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Rubyprogramming~20 mins

Type checking with .class and .is_a? in Ruby - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
Ruby Type Checking Master
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediate
1:30remaining
Output of .class vs .is_a? for Integer
What is the output of the following Ruby code?
Ruby
num = 42
puts num.class
puts num.is_a?(Integer)
A
Integer
true
B
Integer
false
C
Fixnum
true
D
Fixnum
false
Attempts:
2 left
💡 Hint
Remember Ruby 2.4+ unified Fixnum and Bignum into Integer.
❓ Predict Output
intermediate
1:30remaining
Checking class inheritance with .is_a?
What will this Ruby code print?
Ruby
class Animal; end
class Dog < Animal; end
pet = Dog.new
puts pet.class
puts pet.is_a?(Animal)
A
Dog
true
B
Animal
true
C
Dog
false
D
Animal
false
Attempts:
2 left
💡 Hint
Remember that .class returns the object's exact class, but .is_a? checks inheritance.
🔧 Debug
advanced
2:00remaining
Why does this .is_a? check fail?
Consider this Ruby code snippet. Why does the .is_a? check return false?
Ruby
class Vehicle; end
class Car < Vehicle; end
my_car = Vehicle.new
puts my_car.is_a?(Car)
ABecause Car is not defined properly as a subclass
BBecause .is_a? only works with modules, not classes
CBecause my_car is an instance of Vehicle, not Car or its subclass
DBecause .is_a? checks exact class equality, not inheritance
Attempts:
2 left
💡 Hint
Think about the object and class relationship and what .is_a? means.
📝 Syntax
advanced
1:30remaining
Identify the syntax error in type checking
Which option contains a syntax error when checking an object's type in Ruby?
Ruby
obj = 'hello'
Aobj.is_a?(String)
Bobj.is_a?(String))
Cobj.class == String
Dobj.class.eql?(String)
Attempts:
2 left
💡 Hint
Check for unmatched parentheses.
🚀 Application
expert
2:30remaining
Determine the output of complex type checks
What is the output of this Ruby code?
Ruby
module Mixin; end
class Parent; include Mixin; end
class Child < Parent; end
obj = Child.new
puts obj.is_a?(Mixin)
puts obj.class == Parent
puts obj.is_a?(Parent)
A
false
false
true
B
true
true
true
C
true
false
false
D
true
false
true
Attempts:
2 left
💡 Hint
Remember that .is_a? checks inheritance and included modules, but .class checks exact class.

Practice

(1/5)
1. What does the .class method return when called on an object in Ruby?
easy
A. Whether the object is a kind of a class
B. The exact type (class) of the object
C. The parent class of the object
D. A boolean indicating if the object is a class

Solution

  1. Step 1: Understand what .class does

    The .class method returns the exact class of the object it is called on.
  2. Step 2: Compare with other options

    Options A, C, and D describe behaviors of other methods or incorrect meanings.
  3. Final Answer:

    The exact type (class) of the object -> Option B
  4. Quick Check:

    .class returns exact type [OK]
Hint: Remember: .class gives exact type, not inheritance [OK]
Common Mistakes:
  • Confusing .class with .is_a?
  • Thinking .class returns boolean
  • Assuming .class returns parent class
2. Which of the following is the correct syntax to check if variable x is an instance of the Integer class using .is_a??
easy
A. x.is_a?(Integer)
B. x.is_a(Integer)
C. x.is_a<Integer>
D. x.is_a? Integer

Solution

  1. Step 1: Recall the syntax of .is_a?

    The method .is_a? requires a class argument inside parentheses, like .is_a?(ClassName).
  2. Step 2: Check each option

    x.is_a?(Integer) uses correct syntax with parentheses and question mark. Options A, B, and D have syntax errors or missing parentheses.
  3. Final Answer:

    x.is_a?(Integer) -> Option A
  4. Quick Check:

    Use parentheses with .is_a? [OK]
Hint: Always use parentheses with .is_a? method [OK]
Common Mistakes:
  • Omitting parentheses after .is_a?
  • Using angle brackets instead of parentheses
  • Leaving out the question mark
3. What will be the output of the following Ruby code?
class Animal; end
class Dog < Animal; end

dog = Dog.new
puts dog.class
puts dog.is_a?(Animal)
medium
A. Dog true
B. Animal true
C. Dog false
D. Animal false

Solution

  1. Step 1: Understand dog.class

    The dog object is an instance of Dog, so dog.class returns Dog.
  2. Step 2: Understand dog.is_a?(Animal)

    Since Dog inherits from Animal, dog.is_a?(Animal) returns true.
  3. Final Answer:

    Dog true -> Option A
  4. Quick Check:

    .class exact type, .is_a? checks inheritance [OK]
Hint: Remember: .class exact, .is_a? true for subclasses too [OK]
Common Mistakes:
  • Thinking .class returns parent class
  • Assuming .is_a? false for subclasses
  • Confusing output order
4. Identify the error in the following Ruby code snippet:
num = 10
if num.is_a?(Integer)
  puts "Number is integer"
else
  puts "Number is not integer"
end
medium
A. Syntax error in if statement
B. Missing parentheses in is_a? call
C. No error, code runs correctly
D. Incorrect class name Integer

Solution

  1. Step 1: Check is_a? usage

    The method .is_a? is correctly called with parentheses and the class Integer.
  2. Step 2: Verify syntax correctness

    The if statement and puts calls are syntactically correct.
  3. Final Answer:

    No error, code runs correctly -> Option C
  4. Quick Check:

    Correct syntax and usage means no error [OK]
Hint: Check parentheses and class names carefully [OK]
Common Mistakes:
  • Removing parentheses from is_a?
  • Using wrong class name like 'int'
  • Misplacing if-end keywords
5. Given the following code, which option correctly filters only strings from the mixed array using .is_a??
items = ["apple", 42, :symbol, "banana", 3.14]
strings = items.select { |item| ??? }
hard
A. item.class != String
B. item.class == String
C. item.is_a?(Integer)
D. item.is_a?(String)

Solution

  1. Step 1: Understand filtering with .is_a?

    We want to select only elements that are strings, so we check if each item is a kind of String.
  2. Step 2: Compare options

    item.is_a?(String) uses .is_a?(String) which returns true for strings. item.class == String uses .class == String which also works but is less flexible if subclasses exist. Options C and D filter integers or non-strings, which is incorrect.
  3. Final Answer:

    item.is_a?(String) -> Option D
  4. Quick Check:

    Use .is_a?(String) to filter strings [OK]
Hint: Use .is_a?(String) to include subclasses too [OK]
Common Mistakes:
  • Using .class == String and missing subclasses
  • Filtering wrong types by mistake
  • Forgetting question mark in .is_a?
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