Case with ranges and patterns in Ruby - Mini Project: Build & Apply

Case with ranges and patterns

📖 Scenario: You are creating a simple program to categorize ages into life stages using Ruby's case statement with ranges and pattern matching.

🎯 Goal: Build a Ruby program that uses a case statement with ranges and patterns to print the life stage for a given age.

📋 What You'll Learn

Create a variable age with a specific integer value.

Create a variable adult_age to set the minimum adult age.

Use a case statement with ranges and pattern matching to determine the life stage.

Print the life stage as output.

💡 Why This Matters

🌍 Real World

Categorizing ages into groups is common in apps like surveys, games, or health trackers.

💼 Career

Understanding <code>case</code> with ranges and patterns helps in writing clear, readable decision-making code in Ruby.

1

DATA SETUP: Create the age variable

Create a variable called age and set it to the integer 25.

Ruby

# Create a variable called age and set it to 25
# Your code here

Hint

Use = to assign the value 25 to the variable age.

2

CONFIGURATION: Create the adult_age variable

Create a variable called adult_age and set it to the integer 18.

Ruby

age = 25
# Create a variable called adult_age and set it to 18
# Your code here

Hint

Use = to assign the value 18 to the variable adult_age.

3

CORE LOGIC: Use case with ranges and pattern matching

Write a case statement using the variable age to match these ranges and patterns:
- When age is between 0 and 12 (inclusive), assign stage the string "Child".
- When age is between 13 and 17 (inclusive), assign stage the string "Teenager".
- When age is greater than or equal to adult_age, assign stage the string "Adult".
- Otherwise, assign stage the string "Unknown".

Ruby

age = 25
adult_age = 18
# Use a case statement with ranges and patterns to assign stage
# Your code here

Hint

Use case age and when with ranges like 0..12. Use Float::INFINITY for open-ended ranges.

4

OUTPUT: Print the life stage

Write a puts statement to print the value of the variable stage.

Ruby

age = 25
adult_age = 18

stage = case age
when 0..12
  "Child"
when 13..17
  "Teenager"
when adult_age..Float::INFINITY
  "Adult"
else
  "Unknown"
end

# Print the stage variable
# Your code here

Hint

Use puts stage to print the life stage.

Practice

1.

What does the in keyword do inside a case statement in Ruby when used with ranges?

easy

A. It checks if the value falls within the given range.

B. It assigns the range to the value.

C. It creates a new range object.

D. It compares the value for equality with the range.

Solution

1. Step 1: Understand the role of in in case

   The in keyword is used to match a value against a pattern or range inside a case statement.

2. Step 2: Check how it works with ranges

   When used with a range like 1..10, it checks if the value lies within that range.

3. Final Answer:

   It checks if the value falls within the given range. -> Option A

4. Quick Check:

   in with range means value in range [OK]

Hint: Remember: in checks membership in range or pattern [OK]

Common Mistakes:

• Thinking in assigns values instead of matching
• Confusing range equality with membership
• Assuming in creates new objects

2.

Which of the following is the correct syntax to match a number n in the range 5 to 15 inside a case statement using pattern matching?

case n
  in ???
    puts "In range"
  else
    puts "Out of range"
end

easy

A. in (5..15)

B. 5..15

C. 5...15

D. in 5..15

Solution

1. Step 1: Identify correct pattern syntax in in clause

   Inside case, in is followed directly by the pattern, so in 5..15 is correct syntax.

2. Step 2: Check other options for syntax errors

   Options without in or with extra parentheses are invalid syntax in this context.

3. Final Answer:

   in 5..15 -> Option D

4. Quick Check:

   Use in followed by the pattern without extra keywords or parentheses [OK]

Hint: Use in once, then the pattern without extra keywords [OK]

Common Mistakes:

• Writing in in 5..15 which is invalid
• Adding parentheses around the range
• Using three-dot range 5...15 which excludes 15

3.

What will be the output of this Ruby code?

score = 75
case score
in 0..49 then puts "Fail"
in 50..79 then puts "Pass"
in 80..100 then puts "Excellent"
else puts "Invalid"
end

medium

A. Pass

B. Fail

C. Excellent

D. Invalid

Solution

1. Step 1: Check which range includes 75

   75 is not in 0..49 but is in 50..79.

2. Step 2: Match the corresponding output

   The code prints "Pass" when score is in 50..79.

3. Final Answer:

   Pass -> Option A

4. Quick Check:

   75 in 50..79 means output "Pass" [OK]

Hint: Find which range includes the value, then pick that output [OK]

Common Mistakes:

• Choosing "Fail" because 75 is greater than 49
• Confusing inclusive and exclusive ranges
• Ignoring the order of case branches

4.

Identify the error in this Ruby code snippet using case with pattern matching:

value = 10
case value
in 1..5
  puts "Low"
in 6..10
  puts "Medium"
else
  puts "High"
end

medium

A. Missing then after in clauses

B. No error; code runs and prints "Medium"

C. Ranges should be written as arrays inside in

D. The case statement should use when instead of in

Solution

1. Step 1: Check syntax of case with in and ranges

   Using in with ranges inside case is valid Ruby syntax.

2. Step 2: Verify output for value 10

   10 matches the range 6..10, so it prints "Medium".

3. Final Answer:

   No error; code runs and prints "Medium" -> Option B

4. Quick Check:

   in with ranges works fine [OK]

Hint: Remember in works like when for pattern matching [OK]

Common Mistakes:

• Thinking then is mandatory after in
• Confusing in with when
• Trying to write ranges as arrays

5.

Given this Ruby code, what will be the output?

data = [3, 7, 12, 18]
case data
in [Integer, Integer, Integer, Integer]
  puts "All integers"
in [Integer, Integer, Integer, 18]
  puts "Last is 18"
else
  puts "No match"
end

hard

A. No match

B. Last is 18

C. All integers

D. SyntaxError

Solution

1. Step 1: Understand array pattern matching order

   The case checks patterns in order. The first pattern matches any array of four integers.

2. Step 2: Check if data matches first pattern

   Data is [3,7,12,18], all integers, so it matches the first pattern.

3. Step 3: Confirm second pattern is not reached

   Since first pattern matches, second is skipped.

4. Final Answer:

   All integers -> Option C

5. Quick Check:

   First matching pattern runs, so output is "All integers" [OK]

Hint: Patterns checked top-down; first match wins [OK]

Common Mistakes:

• Assuming second pattern runs despite first matching
• Confusing element types with values in patterns
• Expecting syntax error due to pattern complexity