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Selenium Pythontesting~10 mins

Handling pop-up windows in Selenium Python - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to switch to the pop-up alert window.

Selenium Python
alert = driver.switch_to.[1]()
Drag options to blanks, or click blank then click option'
Adefault_content
Bwindow
Cframe
Dalert
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'window' or 'frame' instead of 'alert' causes errors.
Forgetting that 'alert' is a property, not a method (no parentheses).
2fill in blank
medium

Complete the code to accept (click OK) on the alert pop-up.

Selenium Python
alert.[1]()
Drag options to blanks, or click blank then click option'
Adismiss
Bsend_keys
Caccept
Dclose
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'dismiss' cancels the alert instead of accepting.
Trying to use 'send_keys' on alerts that don't accept input.
3fill in blank
hard

Fix the error in switching back to the main window after handling a pop-up.

Selenium Python
driver.switch_to.[1]()
Drag options to blanks, or click blank then click option'
Aalert
Bdefault_content
Cwindow
Dparent_frame
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'alert' again keeps focus on the pop-up.
Using 'window' is not a valid method here.
4fill in blank
hard

Fill both blanks to switch to a new browser window and then close it.

Selenium Python
driver.switch_to.[1](driver.window_handles[1])
driver.[2]()
Drag options to blanks, or click blank then click option'
Awindow
Bclose
Calert
Dquit
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'alert' instead of 'window' for switching windows.
Using 'quit' closes the whole browser, not just one window.
5fill in blank
hard

Fill all three blanks to handle a prompt pop-up by sending text, accepting it, and switching back to main window.

Selenium Python
alert = driver.switch_to.[1]()
alert.[2]('Hello')
alert.[3]()
Drag options to blanks, or click blank then click option'
Aalert
Bsend_keys
Caccept
Ddismiss
Attempts:
3 left
💡 Hint
Common Mistakes
Trying to send keys before switching to alert.
Using 'dismiss' instead of 'accept' cancels the prompt.

Practice

(1/5)
1. What is the correct way to switch to a browser alert pop-up in Selenium with Python?
easy
A. driver.switch_to.window('alert')
B. driver.switch_to.alert
C. driver.switch_to.frame('alert')
D. driver.switch_to.default_content()

Solution

  1. Step 1: Understand alert handling in Selenium

    Alerts are special pop-ups that require switching to alert context using driver.switch_to.alert.
  2. Step 2: Identify the correct method to switch

    Using driver.switch_to.alert accesses the alert object directly, allowing interaction.
  3. Final Answer:

    driver.switch_to.alert -> Option B
  4. Quick Check:

    Alert pop-up switch = driver.switch_to.alert [OK]
Hint: Use driver.switch_to.alert for alerts, not window or frame [OK]
Common Mistakes:
  • Using switch_to.window for alerts
  • Trying to switch to alert as a frame
  • Not switching before interacting with alert
2. Which of the following is the correct syntax to switch to a new browser window by its handle in Selenium Python?
easy
A. driver.switch_to.alert(window_handle)
B. driver.switch_to.default_content(window_handle)
C. driver.switch_to.frame(window_handle)
D. driver.switch_to.window(window_handle)

Solution

  1. Step 1: Recall method to switch windows

    To switch to a new browser window, use driver.switch_to.window() with the window handle.
  2. Step 2: Confirm correct syntax

    The method requires the window handle string as an argument, so driver.switch_to.window(window_handle) is correct.
  3. Final Answer:

    driver.switch_to.window(window_handle) -> Option D
  4. Quick Check:

    Switch window syntax = driver.switch_to.window(handle) [OK]
Hint: Use switch_to.window(handle) to change browser tabs/windows [OK]
Common Mistakes:
  • Using switch_to.alert for windows
  • Passing window handle to switch_to.frame
  • Omitting the window handle argument
3. Given the following code snippet, what will be printed?
driver.get('https://example.com')
main_window = driver.current_window_handle
# Assume clicking button opens a new window
button = driver.find_element('id', 'openWindow')
button.click()
all_windows = driver.window_handles
for handle in all_windows:
    if handle != main_window:
        driver.switch_to.window(handle)
        print(driver.title)
        driver.close()
        break

# Switch back to main window
driver.switch_to.window(main_window)
print(driver.title)
medium
A. Title of new window followed by title of main window
B. Only title of main window printed twice
C. Only title of new window printed
D. No output due to error

Solution

  1. Step 1: Understand window switching and closing

    The code clicks a button that opens a new window, then switches to it, prints its title, closes it, and breaks the loop.
  2. Step 2: Switch back and print main window title

    After closing the new window, the code switches back to the main window and prints its title.
  3. Final Answer:

    Title of new window followed by title of main window -> Option A
  4. Quick Check:

    Print new window title, then main window title [OK]
Hint: Switch to new window, print title, close, then switch back [OK]
Common Mistakes:
  • Not switching back to main window before printing
  • Trying to print after closing main window
  • Assuming both titles print simultaneously
4. Identify the error in the following Selenium Python code for handling an alert pop-up:
alert = driver.switch_to.alert()
alert.accept()
medium
A. Incorrect use of parentheses after switch_to.alert
B. Missing import for Alert class
C. alert.accept() should be alert.dismiss()
D. No error, code is correct

Solution

  1. Step 1: Check method usage for alert switching

    driver.switch_to.alert is a property, not a method, so it should not have parentheses.
  2. Step 2: Correct the syntax

    Remove parentheses: use alert = driver.switch_to.alert to get the alert object.
  3. Final Answer:

    Incorrect use of parentheses after switch_to.alert -> Option A
  4. Quick Check:

    switch_to.alert is property, no () [OK]
Hint: Don't add () after switch_to.alert, it's a property [OK]
Common Mistakes:
  • Adding parentheses after switch_to.alert
  • Confusing accept() with dismiss()
  • Not switching to alert before accepting
5. You have a test that opens multiple pop-up windows in sequence. Which approach correctly handles switching to each new window, closing it, and returning to the main window without errors?
hard
A. Store main window handle, loop through all handles, switch to each new window, close it, then switch back to main window after loop
B. Switch to each window and close it inside the loop, then switch back to main window after closing all windows
C. Switch to each new window, close it immediately, and switch back to main window inside the loop after each close
D. Close main window first, then switch to new windows one by one

Solution

  1. Step 1: Save main window handle before opening pop-ups

    Store the main window handle to return to it later safely.
  2. Step 2: Loop through all window handles, switch, close, and return

    For each new window, switch to it, close it, then switch back to main window inside the loop to avoid stale window errors.
  3. Step 3: Avoid closing main window before others

    Closing the main window first causes errors; it should be closed last or not at all during pop-up handling.
  4. Final Answer:

    Switch to each new window, close it immediately, and switch back to main window inside the loop after each close -> Option C
  5. Quick Check:

    Switch-close-switch back per window to avoid errors [OK]
Hint: Switch-close-switch back inside loop for each pop-up [OK]
Common Mistakes:
  • Closing main window before others
  • Switching back only after closing all pop-ups
  • Not storing main window handle before loop
Recommended

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10 questions~5 mineasy hard