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Selenium Javatesting~5 mins

Window handles (getWindowHandles) in Selenium Java - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a window handle in Selenium WebDriver?
A window handle is a unique identifier that Selenium uses to keep track of different browser windows or tabs opened during a test session.
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beginner
What does the method getWindowHandles() return in Selenium?
The getWindowHandles() method returns a Set of strings, each representing the unique window handle of every open browser window or tab.
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intermediate
How do you switch control to a new browser window using window handles?
You get all window handles using getWindowHandles(), then iterate through them and switch to the desired window using driver.switchTo().window(handle).
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intermediate
Why is it important to store the original window handle before opening a new window?
Storing the original window handle lets you switch back to the main window after interacting with new windows or tabs, ensuring your test continues correctly.
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beginner
What data structure does getWindowHandles() return and why is it useful?
It returns a Set<String> which ensures all window handles are unique and allows easy iteration to find and switch between windows.
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What does getWindowHandles() return in Selenium WebDriver?
AA Set of all open window handles
BThe handle of the current window only
CA list of all browser tabs titles
DThe URL of the current window
How do you switch to a new window after opening it?
Adriver.getWindowHandle(newWindowHandle)
Bdriver.switchTo().window(newWindowHandle)
Cdriver.openWindow(newWindowHandle)
Ddriver.switchTo().frame(newWindowHandle)
Why should you save the original window handle before opening a new window?
ATo switch back to it after working with new windows
BTo close the original window later
CTo refresh the original window
DTo maximize the original window
Which data structure does getWindowHandles() return?
AArray<String>
BList<String>
CMap<String, String>
DSet<String>
If you want to close a popup window and return to the main window, what is the correct sequence?
ASwitch to popup, close main window
BSwitch to main window, close popup
CClose popup, switch to main window handle
DClose main window, switch to popup
Explain how to handle multiple browser windows in Selenium using getWindowHandles().
Think about how Selenium identifies and switches between tabs or windows.
You got /4 concepts.
    Describe a scenario where you would need to use getWindowHandles() and how you would implement it in a test.
    Consider testing a link that opens a popup or new tab.
    You got /5 concepts.

      Practice

      (1/5)
      1. What does the Selenium method getWindowHandles() return when called?
      easy
      A. A set of all open window handles (IDs) in the current WebDriver session
      B. The handle of the current active window only
      C. The title of the current browser window
      D. The URL of the current page

      Solution

      1. Step 1: Understand the purpose of getWindowHandles()

        This method is designed to return all window handles for every open window or tab in the current browser session.
      2. Step 2: Identify the return type

        The method returns a Set of Strings, each representing a unique window handle (ID).
      3. Final Answer:

        A set of all open window handles (IDs) in the current WebDriver session -> Option A
      4. Quick Check:

        getWindowHandles() = all window IDs [OK]
      Hint: Remember: getWindowHandles() returns all window IDs as a set [OK]
      Common Mistakes:
      • Confusing getWindowHandles() with getWindowHandle() which returns one handle
      • Expecting a list or array instead of a set
      • Thinking it returns page titles or URLs
      2. Which of the following is the correct syntax to get all window handles in Selenium Java?
      easy
      A. List<String> handles = driver.getWindowHandles();
      B. String handles = driver.getWindowHandles();
      C. Set<String> handles = driver.getWindowHandles();
      D. Set handles = driver.getWindowHandle();

      Solution

      1. Step 1: Check the return type of getWindowHandles()

        The method returns a Set of Strings, so the variable must be declared as Set<String>.
      2. Step 2: Verify method name and syntax

        The correct method is getWindowHandles() (plural), and it belongs to the WebDriver instance named driver.
      3. Final Answer:

        Set<String> handles = driver.getWindowHandles(); -> Option C
      4. Quick Check:

        Correct syntax uses Set<String> and getWindowHandles() [OK]
      Hint: Use Set<String> for getWindowHandles() return type [OK]
      Common Mistakes:
      • Using List instead of Set for window handles
      • Calling getWindowHandle() instead of getWindowHandles()
      • Assigning to a String instead of a collection
      3. Consider the following code snippet:
      Set<String> handles = driver.getWindowHandles();
      System.out.println(handles.size());

      If the browser has 3 tabs open, what will be printed?
      medium
      A. An exception is thrown
      B. 1
      C. 0
      D. 3

      Solution

      1. Step 1: Understand what getWindowHandles() returns

        It returns a set containing all window handles for every open tab or window.
      2. Step 2: Determine the size of the set

        Since there are 3 tabs open, the set will contain 3 unique handles, so size() returns 3.
      3. Final Answer:

        3 -> Option D
      4. Quick Check:

        Number of tabs = size of handles set = 3 [OK]
      Hint: Size of getWindowHandles() set equals number of open tabs/windows [OK]
      Common Mistakes:
      • Assuming size() returns 1 for current window only
      • Expecting an exception if multiple tabs exist
      • Confusing getWindowHandles() with getWindowHandle()
      4. You wrote this code to switch to a new window:
      Set<String> handles = driver.getWindowHandles();
      String newWindow = handles.iterator().next();
      driver.switchTo().window(newWindow);

      But it always switches to the original window. What is the likely problem?
      medium
      A. getWindowHandles() returns an empty set
      B. Using iterator().next() returns the first handle, which is the original window
      C. switchTo().window() requires window title, not handle
      D. You must convert the set to a list before switching

      Solution

      1. Step 1: Analyze iterator().next() behavior on a Set

        Calling iterator().next() on a Set returns the first element, which is usually the original window handle.
      2. Step 2: Understand why it switches to original window

        Since newWindow is assigned the original window handle, switching to it does not change the window.
      3. Final Answer:

        Using iterator().next() returns the first handle, which is the original window -> Option B
      4. Quick Check:

        iterator().next() = first handle (original window) [OK]
      Hint: iterator().next() returns first handle, often original window [OK]
      Common Mistakes:
      • Assuming iterator().next() gives the new window handle
      • Thinking switchTo().window() needs window title
      • Not checking if getWindowHandles() is empty
      5. You want to switch to a newly opened window different from the original one. Given String originalHandle = driver.getWindowHandle(); and Set<String> allHandles = driver.getWindowHandles();, which code correctly switches to the new window?
      hard
      A. for (String handle : allHandles) { if (!handle.equals(originalHandle)) { driver.switchTo().window(handle); break; } }
      B. driver.switchTo().window(allHandles.iterator().next());
      C. driver.switchTo().window(originalHandle);
      D. driver.switchTo().window(allHandles.toArray()[0].toString());

      Solution

      1. Step 1: Identify the original window handle

        We have the original window handle stored in originalHandle.
      2. Step 2: Loop through all handles to find the new one

        Iterate over all handles and switch to the one that is not equal to the original handle.
      3. Step 3: Switch to the new window

        Once found, call driver.switchTo().window(handle) and break the loop.
      4. Final Answer:

        for (String handle : allHandles) { if (!handle.equals(originalHandle)) { driver.switchTo().window(handle); break; } } -> Option A
      5. Quick Check:

        Switch to handle != originalHandle [OK]
      Hint: Loop handles, skip original, switch to new [OK]
      Common Mistakes:
      • Switching to first handle without checking if it's original
      • Using toArray()[0] which may be original window
      • Switching to originalHandle instead of new window
      Recommended

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      Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

      10 questions~5 mineasy hard