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Selenium Javatesting~15 mins

FluentWait with polling in Selenium Java - Build an Automation Script

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Wait for a dynamic element to be visible using FluentWait with polling
Preconditions (3)
Step 1: Navigate to the test page URL
Step 2: Click the button with id 'loadButton'
Step 3: Use FluentWait to wait for the element with id 'dynamicElement' to be visible
Step 4: Set polling interval to 500 milliseconds and timeout to 10 seconds
Step 5: Verify that the element with id 'dynamicElement' is displayed
✅ Expected Result: The dynamic element with id 'dynamicElement' becomes visible within 10 seconds after clicking 'loadButton'
Automation Requirements - Selenium WebDriver with Java
Assertions Needed:
Assert that the dynamic element is displayed after waiting
Best Practices:
Use FluentWait with polling interval and timeout
Use ExpectedConditions for visibility check
Avoid Thread.sleep; use explicit waits
Use By.id locator for element identification
Automated Solution
Selenium Java
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.FluentWait;
import org.openqa.selenium.support.ui.Wait;
import java.time.Duration;
import java.util.NoSuchElementException;

public class FluentWaitExample {
    public static void main(String[] args) {
        System.setProperty("webdriver.chrome.driver", "path/to/chromedriver");
        WebDriver driver = new ChromeDriver();
        try {
            driver.get("https://example.com/testpage");

            // Click the load button
            driver.findElement(By.id("loadButton")).click();

            // Create FluentWait instance
            Wait<WebDriver> wait = new FluentWait<>(driver)
                    .withTimeout(Duration.ofSeconds(10))
                    .pollingEvery(Duration.ofMillis(500))
                    .ignoring(NoSuchElementException.class);

            // Wait for the dynamic element to be visible
            WebElement dynamicElement = wait.until(ExpectedConditions.visibilityOfElementLocated(By.id("dynamicElement")));

            // Assertion: element is displayed
            if (dynamicElement.isDisplayed()) {
                System.out.println("Test Passed: Dynamic element is visible.");
            } else {
                System.out.println("Test Failed: Dynamic element is not visible.");
            }
        } finally {
            driver.quit();
        }
    }
}

This code starts by setting up the Chrome WebDriver and opening the test page.

It clicks the button with id loadButton to trigger loading the dynamic element.

Then, it creates a FluentWait object with a timeout of 10 seconds and polling every 500 milliseconds. It ignores NoSuchElementException during waiting.

The wait uses ExpectedConditions.visibilityOfElementLocated to wait until the dynamic element with id dynamicElement is visible.

Finally, it checks if the element is displayed and prints the test result.

The driver.quit() in finally ensures the browser closes even if an error occurs.

Common Mistakes - 3 Pitfalls
Using Thread.sleep instead of FluentWait
Not ignoring NoSuchElementException in FluentWait
Using hardcoded XPath instead of By.id
Bonus Challenge

Now add data-driven testing to click different buttons with ids 'loadButton1', 'loadButton2', 'loadButton3' and verify their respective dynamic elements appear.

Show Hint

Practice

(1/5)
1. What is the main purpose of using FluentWait in Selenium Java?
easy
A. To throw an exception as soon as an element is not found
B. To wait for an element with a custom timeout and polling interval
C. To immediately find an element without waiting
D. To perform actions on elements without any wait

Solution

  1. Step 1: Understand FluentWait functionality

    FluentWait allows waiting for a condition with a custom timeout and polling frequency.
  2. Step 2: Compare options with FluentWait purpose

    Only To wait for an element with a custom timeout and polling interval describes waiting with custom timeout and polling, which matches FluentWait's use.
  3. Final Answer:

    To wait for an element with a custom timeout and polling interval -> Option B
  4. Quick Check:

    FluentWait = custom wait with polling [OK]
Hint: FluentWait customizes wait time and checks repeatedly [OK]
Common Mistakes:
  • Confusing FluentWait with immediate findElement
  • Thinking FluentWait throws exception immediately
  • Assuming FluentWait skips polling
2. Which of the following is the correct way to create a FluentWait object with polling every 500 milliseconds?
easy
A. new FluentWait(driver).pollingEvery(Duration.ofMillis(500))
B. new FluentWait(driver).pollingEvery(500, TimeUnit.MILLISECONDS)
C. new FluentWait(driver).pollingEvery(500)
D. new FluentWait(driver).pollingEvery(Duration.ofSeconds(500))

Solution

  1. Step 1: Check correct Duration usage for pollingEvery

    pollingEvery expects a Duration object, so Duration.ofMillis(500) is correct for 500 ms.
  2. Step 2: Analyze other options for syntax errors

    new FluentWait(driver).pollingEvery(Duration.ofSeconds(500)) uses seconds instead of milliseconds; B uses deprecated TimeUnit syntax; C uses int without Duration.
  3. Final Answer:

    new FluentWait(driver).pollingEvery(Duration.ofMillis(500)) -> Option A
  4. Quick Check:

    pollingEvery needs Duration.ofMillis for milliseconds [OK]
Hint: Use Duration.ofMillis for polling intervals in FluentWait [OK]
Common Mistakes:
  • Using Duration.ofSeconds instead of ofMillis for milliseconds
  • Passing int directly without Duration
  • Using deprecated TimeUnit with pollingEvery
3. What will happen when the following FluentWait code runs if the element appears after 3 seconds?
Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(5))
  .pollingEvery(Duration.ofSeconds(1))
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("dynamicElement")));
System.out.println(element.getText());
medium
A. The code waits full 5 seconds then throws TimeoutException
B. The code throws NoSuchElementException immediately
C. The element is found and its text is printed after about 3 seconds
D. The code prints null because element is not found

Solution

  1. Step 1: Understand FluentWait behavior with polling and timeout

    The wait polls every 1 second up to 5 seconds, ignoring NoSuchElementException until element appears.
  2. Step 2: Analyze timing and result

    Since element appears after 3 seconds, wait finds it before timeout and prints its text.
  3. Final Answer:

    The element is found and its text is printed after about 3 seconds -> Option C
  4. Quick Check:

    FluentWait polls until element found or timeout [OK]
Hint: FluentWait polls repeatedly until element found or timeout [OK]
Common Mistakes:
  • Expecting immediate exception on missing element
  • Assuming wait always waits full timeout
  • Thinking element text prints null if not found
4. Identify the error in this FluentWait code snippet:
Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(10))
  .pollingEvery(500)
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("test")));
medium
A. pollingEvery should use Duration, not int
B. withTimeout should be in milliseconds, not seconds
C. Ignoring NoSuchElementException is not allowed
D. FluentWait cannot be used with WebDriver

Solution

  1. Step 1: Check pollingEvery parameter type

    pollingEvery expects a Duration object, but 500 (int) is passed, causing a compile error.
  2. Step 2: Verify other method usages

    withTimeout(Duration.ofSeconds(10)) is correct; ignoring NoSuchElementException is valid; FluentWait works with WebDriver.
  3. Final Answer:

    pollingEvery should use Duration, not int -> Option A
  4. Quick Check:

    pollingEvery requires Duration parameter [OK]
Hint: pollingEvery needs Duration, not plain int [OK]
Common Mistakes:
  • Passing int directly to pollingEvery
  • Confusing withTimeout units
  • Thinking ignoring exceptions is invalid
5. You want to wait up to 10 seconds for an element with id "submitBtn" to appear, checking every 2 seconds, and ignoring both NoSuchElementException and ElementNotVisibleException. Which FluentWait code snippet correctly implements this?
hard
A. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .until(d -> d.findElement(By.id("submitBtn")));
B. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));
C. new FluentWait<>(driver) .withTimeout(10) .pollingEvery(2) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));
D. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));

Solution

  1. Step 1: Check timeout and polling interval syntax

    withTimeout and pollingEvery correctly use Duration.ofSeconds(10) and Duration.ofSeconds(2) in new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));.
  2. Step 2: Verify ignoring multiple exceptions

    new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); chains .ignoring() calls for each exception, which is valid. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class, ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); tries to pass two exceptions in one call, which is invalid.
  3. Step 3: Confirm other options

    new FluentWait<>(driver) .withTimeout(10) .pollingEvery(2) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); uses int instead of Duration, causing errors. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .until(d -> d.findElement(By.id("submitBtn"))); ignores only one exception, missing ElementNotVisibleException.
  4. Final Answer:

    new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); -> Option D
  5. Quick Check:

    Chain ignoring() for multiple exceptions with Duration times [OK]
Hint: Chain ignoring() for each exception; use Duration for times [OK]
Common Mistakes:
  • Passing multiple exceptions in one ignoring() call
  • Using int instead of Duration for time values
  • Ignoring only one exception when multiple needed
Recommended

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10 questions~5 mineasy hard