   Using driver.switch_to.alert accesses the alert object directly, allowing interaction.

3. Final Answer:

   driver.switch_to.alert -> Option B

4. Quick Check:

   Alert pop-up switch = driver.switch_to.alert [OK]

Hint: Use driver.switch_to.alert for alerts, not window or frame [OK]

Common Mistakes:

• Using switch_to.window for alerts
• Trying to switch to alert as a frame
• Not switching before interacting with alert

2. Which of the following is the correct syntax to switch to a new browser window by its handle in Selenium Python?

easy

A. driver.switch_to.alert(window_handle)

B. driver.switch_to.default_content(window_handle)

C. driver.switch_to.frame(window_handle)

D. driver.switch_to.window(window_handle)

Solution

1. Step 1: Recall method to switch windows

   To switch to a new browser window, use driver.switch_to.window() with the window handle.

2. Step 2: Confirm correct syntax

   The method requires the window handle string as an argument, so driver.switch_to.window(window_handle) is correct.

3. Final Answer:

   driver.switch_to.window(window_handle) -> Option D

4. Quick Check:

   Switch window syntax = driver.switch_to.window(handle) [OK]

Hint: Use switch_to.window(handle) to change browser tabs/windows [OK]

Common Mistakes:

• Using switch_to.alert for windows
• Passing window handle to switch_to.frame
• Omitting the window handle argument

3. Given the following code snippet, what will be printed?

driver.get('https://example.com')
main_window = driver.current_window_handle
# Assume clicking button opens a new window
button = driver.find_element('id', 'openWindow')
button.click()
all_windows = driver.window_handles
for handle in all_windows:
    if handle != main_window:
        driver.switch_to.window(handle)
        print(driver.title)
        driver.close()
        break

# Switch back to main window
driver.switch_to.window(main_window)
print(driver.title)

medium

A. Title of new window followed by title of main window

B. Only title of main window printed twice

C. Only title of new window printed

D. No output due to error

Solution

1. Step 1: Understand window switching and closing

   The code clicks a button that opens a new window, then switches to it, prints its title, closes it, and breaks the loop.

2. Step 2: Switch back and print main window title

   After closing the new window, the code switches back to the main window and prints its title.

3. Final Answer:

   Title of new window followed by title of main window -> Option A

4. Quick Check:

   Print new window title, then main window title [OK]

Hint: Switch to new window, print title, close, then switch back [OK]

Common Mistakes:

• Not switching back to main window before printing
• Trying to print after closing main window
• Assuming both titles print simultaneously

4. Identify the error in the following Selenium Python code for handling an alert pop-up:

alert = driver.switch_to.alert()
alert.accept()

medium

A. Incorrect use of parentheses after switch_to.alert

B. Missing import for Alert class

C. alert.accept() should be alert.dismiss()

D. No error, code is correct

Solution

1. Step 1: Check method usage for alert switching

   driver.switch_to.alert is a property, not a method, so it should not have parentheses.

2. Step 2: Correct the syntax

   Remove parentheses: use alert = driver.switch_to.alert to get the alert object.

3. Final Answer:

   Incorrect use of parentheses after switch_to.alert -> Option A

4. Quick Check:

   switch_to.alert is property, no () [OK]

Hint: Don't add () after switch_to.alert, it's a property [OK]

Common Mistakes:

• Adding parentheses after switch_to.alert
• Confusing accept() with dismiss()
• Not switching to alert before accepting

5. You have a test that opens multiple pop-up windows in sequence. Which approach correctly handles switching to each new window, closing it, and returning to the main window without errors?

hard

A. Store main window handle, loop through all handles, switch to each new window, close it, then switch back to main window after loop

B. Switch to each window and close it inside the loop, then switch back to main window after closing all windows

C. Switch to each new window, close it immediately, and switch back to main window inside the loop after each close

D. Close main window first, then switch to new windows one by one

Solution

1. Step 1: Save main window handle before opening pop-ups

   Store the main window handle to return to it later safely.

2. Step 2: Loop through all window handles, switch, close, and return

   For each new window, switch to it, close it, then switch back to main window inside the loop to avoid stale window errors.

3. Step 3: Avoid closing main window before others

   Closing the main window first causes errors; it should be closed last or not at all during pop-up handling.

4. Final Answer:

   Switch to each new window, close it immediately, and switch back to main window inside the loop after each close -> Option C

5. Quick Check:

   Switch-close-switch back per window to avoid errors [OK]

Hint: Switch-close-switch back inside loop for each pop-up [OK]

Common Mistakes:

• Closing main window before others
• Switching back only after closing all pop-ups
• Not storing main window handle before loop