FluentWait with polling in Selenium Java - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a FluentWait with a timeout of 30 seconds.

Selenium Java

FluentWait<WebDriver> wait = new FluentWait<>(driver).withTimeout(Duration.ofSeconds([1]));

Drag options to blanks, or click blank then click option'

A20

B10

C30

D60

Attempts:

3 left

💡 Hint

Common Mistakes

Using a timeout value too small causing premature timeout.

Forgetting to use Duration.ofSeconds.

The timeout is set to 30 seconds using Duration.ofSeconds(30).

2fill in blank

medium

Complete the code to set the polling interval to 5 seconds.

Selenium Java

wait.pollingEvery(Duration.ofSeconds([1]));

Drag options to blanks, or click blank then click option'

A1

B5

C10

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Setting polling interval longer than timeout.

Using wrong Duration method.

Polling interval is set to 5 seconds using Duration.ofSeconds(5).

3fill in blank

hard

Fix the error in the code to ignore NoSuchElementException during wait.

Selenium Java

wait.ignoring([1].class);

Drag options to blanks, or click blank then click option'

ANoSuchElementException

BElementNotVisibleException

CTimeoutException

DStaleElementReferenceException

Attempts:

3 left

💡 Hint

Common Mistakes

Ignoring wrong exception causing wait to fail early.

Forgetting to add .class after exception name.

Ignoring NoSuchElementException allows the wait to continue polling if element is not found yet.

4fill in blank

hard

Fill both blanks to create a FluentWait that waits 20 seconds and polls every 2 seconds.

Selenium Java

FluentWait<WebDriver> wait = new FluentWait<>(driver).withTimeout(Duration.ofSeconds([1])).pollingEvery(Duration.ofSeconds([2]));

Drag options to blanks, or click blank then click option'

A20

B5

C2

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Setting polling interval longer than timeout.

Swapping timeout and polling values.

Timeout is 20 seconds and polling interval is 2 seconds as required.

5fill in blank

hard

Fill all three blanks to create a FluentWait that waits 15 seconds, polls every 3 seconds, and ignores StaleElementReferenceException.

Selenium Java

FluentWait<WebDriver> wait = new FluentWait<>(driver).withTimeout(Duration.ofSeconds([1])).pollingEvery(Duration.ofSeconds([2])).ignoring([3].class);

Drag options to blanks, or click blank then click option'

ANoSuchElementException

B3

CStaleElementReferenceException

D15

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong exception to ignore.

Mixing up timeout and polling values.

Timeout is 15 seconds, polling every 3 seconds, ignoring StaleElementReferenceException as required.

Practice

1. What is the main purpose of using FluentWait in Selenium Java?

easy

A. To throw an exception as soon as an element is not found

B. To wait for an element with a custom timeout and polling interval

C. To immediately find an element without waiting

D. To perform actions on elements without any wait

Solution

1. Step 1: Understand FluentWait functionality

   FluentWait allows waiting for a condition with a custom timeout and polling frequency.

2. Step 2: Compare options with FluentWait purpose

   Only To wait for an element with a custom timeout and polling interval describes waiting with custom timeout and polling, which matches FluentWait's use.

3. Final Answer:

   To wait for an element with a custom timeout and polling interval -> Option B

4. Quick Check:

   FluentWait = custom wait with polling [OK]

Hint: FluentWait customizes wait time and checks repeatedly [OK]

Common Mistakes:

• Confusing FluentWait with immediate findElement
• Thinking FluentWait throws exception immediately
• Assuming FluentWait skips polling

2. Which of the following is the correct way to create a FluentWait object with polling every 500 milliseconds?

easy

A. new FluentWait(driver).pollingEvery(Duration.ofMillis(500))

B. new FluentWait(driver).pollingEvery(500, TimeUnit.MILLISECONDS)

C. new FluentWait(driver).pollingEvery(500)

D. new FluentWait(driver).pollingEvery(Duration.ofSeconds(500))

Solution

1. Step 1: Check correct Duration usage for pollingEvery

   pollingEvery expects a Duration object, so Duration.ofMillis(500) is correct for 500 ms.

2. Step 2: Analyze other options for syntax errors

   new FluentWait(driver).pollingEvery(Duration.ofSeconds(500)) uses seconds instead of milliseconds; B uses deprecated TimeUnit syntax; C uses int without Duration.

3. Final Answer:

   new FluentWait(driver).pollingEvery(Duration.ofMillis(500)) -> Option A

4. Quick Check:

   pollingEvery needs Duration.ofMillis for milliseconds [OK]

Hint: Use Duration.ofMillis for polling intervals in FluentWait [OK]

Common Mistakes:

• Using Duration.ofSeconds instead of ofMillis for milliseconds
• Passing int directly without Duration
• Using deprecated TimeUnit with pollingEvery

3. What will happen when the following FluentWait code runs if the element appears after 3 seconds?

Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(5))
  .pollingEvery(Duration.ofSeconds(1))
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("dynamicElement")));
System.out.println(element.getText());

medium

A. The code waits full 5 seconds then throws TimeoutException

B. The code throws NoSuchElementException immediately

C. The element is found and its text is printed after about 3 seconds

D. The code prints null because element is not found

Solution

1. Step 1: Understand FluentWait behavior with polling and timeout

   The wait polls every 1 second up to 5 seconds, ignoring NoSuchElementException until element appears.

2. Step 2: Analyze timing and result

   Since element appears after 3 seconds, wait finds it before timeout and prints its text.

3. Final Answer:

   The element is found and its text is printed after about 3 seconds -> Option C

4. Quick Check:

   FluentWait polls until element found or timeout [OK]

Hint: FluentWait polls repeatedly until element found or timeout [OK]

Common Mistakes:

• Expecting immediate exception on missing element
• Assuming wait always waits full timeout
• Thinking element text prints null if not found

4. Identify the error in this FluentWait code snippet:

Wait<WebDriver> wait = new FluentWait<>(driver)
  .withTimeout(Duration.ofSeconds(10))
  .pollingEvery(500)
  .ignoring(NoSuchElementException.class);

WebElement element = wait.until(d -> d.findElement(By.id("test")));

medium

A. pollingEvery should use Duration, not int

B. withTimeout should be in milliseconds, not seconds

C. Ignoring NoSuchElementException is not allowed

D. FluentWait cannot be used with WebDriver

Solution

1. Step 1: Check pollingEvery parameter type

   pollingEvery expects a Duration object, but 500 (int) is passed, causing a compile error.

2. Step 2: Verify other method usages

   withTimeout(Duration.ofSeconds(10)) is correct; ignoring NoSuchElementException is valid; FluentWait works with WebDriver.

3. Final Answer:

   pollingEvery should use Duration, not int -> Option A

4. Quick Check:

   pollingEvery requires Duration parameter [OK]

Hint: pollingEvery needs Duration, not plain int [OK]

Common Mistakes:

• Passing int directly to pollingEvery
• Confusing withTimeout units
• Thinking ignoring exceptions is invalid

5. You want to wait up to 10 seconds for an element with id "submitBtn" to appear, checking every 2 seconds, and ignoring both NoSuchElementException and ElementNotVisibleException. Which FluentWait code snippet correctly implements this?

hard

A. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class)
.until(d -> d.findElement(By.id("submitBtn")));

B. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

C. new FluentWait<>(driver)
.withTimeout(10)
.pollingEvery(2)
.ignoring(NoSuchElementException.class)
.ignoring(ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

D. new FluentWait<>(driver)
.withTimeout(Duration.ofSeconds(10))
.pollingEvery(Duration.ofSeconds(2))
.ignoring(NoSuchElementException.class)
.ignoring(ElementNotVisibleException.class)
.until(d -> d.findElement(By.id("submitBtn")));

Solution

1. Step 1: Check timeout and polling interval syntax

   withTimeout and pollingEvery correctly use Duration.ofSeconds(10) and Duration.ofSeconds(2) in new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn")));.

2. Step 2: Verify ignoring multiple exceptions

   new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); chains .ignoring() calls for each exception, which is valid. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class, ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); tries to pass two exceptions in one call, which is invalid.

3. Step 3: Confirm other options

   new FluentWait<>(driver) .withTimeout(10) .pollingEvery(2) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); uses int instead of Duration, causing errors. new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .until(d -> d.findElement(By.id("submitBtn"))); ignores only one exception, missing ElementNotVisibleException.

4. Final Answer:

   new FluentWait<>(driver) .withTimeout(Duration.ofSeconds(10)) .pollingEvery(Duration.ofSeconds(2)) .ignoring(NoSuchElementException.class) .ignoring(ElementNotVisibleException.class) .until(d -> d.findElement(By.id("submitBtn"))); -> Option D

5. Quick Check:

   Chain ignoring() for multiple exceptions with Duration times [OK]

Hint: Chain ignoring() for each exception; use Duration for times [OK]

Common Mistakes:

• Passing multiple exceptions in one ignoring() call
• Using int instead of Duration for time values
• Ignoring only one exception when multiple needed