[Solved] You wrote this code to switch to a new window:Set handles = driver.getWindowHandles(); String newWindow = handles.iterator().next(); driver.switchTo().... | Selenium Java

Selenium Java - Handling Windows, Frames, and Alerts

You wrote this code to switch to a new window:

Set handles = driver.getWindowHandles();
String newWindow = handles.iterator().next();
driver.switchTo().window(newWindow);

But it always switches to the original window. What is the likely problem?

AgetWindowHandles() returns an empty set

BUsing iterator().next() returns the first handle, which is the original window

CswitchTo().window() requires window title, not handle

DYou must convert the set to a list before switching

Step-by-Step Solution

Solution:

Step 1: Analyze iterator().next() behavior on a Set
Calling iterator().next() on a Set returns the first element, which is usually the original window handle.
Step 2: Understand why it switches to original window
Since newWindow is assigned the original window handle, switching to it does not change the window.
Final Answer:
Using iterator().next() returns the first handle, which is the original window -> Option B
Quick Check:
iterator().next() = first handle (original window) [OK]

Quick Trick: iterator().next() returns first handle, often original window [OK]

Common Mistakes:

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You wrote this code to switch to a new window: