FluentWait with polling in Selenium Java - Test Execution Trace

Test Overview

This test uses FluentWait with polling to wait for a button to become clickable on a web page. It verifies that the button can be clicked successfully.

Test Code - Selenium

Selenium Java

import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.FluentWait;
import java.time.Duration;
import java.util.NoSuchElementException;

public class FluentWaitTest {
    public static void main(String[] args) {
        System.setProperty("webdriver.chrome.driver", "path/to/chromedriver");
        WebDriver driver = new ChromeDriver();
        try {
            driver.get("https://example.com/dynamic_button");

            FluentWait<WebDriver> wait = new FluentWait<>(driver)
                    .withTimeout(Duration.ofSeconds(15))
                    .pollingEvery(Duration.ofSeconds(2))
                    .ignoring(NoSuchElementException.class);

            WebElement button = wait.until(ExpectedConditions.elementToBeClickable(By.id("dynamicButton")));

            button.click();

            WebElement message = driver.findElement(By.id("message"));
            assert message.getText().equals("Button clicked!") : "Message text did not match expected value.";

            System.out.println("Test Passed: Button clicked and message verified.");
        } finally {
            driver.quit();
        }
    }
}

Execution Trace - 7 Steps

Step	Action	System State	Assertion	Result
1	Test starts and Chrome browser opens	Browser window is open and ready	—	PASS
2	Navigates to https://example.com/dynamic_button	Page with dynamic button is loaded	—	PASS
3	Creates FluentWait with 15 seconds timeout and 2 seconds polling interval, ignoring NoSuchElementException	Wait object configured	—	PASS
4	Waits until button with id 'dynamicButton' is clickable	Button becomes clickable after some delay	Button is clickable	PASS
5	Clicks the button	Button clicked, page updates message	—	PASS
6	Finds element with id 'message' and verifies its text equals 'Button clicked!'	Message displayed on page	Message text equals 'Button clicked!'	PASS
7	Test ends and browser closes	Browser closed	—	PASS

Failure Scenario

Failing Condition: Button does not become clickable within 15 seconds timeout

Execution Trace Quiz - 3 Questions

What does the FluentWait pollingEvery(Duration.ofSeconds(2)) do in this test?

A It clicks the button every 2 seconds

B It waits 2 seconds after the button is found

C It checks for the button every 2 seconds until timeout

D It ignores the button for 2 seconds

Key Result

Using FluentWait with polling allows tests to repeatedly check for a condition at intervals, handling dynamic page elements more reliably than fixed waits.

Practice

1. What is the main purpose of using FluentWait in Selenium Java?

easy

A. To throw an exception as soon as an element is not found

B. To wait for an element with a custom timeout and polling interval

C. To immediately find an element without waiting

D. To perform actions on elements without any wait

Solution

1. Step 1: Understand FluentWait functionality

   FluentWait allows waiting for a condition with a custom timeout and polling frequency.

2. Step 2: Compare options with FluentWait purpose

   Only To wait for an element with a custom timeout and polling interval describes waiting with custom timeout and polling, which matches FluentWait's use.

3. Final Answer:

   To wait for an element with a custom timeout and polling interval -> Option B

4. Quick Check:

   FluentWait = custom wait with polling [OK]

Hint: FluentWait customizes wait time and checks repeatedly [OK]

Common Mistakes:

• Confusing FluentWait with immediate findElement
• Thinking FluentWait throws exception immediately
• Assuming FluentWait skips polling

2. Which of the following is the correct way to create a FluentWait object with polling every 500 milliseconds?

easy

A. new FluentWait(driver).pollingEvery(Duration.ofMillis(500))

B. new FluentWait(driver).pollingEvery(500, TimeUnit.MILLISECONDS)

C. new FluentWait(driver).pollingEvery(500)

D. new FluentWait(driver).pollingEvery(Duration.ofSeconds(500))

Solution

1. Step 1: Check correct Duration usage for pollingEvery

   pollingEvery expects a Duration object, so Duration.ofMillis(500) is correct for 500 ms.

2. Step 2: Analyze other options for syntax errors

   new FluentWait(driver).pollingEvery(Duration.ofSeconds(500)) uses seconds instead of milliseconds; B uses deprecated TimeUnit syntax; C uses int without Duration.

3. Final Answer:

   new FluentWait(driver).pollingEvery(Duration.ofMillis(500)) -> Option A

4. Quick Check:

   pollingEvery needs Duration.ofMillis for milliseconds [OK]

Hint: Use Duration.ofMillis for polling intervals in FluentWait [OK]

Common Mistakes:

• Using Duration.ofSeconds instead of ofMillis for milliseconds
• Passing int directly without Duration
• Using deprecated TimeUnit with pollingEvery

3. What will happen when the following FluentWait code runs if the element appears after 3 seconds?

Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(5))
  .pollingEvery(Duration.ofSeconds(1))
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("dynamicElement")));
System.out.println(element.getText());

medium

A. The code waits full 5 seconds then throws TimeoutException

B. The code throws NoSuchElementException immediately

C. The element is found and its text is printed after about 3 seconds

D. The code prints null because element is not found

Solution

1. Step 1: Understand FluentWait behavior with polling and timeout

   The wait polls every 1 second up to 5 seconds, ignoring NoSuchElementException until element appears.

2. Step 2: Analyze timing and result

   Since element appears after 3 seconds, wait finds it before timeout and prints its text.

3. Final Answer:

   The element is found and its text is printed after about 3 seconds -> Option C

4. Quick Check:

   FluentWait polls until element found or timeout [OK]

Hint: FluentWait polls repeatedly until element found or timeout [OK]

Common Mistakes:

• Expecting immediate exception on missing element
• Assuming wait always waits full timeout
• Thinking element text prints null if not found

4. Identify the error in this FluentWait code snippet:

Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(10))
  .pollingEvery(500)
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("test")));

medium

A. pollingEvery should use Duration, not int

B. withTimeout should be in milliseconds, not seconds

C. Ignoring NoSuchElementException is not allowed

D. FluentWait cannot be used with WebDriver

Solution

1. Step 1: Check pollingEvery parameter type

   pollingEvery expects a Duration object, but 500 (int) is passed, causing a compile error.

2. Step 2: Verify other method usages

   withTimeout(Duration.ofSeconds(10)) is correct; ignoring NoSuchElementException is valid; FluentWait works with WebDriver.

3. Final Answer:

   pollingEvery should use Duration, not int -> Option A

4. Quick Check:

   pollingEvery requires Duration parameter [OK]

Hint: pollingEvery needs Duration, not plain int [OK]

Common Mistakes:

• Passing int directly to pollingEvery
• Confusing withTimeout units
• Thinking ignoring exceptions is invalid

5. You want to wait up to 10 seconds for an element with id "submitBtn" to appear, checking every 2 seconds, and ignoring both NoSuchElementException and ElementNotVisibleException. Which FluentWait code snippet correctly implements this?

hard

A. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class)
.until(d -> d.findElement(By.id("submitBtn")));

B. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

C. new FluentWait<>(driver)
.withTimeout(10)
.pollingEvery(2)
.ignoring(NoSuchElementException.class)
.ignoring(ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

D. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class)
.ignoring(ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

Solution

1. Step 1: Check timeout and polling interval syntax

   withTimeout and pollingEvery correctly use Duration.ofSeconds(10) and Duration.ofSeconds(2) in new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));.

2. Step 2: Verify ignoring multiple exceptions

   new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); chains .ignoring() calls for each exception, which is valid. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class, ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); tries to pass two exceptions in one call, which is invalid.

3. Step 3: Confirm other options

   new FluentWait<>(driver) .withTimeout(10) .pollingEvery(2) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); uses int instead of Duration, causing errors. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .until(d -> d.findElement(By.id("submitBtn"))); ignores only one exception, missing ElementNotVisibleException.

4. Final Answer:

   new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); -> Option D

5. Quick Check:

   Chain ignoring() for multiple exceptions with Duration times [OK]

Hint: Chain ignoring() for each exception; use Duration for times [OK]

Common Mistakes:

• Passing multiple exceptions in one ignoring() call
• Using int instead of Duration for time values
• Ignoring only one exception when multiple needed